# The most energetic line among the given lines in the emission spectrum of mercury has to be identified. Concept introduction: Planck’s equation, E = hν = hc λ where, E = energy h = Planck's constant ν = frequency The energy increases as the wavelength of the light decrease. Also the energy increases as the frequency of the light increases. The frequency of the light is inversely proportional to its wavelength. ν = c λ where, c = speed of light ν = frequency λ = wavelength ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640 ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640

#### Solutions

Chapter 6, Problem 13PS

(a)

Interpretation Introduction

## Interpretation: The most energetic line among the given lines in the emission spectrum of mercury has to be identified.Concept introduction: Planck’s equation,    E = hν =hcλwhere, E = energyh = Planck's constantν = frequencyThe energy increases as the wavelength of the light decrease. Also the energy increases as the frequency of the light increases. The frequency of the light is inversely proportional to its wavelength.  ν = cλwhere, c = speed of lightν = frequencyλ = wavelength

(b)

Interpretation Introduction

### Interpretation: The frequency and the energy per photon of most energetic line in the emission spectrum of mercury have to be calculated.Concept introduction: Planck’s equation,    E = hν =hcλwhere, E = energyh = Planck's constantν = frequencyThe energy increases as the wavelength of the light decrease. Also the energy increases as the frequency of the light increases. The frequency of the light is inversely proportional to its wavelength.  ν = cλwhere, c = speed of lightν = frequencyλ = wavelength

(c)

Interpretation Introduction

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