Statistics for Engineers and Scientists
4th Edition
ISBN: 9780073401331
Author: William Navidi Prof.
Publisher: McGraw-Hill Education
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Textbook Question
Chapter 5.2, Problem 5E
The article “The
- a. Find a 95% confidence interval for the proportion of surgeries that result in complications within six months.
- b. Find a 99% confidence interval for the proportion of surgeries that result in complications within six months.
- c. A surgeon claims that the rate of complications is less than 8.5%. With what level of confidence can this claim be made?
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In an article in the Journal of Advertising, Weinberger and Spotts compare the use of humor in television ads in the United States and the United Kingdom. They found that a substantially greater percentage of U.K. ads use humor.a. Suppose that a random sample of 400 television ads in the United Kingdom reveals that 142 of these ads use humor. Find a point estimate of and a 95 percent confidence interval for the proportion of all U.K. television ads that use humor.b. Suppose a random sample of 500 television ads in the United States reveals that 122 of these ads use humor. Find a point estimate of and a 95 percent confidence interval for the proportion of all U.S. television ads that use humor.c. Do the confidence intervals you computed in parts a and b suggest that a greater percentage of U.K. ads use humor? Explain.
In a recent questionnaire about homeownership, a random sample of 545 homeowners were asked about fixed and adjustable-rate mortgages, and 268 reported that they have an adjustable-rate mortgage.
What value of z should be used to calculate a confidence interval with a 95% confidence level?
z0.10
z0.05
z0.025
z0.01
z0.005
1.282
1.645
1.960
2.326
2.576
In a particular year, approximately 136,943,000 people visited an emergency room in the United States. In a random sample of 100,000 visits, 12,462 were subsequently admitted to the hospital. Provide a 99% confidence interval for the proportion of people visiting an emergency room who were subsequently admitted to the hospital.
a) 0.121745 to 0.127495
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c) 0.122573 to 0.126667
d) 0.122902 to 0.126338
Chapter 5 Solutions
Statistics for Engineers and Scientists
Ch. 5.1 - Find the value of Z/2 to use in expression (5.1)...Ch. 5.1 - Find the levels of the confidence intervals that...Ch. 5.1 - As the confidence level goes up, the reliability...Ch. 5.1 - The article Modeling Arterial Signal Optimization...Ch. 5.1 - In a sample of 100 steel wires the average...Ch. 5.1 - The article Application of Surgical Navigation to...Ch. 5.1 - The capacities (in ampere-hours) were measured for...Ch. 5.1 - Oven thermostats were tested by setting them to...Ch. 5.1 - In a sample of 80 ten-penny nails, the average...Ch. 5.1 - In a sample of 60 electric motors, the average...
Ch. 5.1 - The sugar content in a one-cup serving of a...Ch. 5.1 - Refer to Exercise 5. a. Find a 95% lower...Ch. 5.1 - Prob. 13ECh. 5.1 - Prob. 14ECh. 5.1 - Prob. 15ECh. 5.1 - Refer to Exercise 9. a. Find a 90% upper...Ch. 5.1 - Refer to Exercise 10. a. Find a 98% lower...Ch. 5.1 - Refer to Exercise 11. a. Find a 95% upper...Ch. 5.1 - Prob. 19ECh. 5.1 - A 95% confidence interval for a population mean is...Ch. 5.1 - Based on a large sample of capacitors of a certain...Ch. 5.1 - Sixty-four independent measurements were made of...Ch. 5.1 - A large box contains 10,000 ball bearings. A...Ch. 5.1 - Prob. 24ECh. 5.1 - Prob. 25ECh. 5.1 - Prob. 26ECh. 5.2 - In a simple random sample of 70 automobiles...Ch. 5.2 - During a recent drought, a water utility in a...Ch. 5.2 - A soft-drink manufacturer purchases aluminum cans...Ch. 5.2 - The article HIV-positive Smokers Considering...Ch. 5.2 - The article The Functional Outcomes of Total Knee...Ch. 5.2 - Refer to Exercise 1. Find a 95% lower confidence...Ch. 5.2 - Refer to Exercise 2. Find a 98% upper confidence...Ch. 5.2 - Refer to Exercise 4. Find a 99% lower confidence...Ch. 5.2 - A random sample of 400 electronic components...Ch. 5.2 - Refer to Exercise 9. A device will be manufactured...Ch. 5.2 - When the light turns yellow, should you stop or go...Ch. 5.2 - In a random sample of 150 customers of a...Ch. 5.2 - A sociologist is interested in surveying workers...Ch. 5.2 - Stainless steels can be susceptible to stress...Ch. 5.2 - The article A Music Key Detection Method Based on...Ch. 5.2 - A stock market analyst notices that in a certain...Ch. 5.3 - Find the value of tn1,/2 needed to construct a...Ch. 5.3 - Find the value of tn1, needed to construct an...Ch. 5.3 - Find the level of a two-sided confidence interval...Ch. 5.3 - True or false: The Students t distribution may be...Ch. 5.3 - The article Wind-Uplift Capacity of Residential...Ch. 5.3 - Prob. 6ECh. 5.3 - The article An Automatic Visual System for Marble...Ch. 5.3 - A chemist made eight independent measurements of...Ch. 5.3 - Six measurements are taken of the thickness of a...Ch. 5.3 - Fission tracks are trails found in uranium-bearing...Ch. 5.3 - The article Effect of Granular Subbase Thickness...Ch. 5.3 - The article Influence of Penetration Rate on...Ch. 5.3 - Prob. 13ECh. 5.3 - Prob. 14ECh. 5.3 - Prob. 15ECh. 5.3 - The concentration of carbon monoxide (CO) in a gas...Ch. 5.3 - The article Filtration Rates of the Zebra Mussel...Ch. 5.4 - To study the effect of curing temperature on shear...Ch. 5.4 - The article Some Parameters of the Population...Ch. 5.4 - The article Inconsistent Health Perceptions for US...Ch. 5.4 - The article Hatching Distribution of Eggs Varying...Ch. 5.4 - The article Automatic Filtering of Outliers in RR...Ch. 5.4 - A group of 78 people enrolled in a weight-loss...Ch. 5.4 - In experiments to determine the effectiveness of...Ch. 5.4 - A stress analysis was conducted on random samples...Ch. 5.4 - In a study to compare two different corrosion...Ch. 5.4 - An electrical engineer wishes to compare the mean...Ch. 5.4 - In a study of the effect of cooling rate on the...Ch. 5.4 - Refer to Exercise 11. Ten more welds will be made...Ch. 5.4 - The article The Prevalence of Daytime Napping and...Ch. 5.4 - The article Occurrence and Distribution of...Ch. 5.5 - In a test of the effect of dampness on electric...Ch. 5.5 - The specification for the pull strength of a wire...Ch. 5.5 - Angioplasty is a medical procedure in which an...Ch. 5.5 - Prob. 4ECh. 5.5 - Prob. 5ECh. 5.5 - Prob. 6ECh. 5.5 - In a study of contamination at landfills...Ch. 5.5 - Prob. 8ECh. 5.5 - A mobile computer network consists of a number of...Ch. 5.5 - The article Evaluation of Criteria for Setting...Ch. 5.5 - In a certain year, there were 80 days with...Ch. 5.6 - In a study comparing various methods of gold...Ch. 5.6 - Prob. 2ECh. 5.6 - In an experiment involving the breaking strength...Ch. 5.6 - A new post-surgical treatment is being compared...Ch. 5.6 - The article Differences in Susceptibilities of...Ch. 5.6 - The article Tibiofemoral Cartilage Thickness...Ch. 5.6 - During the spring of 1999, many fuel storage...Ch. 5.6 - Prob. 8ECh. 5.6 - The article Toward a Lifespan Metric of Reading...Ch. 5.6 - Prob. 10ECh. 5.6 - Measurements of the sodium content in samples of...Ch. 5.6 - Prob. 12ECh. 5.6 - Prob. 13ECh. 5.6 - In the article Bactericidal Properties of Flat...Ch. 5.6 - Prob. 15ECh. 5.7 - The article Simulation of the Hot Carbonate...Ch. 5.7 - The article Effect of Refrigeration on the...Ch. 5.7 - Transepidermal water loss (TEWL) is a measure of...Ch. 5.7 - Breathing rates, in breaths per minute, were...Ch. 5.7 - A group of five individuals with high blood...Ch. 5.7 - A sample of 10 diesel trucks were run both hot and...Ch. 5.7 - For a sample of nine automobiles, the mileage (in...Ch. 5.7 - Prob. 8ECh. 5.7 - Prob. 9ECh. 5.7 - Prob. 10ECh. 5.8 - Find the following values. a. 12,.0252 b. 12,.9752...Ch. 5.8 - Prob. 2ECh. 5.8 - Construct a 99% confidence interval for the...Ch. 5.8 - Prob. 4ECh. 5.8 - Scores on an IQ test are normally distributed. A...Ch. 5.8 - Prob. 6ECh. 5.8 - Boxes of cereal are labeled as containing 14...Ch. 5.8 - Prob. 8ECh. 5.8 - Following are interest rates (annual percentage...Ch. 5.8 - Prob. 10ECh. 5.8 - Prob. 11ECh. 5.8 - Prob. 12ECh. 5.9 - A sample of 25 resistors, each labeled 100, had an...Ch. 5.9 - Prob. 2ECh. 5.9 - The article Ozone for Removal of Acute Toxicity...Ch. 5.9 - Six measurements were made of the concentration...Ch. 5.9 - Five measurements are taken of the octane rating...Ch. 5 - A molecular biologist is studying the...Ch. 5 - Prob. 2SECh. 5 - The article Genetically Based Tolerance to...Ch. 5 - A sample of 87 glass sheets has a mean thickness...Ch. 5 - Prob. 5SECh. 5 - Prob. 6SECh. 5 - Leakage from underground fuel tanks has been a...Ch. 5 - Prob. 8SECh. 5 - Prob. 9SECh. 5 - Prob. 10SECh. 5 - In the article Groundwater Electromagnetic Imaging...Ch. 5 - Prob. 12SECh. 5 - Prob. 13SECh. 5 - Prob. 14SECh. 5 - A metallurgist makes several measurements of the...Ch. 5 - In a study of the lifetimes of electronic...Ch. 5 - The temperature of a certain solution is estimated...Ch. 5 - Prob. 18SECh. 5 - Prob. 19SECh. 5 - The answer to Exercise 19 part (d) is needed for...Ch. 5 - The carbon content (in ppm) was measured for each...Ch. 5 - Diameters, in mm, were measured for eight...Ch. 5 - A sample of eight repair records for a certain...Ch. 5 - Prob. 25SE
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- In a recent survey of US adults, 35 people were asked the question: “Do you own a smart phone?”. Of those surveyed, 29 responded that they own a smart phone. Use the “plus-four” method to find a 90% confidence interval for the true proportion of US adults who own a smart phone. Use the z-score table below: z0.10 z0.05 z0.025 z0.01 z0.005 1.282 1.645 1.960 2.326 2.576arrow_forwardA research group studying cell phone habits asked the question “Do you ever use your cell phone to make a payment at a convenience store?” to people selected from two random samples of cell phone users. One sample consisted of older adults, ages 35 years and older, and the other sample consisted of younger adults, ages 18 years to 34 years. The proportion of people who answered yes in each sample was used to create a 95 percent confidence interval of (0.097,0.125)(0.097,0.125) to estimate the difference (younger minus older) between the population proportions of people who would answer yes to the question. Which of the following is the best description of what is meant by 95 percent confidence? In repeated random sampling with the same sample size, approximately 95% of the sample proportions from the younger group will be between 0.097 and 0.125 greater than the sample proportion from the older group. A In repeated random sampling with the same sample size,…arrow_forwardIn a situation where the sample size was decreased from 39 to 29 in a normally distributed data set, what would be the impact on the confidence interval?arrow_forward
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