Basic Chemistry (5th Edition)
Basic Chemistry (5th Edition)
5th Edition
ISBN: 9780134138046
Author: Karen C. Timberlake
Publisher: PEARSON
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Chapter 5, Problem 5.96AQAP
Interpretation Introduction

(a)

Interpretation:

The number of 4d electrons in Cd should be determined.

Concept Introduction:

The rules for the allowed quantum numbers combinations are as follows:

  1. All the three quantum numbers ( n, l and m ) describes the orbital of an atom and they are integers.
  2. The principal quantum number, n value cannot be zero. Thus, the values allowed for the principal quantum number are 1, 2, 3, 4, and so on.
  3. The value of angular quantum number, l can be between 0 to n-1. Thus, if value of n is equal to 3 the value of l can be 0, 1 or 2.
  4. The value of magnetic quantum number, m can be between − l to +l . Thus, if value of l is equal to 2, m can be wither -2, -1, 0, +1, or +2
For same number of principal quantum number, an orbital form a shell. The first character denotes the shell and the second identifies the sub-shell.

Here, for s orbital value of l=0 , for p orbital it is l=1 , for d orbital it is l=2 and for f it is 3.

The relative energy of orbitals is represented as follows:

Basic Chemistry (5th Edition), Chapter 5, Problem 5.96AQAP , additional homework tip  1

A s orbital can have maximum of 2 electrons, p orbital can have maximum of 6 electrons. Similarly, maximum electrons that a d and f orbital can have are 10 and 14 respectively.

Interpretation Introduction

(b)

Interpretation:

The number of 4p electrons in Br should be determined.

Concept Introduction:

The rules for the allowed quantum numbers combinations are as follows:

  1. All the three quantum numbers ( n, l and m ) describes the orbital of an atom and they are integers.
  2. The principal quantum number, n value cannot be zero. Thus, the values allowed for the principal quantum number are 1, 2, 3, 4, and so on.
  3. The value of angular quantum number, l can be between 0 to n-1. Thus, if value of n is equal to 3 the value of l can be 0, 1 or 2.
  4. The value of magnetic quantum number, m can be between − l to +l . Thus, if value of l is equal to 2, m can be wither -2, -1, 0, +1, or +2
For same number of principal quantum number, an orbital form a shell. The first character denotes the shell and the second identifies the sub-shell.

Here, for s orbital value of l=0 , for p orbital it is l=1 , for d orbital it is l=2 and for f it is 3.

The relative energy of orbitals is represented as follows:

Basic Chemistry (5th Edition), Chapter 5, Problem 5.96AQAP , additional homework tip  2

A s orbital can have maximum of 2 electrons, p orbital can have maximum of 6 electrons. Similarly, maximum electrons that a d and f orbital can have are 10 and 14 respectively.

Interpretation Introduction

(c)

Interpretation:

The number of 6p electrons in Bi should be determined.

Concept Introduction:

The rules for the allowed quantum numbers combinations are as follows:

  1. All the three quantum numbers ( n, l and m ) describes the orbital of an atom and they are integers.
  2. The principal quantum number, n value cannot be zero. Thus, the values allowed for the principal quantum number are 1, 2, 3, 4, and so on.
  3. The value of angular quantum number, l can be between 0 to n-1. Thus, if value of n is equal to 3 the value of l can be 0, 1 or 2.
  4. The value of magnetic quantum number, m can be between − l to +l . Thus, if value of l is equal to 2, m can be wither -2, -1, 0, +1, or +2
For same number of principal quantum number, an orbital form a shell. The first character denotes the shell and the second identifies the sub-shell.

Here, for s orbital value of l=0 , for p orbital it is l=1 , for d orbital it is l=2 and for f it is 3.

The relative energy of orbitals is represented as follows:

Basic Chemistry (5th Edition), Chapter 5, Problem 5.96AQAP , additional homework tip  3

A s orbital can have maximum of 2 electrons, p orbital can have maximum of 6 electrons. Similarly, maximum electrons that a d and f orbital can have are 10 and 14 respectively.

Interpretation Introduction

(d)

Interpretation:

The number of 4s electrons in Zn should be determined.

Concept Introduction:

The rules for the allowed quantum numbers combinations are as follows:

  1. All the three quantum numbers ( n, l and m ) describes the orbital of an atom and they are integers.
  2. The principal quantum number, n value cannot be zero. Thus, the values allowed for the principal quantum number are 1, 2, 3, 4, and so on.
  3. The value of angular quantum number, l can be between 0 to n-1. Thus, if value of n is equal to 3 the value of l can be 0, 1 or 2.
  4. The value of magnetic quantum number, m can be between − l to +l . Thus, if value of l is equal to 2, m can be wither -2, -1, 0, +1, or +2
For same number of principal quantum number, an orbital form a shell. The first character denotes the shell and the second identifies the sub-shell.

Here, for s orbital value of l=0 , for p orbital it is l=1 , for d orbital it is l=2 and for f it is 3.

The relative energy of orbitals is represented as follows:

Basic Chemistry (5th Edition), Chapter 5, Problem 5.96AQAP , additional homework tip  4

A s orbital can have maximum of 2 electrons, p orbital can have maximum of 6 electrons. Similarly, maximum electrons that a d and f orbital can have are 10 and 14 respectively.

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Chapter 5 Solutions

Basic Chemistry (5th Edition)

Ch. 5.1 - Prob. 5.11QAPCh. 5.1 - Prob. 5.12QAPCh. 5.1 - Place the following types of electromagnetic...Ch. 5.1 - Prob. 5.14QAPCh. 5.2 - What feature of an atomic spectrum indicates that...Ch. 5.2 - Prob. 5.16QAPCh. 5.2 - Prob. 5.17QAPCh. 5.2 - Prob. 5.18QAPCh. 5.2 - Prob. 5.19QAPCh. 5.2 - Identify the photon in each pair with the greater...Ch. 5.3 - Describe the shape of each of the following...Ch. 5.3 - Prob. 5.22QAPCh. 5.3 - Prob. 5.23QAPCh. 5.3 - Prob. 5.24QAPCh. 5.3 - Prob. 5.25QAPCh. 5.3 - Prob. 5.26QAPCh. 5.3 - Prob. 5.27QAPCh. 5.3 - Prob. 5.28QAPCh. 5.4 - Compare the terms electron configuration and...Ch. 5.4 - Prob. 5.30QAPCh. 5.4 - 5.31 Draw the orbital diagram for each of the...Ch. 5.4 - 5.32 Draw the orbital diagram for each of the...Ch. 5.4 - Prob. 5.33QAPCh. 5.4 - Prob. 5.34QAPCh. 5.4 - Prob. 5.35QAPCh. 5.4 - Prob. 5.36QAPCh. 5.4 - Prob. 5.37QAPCh. 5.4 - Prob. 5.38QAPCh. 5.4 - Prob. 5.39QAPCh. 5.4 - Prob. 5.40QAPCh. 5.5 - Use the sublevel blocks on the periodic table to...Ch. 5.5 - Prob. 5.42QAPCh. 5.5 - Prob. 5.43QAPCh. 5.5 - Prob. 5.44QAPCh. 5.5 - Prob. 5.45QAPCh. 5.5 - Prob. 5.46QAPCh. 5.5 - Use the periodic table to give the symbol of the...Ch. 5.5 - Prob. 5.48QAPCh. 5.5 - Prob. 5.49QAPCh. 5.5 - Use the periodic table to give the number of...Ch. 5.6 - What do the group numbers from 1A (1) to 8A (18)...Ch. 5.6 - Prob. 5.52QAPCh. 5.6 - Write the group number using both A/B and 1 to 18...Ch. 5.6 - Prob. 5.54QAPCh. 5.6 - Prob. 5.55QAPCh. 5.6 - Prob. 5.56QAPCh. 5.6 - Prob. 5.57QAPCh. 5.6 - Indicate the number of valence electrons in each...Ch. 5.6 - Write the group number and draw the Lewis symbol...Ch. 5.6 - Prob. 5.60QAPCh. 5.6 - Prob. 5.61QAPCh. 5.6 - Prob. 5.62QAPCh. 5.6 - Prob. 5.63QAPCh. 5.6 - Prob. 5.64QAPCh. 5.6 - Prob. 5.65QAPCh. 5.6 - Prob. 5.66QAPCh. 5.6 - Prob. 5.67QAPCh. 5.6 - Prob. 5.68QAPCh. 5.6 - Prob. 5.69QAPCh. 5.6 - Prob. 5.70QAPCh. 5.6 - Prob. 5.71QAPCh. 5.6 - Fill in each of the following blanks using higher...Ch. 5.6 - Prob. 5.73QAPCh. 5.6 - Prob. 5.74QAPCh. 5.6 - Prob. 5.75QAPCh. 5.6 - Prob. 5.76QAPCh. 5 - Prob. 5.77FUCh. 5 - Prob. 5.78FUCh. 5 - Prob. 5.79UTCCh. 5 - Prob. 5.80UTCCh. 5 - Prob. 5.81UTCCh. 5 - Prob. 5.82UTCCh. 5 - Prob. 5.83UTCCh. 5 - Prob. 5.84UTCCh. 5 - Prob. 5.85UTCCh. 5 - Prob. 5.86UTCCh. 5 - Prob. 5.87AQAPCh. 5 - Prob. 5.88AQAPCh. 5 - Prob. 5.89AQAPCh. 5 - Prob. 5.90AQAPCh. 5 - Prob. 5.91AQAPCh. 5 - Prob. 5.92AQAPCh. 5 - 5.93 a. What electron sublevel starts to fill...Ch. 5 - Prob. 5.94AQAPCh. 5 - Prob. 5.95AQAPCh. 5 - Prob. 5.96AQAPCh. 5 - Prob. 5.97AQAPCh. 5 - Prob. 5.98AQAPCh. 5 - Prob. 5.99AQAPCh. 5 - Prob. 5.100AQAPCh. 5 - Prob. 5.101AQAPCh. 5 - Prob. 5.102AQAPCh. 5 - Prob. 5.103AQAPCh. 5 - Why is the ionization energy of Br lower than that...Ch. 5 - Prob. 5.105AQAPCh. 5 - Prob. 5.106AQAPCh. 5 - Prob. 5.107AQAPCh. 5 - Prob. 5.108AQAPCh. 5 - Prob. 5.109AQAPCh. 5 - Prob. 5.110AQAPCh. 5 - Prob. 5.111AQAPCh. 5 - Prob. 5.112AQAPCh. 5 - Prob. 5.113CQCh. 5 - Prob. 5.114CQCh. 5 - Prob. 5.115CQCh. 5 - Prob. 5.116CQCh. 5 - Prob. 5.117CQCh. 5 - Prob. 5.118CQCh. 5 - Prob. 5.119CQCh. 5 - Prob. 5.120CQ
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