A car is stuck in the mud. A tow truck pulls on the car with the arrangement shown in Figure P5.24. The tow cable is under a tension of 2 500 N and pulls downward and to the left on the pin at its upper end. The light pin is held in equilibrium by forces exerted by the two bars A and B. Each bar is a strut ; that is, each is a bar whose weight is small compared to the forces it exerts and which exerts forces only through hinge pins at its ends. Each strut exerts a force directed parallel to its length. Determine the force of tension or compression in each strut. Proceed as follows. Make a guess as to which way (pushing or pulling) each force acts on the top pin. Draw a free-body diagram of the pin. Use the condition for equilibrium of the pin to translate the free-body diagram into equations. From the equations calculate the forces exerted by struts A and B. If you obtain a positive answer, you correctly guessed the direction of the force. A negative answer means that the direction should be reversed, but the absolute value correctly gives the magnitude of the force. If a strut pulls on a pin. it is in tension. If it pushes, the strut is in compression. Identify whether each strut is in tension or in compression.
A car is stuck in the mud. A tow truck pulls on the car with the arrangement shown in Figure P5.24. The tow cable is under a tension of 2 500 N and pulls downward and to the left on the pin at its upper end. The light pin is held in equilibrium by forces exerted by the two bars A and B. Each bar is a strut ; that is, each is a bar whose weight is small compared to the forces it exerts and which exerts forces only through hinge pins at its ends. Each strut exerts a force directed parallel to its length. Determine the force of tension or compression in each strut. Proceed as follows. Make a guess as to which way (pushing or pulling) each force acts on the top pin. Draw a free-body diagram of the pin. Use the condition for equilibrium of the pin to translate the free-body diagram into equations. From the equations calculate the forces exerted by struts A and B. If you obtain a positive answer, you correctly guessed the direction of the force. A negative answer means that the direction should be reversed, but the absolute value correctly gives the magnitude of the force. If a strut pulls on a pin. it is in tension. If it pushes, the strut is in compression. Identify whether each strut is in tension or in compression.
Solution Summary: The author analyzes the free body diagram and the force exerted by struts A and B.
A car is stuck in the mud. A tow truck pulls on the car with the arrangement shown in Figure P5.24. The tow cable is under a tension of 2 500 N and pulls downward and to the left on the pin at its upper end. The light pin is held in equilibrium by forces exerted by the two bars A and B. Each bar is a strut; that is, each is a bar whose weight is small compared to the forces it exerts and which exerts forces only through hinge pins at its ends. Each strut exerts a force directed parallel to its length. Determine the force of tension or compression in each strut. Proceed as follows. Make a guess as to which way (pushing or pulling) each force acts on the top pin. Draw a free-body diagram of the pin. Use the condition for equilibrium of the pin to translate the free-body diagram into equations. From the equations calculate the forces exerted by struts A and B. If you obtain a positive answer, you correctly guessed the direction of the force. A negative answer means that the direction should be reversed, but the absolute value correctly gives the magnitude of the force. If a strut pulls on a pin. it is in tension. If it pushes, the strut is in compression. Identify whether each strut is in tension or in compression.
A woman stands on a scale while riding in an elevator. When the elevator is at rest, the scale reads 60kg. What will be the reading of the scale in kg when the elevator accelerates. (a) upward at 1.2 m/s^2. (b) downward at 1.2 m/s^2. (c) At what acceleration of the elevator would the person appear to be weightless? Draw the FBD of the problem.
A pig has weight 500 N. It stands on a scale in an elevator, which reads 530 N. Which is correct?A. the elevator is moving at constant velocityB. the elevator is stationaryC. the elevator is accelerating upD. the elevator is accelerating down.
A skier with a mass of 60 kg is sliding down a snowy slope, the slope with an angle of 30 degrees above the horizontal as shown in the figure.
Find Normal force N for the skier as shown in the figure if friction is known to be 45.0 N. Assuming no air resistance and g=10m/s^2
a) 600 N
b) 519.62 N
c) 45 N
d) 38.97 N
Chapter 5 Solutions
Physics for Scientists and Engineers, Technology Update, Hybrid Edition (with Enhanced WebAssign Multi-Term LOE Printed Access Card for Physics)
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