Chemistry: Matter and Change
Chemistry: Matter and Change
1st Edition
ISBN: 9780078746376
Author: Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher: Glencoe/McGraw-Hill School Pub Co
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Chapter 5, Problem 45A
Interpretation Introduction

(a)

Interpretation:

From the figure radiation type with a frequency of 8.6×1011s1 needs to be explained.

Chemistry: Matter and Change, Chapter 5, Problem 45A , additional homework tip  1

Concept introduction:

All types of electromagnetic radiation are included in electromagnetic spectrum. All types of radiation are different in their frequencies and wavelength values.

Expert Solution
Check Mark

Answer to Problem 45A

The type of radiation is infrared.

Explanation of Solution

From the given figure, it is clear that frequency of 8.6×1011s1 falls between the range of infrared. Hence, the radiation type is infrared.

Interpretation Introduction

(b)

Interpretation:

From the figure radiation type with wave length 4.2 nm needs to be explained.

Chemistry: Matter and Change, Chapter 5, Problem 45A , additional homework tip  2

Concept introduction:

All types of electromagnetic radiation are included in electromagnetic spectrum. All types of radiation are different in their frequencies and wavelength values.

Expert Solution
Check Mark

Answer to Problem 45A

The type of radiation is x-ray.

Explanation of Solution

The speed of an electromagnetic wave is expressed by below formula:

Speed=wavelength×frequencyfrequency=Speedwavelength …… (1)

Convert nanometer into meter as follows:

1nm=109m4.2nm=4.2nm×109m1nm=4.2×109m

The value of speed is 3×108m/s.

Substitute above values in equation (1).

frequency=Speedwavelength=3×108m/s4.2×109m=0.714×108+9s1=7.14×1016s1

Hence, frequency is 7.14×1016s1.

From the diagram the frequency value is in the range of x-rays.

Interpretation Introduction

(c)

Interpretation:

From the figure radiation type with a frequency of 5.6MHz needs to be explained.

Chemistry: Matter and Change, Chapter 5, Problem 45A , additional homework tip  3

Concept introduction:

All types of electromagnetic radiation are included in electromagnetic spectrum. All types of radiation are different in their frequencies and wavelength values.

Expert Solution
Check Mark

Answer to Problem 45A

The type of radiation is AM radio.

Explanation of Solution

Convert MHz into Hz as follows:

1MHz=106Hz5.6MHz=5.6MHz×106Hz1MHz=5.6×106Hz

5.6MHz is equivalent to 5.6×106Hz. From the given figure, it is clear that frequency of 5.6×106Hz falls between the range of radio.

Interpretation Introduction

(d)

Interpretation:

From the figure radiation that travels at a speed of 3.00×108m/s is needs to be explained.

Chemistry: Matter and Change, Chapter 5, Problem 45A , additional homework tip  4

Concept introduction:

All types of electromagnetic radiation are included in electromagnetic spectrum. All types of radiation are different in their frequencies and wavelength values.

Expert Solution
Check Mark

Answer to Problem 45A

All type of radiation passes through the speed 3.00×108m/s.

Explanation of Solution

The speed of all type of radiation is 3.00×108m/s. Hence, the radiation of any type has the speed of 3.00×108m/s.

Chapter 5 Solutions

Chemistry: Matter and Change

Ch. 5.1 - Prob. 11SSCCh. 5.1 - Prob. 12SSCCh. 5.1 - Prob. 13SSCCh. 5.1 - Prob. 14SSCCh. 5.2 - Prob. 15SSCCh. 5.2 - Prob. 16SSCCh. 5.2 - Prob. 17SSCCh. 5.2 - Prob. 18SSCCh. 5.2 - Prob. 19SSCCh. 5.2 - Prob. 20SSCCh. 5.3 - Prob. 21PPCh. 5.3 - Prob. 22PPCh. 5.3 - Prob. 23PPCh. 5.3 - Prob. 25PPCh. 5.3 - Prob. 26PPCh. 5.3 - Prob. 27PPCh. 5.3 - Prob. 28PPCh. 5.3 - Prob. 29SSCCh. 5.3 - Prob. 30SSCCh. 5.3 - Prob. 31SSCCh. 5.3 - Prob. 32SSCCh. 5.3 - Prob. 33SSCCh. 5 - Prob. 34ACh. 5 - Prob. 35ACh. 5 - Prob. 36ACh. 5 - Prob. 37ACh. 5 - Prob. 38ACh. 5 - Prob. 39ACh. 5 - Prob. 40ACh. 5 - Prob. 41ACh. 5 - Prob. 42ACh. 5 - Prob. 43ACh. 5 - Prob. 44ACh. 5 - Prob. 45ACh. 5 - Prob. 46ACh. 5 - Prob. 47ACh. 5 - Prob. 48ACh. 5 - Prob. 49ACh. 5 - Prob. 50ACh. 5 - Prob. 51ACh. 5 - Prob. 52ACh. 5 - Prob. 53ACh. 5 - Prob. 54ACh. 5 - Prob. 55ACh. 5 - Prob. 56ACh. 5 - Prob. 57ACh. 5 - Prob. 58ACh. 5 - According to the Bohr model, how do electrons...Ch. 5 - Prob. 60ACh. 5 - What is the difference between an atom’s ground...Ch. 5 - Prob. 62ACh. 5 - Prob. 63ACh. 5 - Prob. 64ACh. 5 - Prob. 65ACh. 5 - Prob. 66ACh. 5 - Prob. 67ACh. 5 - Prob. 68ACh. 5 - Prob. 69ACh. 5 - Prob. 70ACh. 5 - Prob. 71ACh. 5 - Prob. 72ACh. 5 - Prob. 73ACh. 5 - Prob. 74ACh. 5 - Prob. 75ACh. 5 - Prob. 76ACh. 5 - Prob. 77ACh. 5 - Prob. 78ACh. 5 - Prob. 79ACh. 5 - Prob. 80ACh. 5 - How many electrons are shown in each element’s...Ch. 5 - Prob. 82ACh. 5 - Prob. 83ACh. 5 - Prob. 84ACh. 5 - Prob. 85ACh. 5 - Prob. 86ACh. 5 - Prob. 87ACh. 5 - Prob. 88ACh. 5 - Prob. 89ACh. 5 - Prob. 90ACh. 5 - Prob. 91ACh. 5 - Prob. 92ACh. 5 - Prob. 93ACh. 5 - Prob. 94ACh. 5 - Prob. 95ACh. 5 - Prob. 96ACh. 5 - Prob. 97ACh. 5 - Prob. 98ACh. 5 - Prob. 99ACh. 5 - Prob. 100ACh. 5 - Prob. 101ACh. 5 - Prob. 102ACh. 5 - Prob. 103ACh. 5 - Prob. 104ACh. 5 - Prob. 105ACh. 5 - Prob. 106ACh. 5 - Prob. 107ACh. 5 - Prob. 108ACh. 5 - Prob. 109ACh. 5 - Prob. 110ACh. 5 - Prob. 111ACh. 5 - Prob. 112ACh. 5 - Prob. 113ACh. 5 - Prob. 114ACh. 5 - Prob. 115ACh. 5 - Prob. 116ACh. 5 - Prob. 117ACh. 5 - Prob. 118ACh. 5 - Prob. 119ACh. 5 - Prob. 1STPCh. 5 - Prob. 2STPCh. 5 - Prob. 3STPCh. 5 - Prob. 4STPCh. 5 - Prob. 5STPCh. 5 - Prob. 6STPCh. 5 - Prob. 7STPCh. 5 - Prob. 8STPCh. 5 - Prob. 9STPCh. 5 - Prob. 10STPCh. 5 - Prob. 11STPCh. 5 - Prob. 12STPCh. 5 - Prob. 13STPCh. 5 - Prob. 14STPCh. 5 - Prob. 15STPCh. 5 - Prob. 16STPCh. 5 - Prob. 17STPCh. 5 - Prob. 18STPCh. 5 - Prob. 19STP
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