EBK COMPUTER NETWORKING
EBK COMPUTER NETWORKING
7th Edition
ISBN: 8220102955479
Author: Ross
Publisher: PEARSON
Expert Solution & Answer
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Chapter 5, Problem P19P

Explanation of Solution

Given scenario:

Let us consider another stub network “V” is a customer of ISP A.

  • Assuming that “B” and “C” have a peering relationship and “A” proceeds as a customer of both “B” and “C”.
  • The traffic has been destined to W which should come from B only and the traffic destined to “V” can either comes from “B” or “C”...

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Consider 2 small ISPs Y and Z and two large ISPs A and B. Y pays A (but not B) to connect it to the rest of the Internet, while Z pays B (but not A) for its connectivity If ISP A learns of a path to some prefix via ISP B and ISP Z, should it advertise that path to ISP Y? Why or why not?
Suppose there are three nodes in a network, A, B, and C.    A starts transmitting over the medium at time t = 0. The time to transmit a single frame is 100 units.    B and C both sense the medium at t = 5 units and detect that the medium is busy. B and C both have data to transmit.    If A, B, and C were to use a CSMA/CD protocol, suppose that the time at which B and C attempt transmission is given by tB1 and tC1.    If A, B, and C were to use a CSMA/CA protocol, suppose that the time at which B and C attempt transmission is given by tB2 and tC2.    What can be said about the values of tB1, tC1, tB2, and tC2? Choose the most appropriate response.   In the choices below, the notation >= represents "greater than equal to", and != represents "not equal to".   tB1= tC1 = 105, tB2 >= 105, and tC2 >= 105 tB1> 100,  tC1 > 100, tB2 > 100, and tC2 > 100 tB1=  tC1 = tB2 = tC2 = 100 tB1=  tC1 = 100, tB2 >= 100, and tC2 >= 100
Suppose a small ISP X pays a larger ISP A to connect him to the rest of the Internet and also pays another ISP B to provide a fall-back connection to the Internet in the event that he loses connectivity via ISP A. If ISP X learns of a path to some prefix via ISP A, should he advertise that path to ISP B? Why or why not?
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