Chapter 5, Problem 72A

Interpretation Introduction

Interpretation : The volume occupied by the liquid is to be calculated.

Concept Introduction :

The density is the mass per unit volume, which is given as,

  $\rho =\frac{m}{V}$

Where, $\rho$ is the density

  $V$ is the volume,

  $m$ is the mass

Answer to Problem 72A

The volume of the liquid is $\text{38}\text{.1mL}$ .

Explanation of Solution

Given information :

The density is, $\rho =1.31\raisebox{1ex}{$\text{g}$}\!\left/ \!\raisebox{-1ex}{$\text{mL}$}\right.$

The mass is, $m=50.\text{0 g}$

Formula used:

The density is defined as,

  $\rho =\frac{m}{V}$

Substitute the values of mass and density into the formula, then the result is,

  $\rho =\frac{m}{V}=\frac{\text{50}\text{.0g}}{\text{1}\text{.31}\raisebox{1ex}{$\text{g}$}\!\left/ \!\raisebox{-1ex}{$\text{mL}$}\right.}\text{=38}\text{.1mL}$

Conclusion

The volume is $38.1\text{mL}$ .