Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN: 9781305632134
Author: J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher: Cengage Learning
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Chapter 5, Problem 5.2P
A 200-km, 230-kV, 60-Hz, three-phase line has a positive-sequence series impedance
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A 500 kV, 60 Hz uncompensated three-phase transmission line is 500 km long. The line has three ACSR 1113-kcmil (Finch) conductors per phase with parameters
Current carrying capability of single ACSR 1113-kcmil (Finch) conductor is 1,110 A. Calculate the theoretical maximum (steady state stability limit) real power that this line can deliver and compare with the thermal limit of the line. Assume VS = VR = 1.0 per unit and unity power factor at the receiving end.
A 230-kV, three-phase transmission line has a per phase series impedance of z = 0.05+j0.45 Ω per Km and a per phase shunt admittance of y = j3.410-6 siemens per km. The line is 80 km long. Using the nominal π model, determine(a) The transmission line ABCD constants. Find the sending end voltage andcurrent, voltage regulation, the sending end power and the transmissionefficiencywhen the line delivers(b) 200 MVA, 0.8 lagging power factor at 220 kV.(c) 306 MW, unity power factor at 220 kV.
A 69-kV, three phase short transmission line is 16km long. The line has a per phase series impedance of 0.125 + j0.4375 ohms per km. Determine the sending end voltage, voltage regulation, the sending end power, and the transmission efficiency when the line delivers:(a) 70 MVA, 0.8 lagging power factor at 64 kV.(b) 120 MW, unity power factor at 64kV.
Chapter 5 Solutions
Power System Analysis and Design (MindTap Course List)
Ch. 5 - Representing a transmission line by the two-port...Ch. 5 - The maximum power flow for a lossy line is...Ch. 5 - Prob. 5.21MCQCh. 5 - A 30-km, 34.5-kV, 60-Hz, three-phase line has a...Ch. 5 - A 200-km, 230-kV, 60-Hz, three-phase line has a...Ch. 5 - The 100-km, 230-kV, 60-Hz, three-phase line in...Ch. 5 - The 500-kV, 60-Hz, three-phase line in Problems...Ch. 5 - A 40-km, 220-kV, 60-Hz, three-phase overhead...Ch. 5 - A 500-km, 500-kV, 60-Hz, uncompensated three-phase...Ch. 5 - The 500-kV, 60-Hz, three-phase line in Problems...
Ch. 5 - A 350-km, 500-kV, 60-Hz, three-phase uncompensated...Ch. 5 - Rated line voltage is applied to the sending end...Ch. 5 - A 500-kV, 300-km, 6()-Hz, three-phase overhead...Ch. 5 - The following parameters are based on a...Ch. 5 - Consider a long radial line terminated in its...Ch. 5 - For a lossless open-circuited line, express the...Ch. 5 - A three-phase power of 460 MW is transmitted to a...Ch. 5 - Prob. 5.55PCh. 5 - Consider the transmission line of Problem 5.18....Ch. 5 - Given the uncompensated line of Problem 5.18, let...
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- Consider a long radial line terminated in its characteristic impedance Zc. Determine the following: (a) V1/I1, known as the driving point impedance. (b) | V2 |/V1|, known as the voltage gain, in terms of al. (c) | I2 |/| I1 |, known as the current gain, in terms of al. (d) The complex power gain, S21/S12, in terms of al. (e) The real power efficiency, (P21/P12)=, terms of al. Note: 1 refers to sending end and 2 refers to receiving end. (S21) is the complex power received at 2; S12 is sent from 1.arrow_forwardCalculate the capacitance-to-neutral in F/m and the admittance-to-neutral in S/km for the three-phase line in Problem 4.18. Also calculate the line-charging current in kA/phase if the line is 110 km in length and is operated at 230 kV. Neglect the effect of the earth plane.arrow_forwardA 3-phase overhead transmission line delivers a load of 80 MW at0.8 p.f. lagging and 220 kV between the lines. Its total seriesimpedance per phase and total shunt admittance per phase are 200ohms with an angle of 80 degrees and 0.0013 mho with an angle of90 degrees per phase respectively. Using nominal-T method,determine the following:(i) A, B, C, D constants of the line(ii) Sending end voltage(iii) Sending end current(iv) Sending end power factor(v) Transmission efficiency of the linearrow_forward
- A single phase overhead transmission line delivers 4000 kW at 11 kV at 0·8 p.f. lagging. If resistance and reactance per conductor are 0·15 Ω and 0·02 Ω respectively,Calculate:Percentage regulation sending end power factor Line lossesarrow_forwardA bundled 500kv, 60Hz three phase completely transposed overhead line having three ACSR 1113kcmil(556.50mm) conductors per bundle,with 0.5m between conductors in the bundle. The horizontal phase spacings between bundle centers are 10,10,and 20m.Calculate the capacitance -to- neutral in F/m. and the admittance -to-neutral in S/km.arrow_forwardIn three-phase short transmission line with end-of-line interphase voltage UR = 31,5kV , from the end of the line active power absorbed PR = 9000 kW, end of line power factor is cosφ = 0,70 (end) and the length of the line is l = 20km, The resistance of the line per km is R'= 0,125 Ohm/km, the reactance per km is X'= 0,375 Ohm/km.With the help of given information; a) Calculate the current drawn from the line (IR) as a phasor. b) Calculate the line-to-line-neutral voltage (VS) as a phasor, determine the effective line-to-line voltage (US) Calculate its value. c) Calculate the line head power factor, active and reactive power drawn from the line head, d) Draw the phasor diagram of the system. ..arrow_forward
- A balanced load of 30 MW is supplied at 132 kV, 50 Hz and 0•85 p.f. lagging by means of a transmission line. The series impedance of a single conductor is (20 + j52) ohms and the total phases-neutral admittance is 315 microsiemens. Shunt leakage may be neglected. Using the nominal T approximation, calculate the line voltage at the sending end of the line. If the load is removed and the sending end voltage remains constant, find the percentage rise in voltage at the receiving end.arrow_forwardA three phase 50 Hz transmission line has impedance of (25.3+ j66.5) ohms and a shunt admittance of 4.42 x 104 mho per phase. If it delivers a load of 50 MW at 220 kV at 0.8 power factor lagging, determine the sending end voltage (a) by short line approximation (b) nominal II method (c) exact transmission line equations.arrow_forward2. A 200-km, 230-kV, 60-Hz three-phase line has a positive-sequence series impedance z = 0.07 + j0.58 ohms/km and a positive-sequence shunt admittance y = j4.33 x 10^-6 S/ km. At full load, the line delivers 350 MW at 0.95 pf lagging and at 220 kV. Using the nominal pi circuit, calculate: (a) the ABCD parameters (b) the sending-end voltage and current, and (c) the percent voltage regulation.arrow_forward
- A three-phase transmission line is 160 km long and supplies a load of 12 MW at 0.85 powerfactor lagging at 80 kV, 50 Hz. Each conductor has a resistance of 0.275 Ω / km, an inductivereactance of 0.5625 Ω / km and a capacitance to neutral of 0.008625 µF / km. Calculate the line-to-line sending end voltage and the sending end current, using: i. The nominal T method.ii. The nominal Π method. If the sending end voltage remains constant, estimate the approximate rise in voltage at thereceiving end when the load is switched off. Hence calculate the per unit voltage regulation ofthe transmission line.arrow_forwardThe length of a transmission line is (1000/3) kilometers. For this transmission line r=0.15 ohm/km x=0.8 Ohm/km y=5 * 10^-6 S/km given in the form. At the end of the line (36) MW is drawn and the end-of-line voltage is (220) kV. power factor: 0.95 (back) a. Assuming the line as a short line, calculate the VS and IS values with their angles. b. A, B, C, D by accepting the line as a mid-length line and using the "T" model approach. Calculate the parameters (Vs Is calculation is not needed) C. Calculate only parameter A, assuming the line as a long line.arrow_forwardQuestion-2) The parameters of a three-phase transmission line are given as Z = (12.84 + j72, 76)Ω and y = j5, 83x10^-4 mho. At the end of the line, a power of 55 MVA with a power factor of 0.8 is drawn under 132 kV voltage. Accordingly, calculate the line head voltage, active and reactive power values per line, and voltage regulation of the line using the nominal π circuit.7-) Since 55 MVA power is drawn from the end of the line under the conditions mentioned above, calculate the line head voltage (phase-phase voltage) and enter it in the box below. (The value will be entered in kiloVolts. Only the amplitude value of the voltage will be entered. The phase value will NOT be entered!!! Two digits after the comma will be sufficient. )8-) Since 55 MVA power is drawn from the end of the line under the conditions mentioned above, calculate the active power value per line and enter it in the box below. (The value will be entered in MegaWatt. It will be sufficient to take two digits after…arrow_forward
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