Concept explainers
(a)
Interpretation: The given pair of compounds, A and B is to be classified as identical molecules, enantiomers, or diastereomers.
Concept introduction: Enantiomers of a compound are the stereoisomers which are non-super imposable mirror images. A carbon atom bonded to four different groups is known as a chiral carbon. A compound which has a chiral carbon can be resolved into enantiomers.
Diastereomers of a compound are the stereoisomers which are non-super imposable non mirror images. On the other hand, identical molecules have superimposable mirror images and similar chemical and physical properties. They possess same
(b)
Interpretation: The given pair of compounds, A and C is to be classified as identical molecules, enantiomers, or diastereomers.
Concept introduction: Enantiomers of a compound are the stereoisomers which are non-super imposable mirror images. A carbon atom bonded to four different groups is known as a chiral carbon. A compound which has a chiral carbon can be resolved into enantiomers.
Diastereomers of a compound are the stereoisomers which are non-super imposable non mirror images. On the other hand, identical molecules have superimposable mirror images and similar chemical and physical properties. They possess same
(c)
Interpretation: The given pair of compounds, A and D is to be classified as identical molecules, enantiomers, or diastereomers.
Concept introduction: Enantiomers of a compound are the stereoisomers which are non-super imposable mirror images. A carbon atom bonded to four different groups is known as a chiral carbon. A compound which has a chiral carbon can be resolved into enantiomers.
Diastereomers of a compound are the stereoisomers which are non-super imposable non mirror images. On the other hand, identical molecules have superimposable mirror images and similar chemical and physical properties. They possess same
(d)
Interpretation: The given pair of compounds, C and D is to be classified as identical molecules, enantiomers, or diastereomers.
Concept introduction: Enantiomers of a compound are the stereoisomers which are non-super imposable mirror images. A carbon atom bonded to four different groups is known as a chiral carbon. A compound which has a chiral carbon can be resolved into enantiomers.
Diastereomers of a compound are the stereoisomers which are non-super imposable non mirror images. On the other hand, identical molecules have superimposable mirror images and similar chemical and physical properties. They possess same
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ORGANIC CHEM W/CONNECT & MODEL KIT >CI
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- Consider the following six compounds (A–F). How are the two compounds in each pair related? Choose from enantiomers, epimers, diastereomers but not epimers, constitutional isomers, and identical compounds.a. A and Bb. A and Cc. B and Cd. A and De. E and Farrow_forwardAnswer the following question about compounds A–D (See in attachment) How are the compounds in each pair related? Choose fromconstitutional isomers, stereoisomers, or identical molecules: A and B; A and C; B and D.arrow_forwardClassify each compound as identical to A or its enantiomer.arrow_forward
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- For each structure, star (*) any asymmetric carbon atoms. label each asymmetric carbon as (R) or (S). draw any internal mirror planes of symmetry. label the structure as chiral or achiral. label any meso structures.*refer to the photo belowarrow_forwardDrawn are four isomeric dimethylcyclopropane. a. How are the compounds in each pair related (enantiomers, diastereomers,constitutional isomers): A and B; A and C; B and C; C and D?b. Label each compound as chiral or achiral.c. Which compounds, alone, would be optically active?d. Which compounds have a plane of symmetry?e. Which of the compounds are meso compounds?f. Would an equal mixture of compounds C and D be optically active? Whatabout an equal mixture of B and C?g. How many stereogenic centers are there for each compound?arrow_forwardDraw all possible configurational stereoisomers for the given molecule below. Designate the R/S on the stereogenic centers and E/Z on the C=Carrow_forward
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