Concepts of Genetics (12th Edition)
12th Edition
ISBN: 9780134604718
Author: William S. Klug, Michael R. Cummings, Charlotte A. Spencer, Michael A. Palladino, Darrell Killian
Publisher: PEARSON
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Chapter 6, Problem 22ESP
In studies of recombination between mutants 1 and 2 from Problem 21, the results shown in the following table were obtained.
- (a) Calculate the recombination frequency.
- (b) When mutant 6 was tested for recombination with mutant 1, the data were the same as those shown above for strain B, but not for K12. The researcher lost the K12 data, but remembered that recombination was ten times more frequent than when mutants 1 and 2 were tested. What were the lost values (dilution and plaque numbers)?
- (c) Mutant 7 (Problem 21) failed to complement any of the other mutants (1–6). Define the nature of mutant 7.
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Chapter 6 Solutions
Concepts of Genetics (12th Edition)
Ch. 6 - When the interrupted mating technique was used...Ch. 6 - In a transformation experiment involving a...Ch. 6 - In complementation studies of the rII locus of...Ch. 6 - A 4-month-old infant had been running a moderate...Ch. 6 - Prob. 2CSCh. 6 - Prob. 3CSCh. 6 - Prob. 4CSCh. 6 - HOW DO WE KNOW? In this chapter, we have focused...Ch. 6 - Review the Chapter Concepts list on p. 123. Many...Ch. 6 - With respect to F+ and F bacterial matings, answer...
Ch. 6 - List all major differences between (a) the F+ F...Ch. 6 - Describe the basis for chromosome mapping in the...Ch. 6 - In general, when recombination experiments are...Ch. 6 - Why are the recombinants produced from an Hfr F...Ch. 6 - Describe the origin of F bacteria and merozygotes.Ch. 6 - In a transformation experiment, donor DNA was...Ch. 6 - Describe the role of heteroduplex formation during...Ch. 6 - Explain the observations that led Zinder and...Ch. 6 - Prob. 12PDQCh. 6 - Two theoretical genetic strains of a virus (abc...Ch. 6 - The bacteriophage genome consists of many genes...Ch. 6 - If a single bacteriophage infects one E. coli cell...Ch. 6 - A phage-infected bacterial culture was subjected...Ch. 6 - In recombination studies of the rII locus in phage...Ch. 6 - In an analysis of rII mutants, complementation...Ch. 6 - If further testing of the mutations in Problem 18...Ch. 6 - Using mutants 2 and 3 from Problem 19, following...Ch. 6 - During the analysis of seven rII mutations in...Ch. 6 - In studies of recombination between mutants 1 and...Ch. 6 - Prob. 23ESPCh. 6 - An Hfr strain is used to map three genes in an...Ch. 6 - A plaque assay is performed beginning with 1 mL of...Ch. 6 - In a cotransformation experiment, using various...Ch. 6 - For the experiment in Problem 26, another gene, g,...Ch. 6 - Bacterial conjugation, mediated mainly by...Ch. 6 - A study was conducted in an attempt to determine...
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- Homozygous wild-type male mice (AA BB CC) were crossed with triplemutant female mice (aa bb cc), forming an F1 generation with the followinggenotype (Aa Bb Cc). The F1 males were crossed with triple mutantfemales, forming the following F2 phenotypes”“a B c” 3“A b C” 3“a b c” 8“A B c” 5“a b C” 5“A B C” 8“a B C” 6“A b c” 6 44 Determine the sequence of the genesarrow_forwardIn the example shown , what is the underlying cause of nonallelichomologous recombination?arrow_forwardWhy is the upper limit of recombination 50% rather than 100%?arrow_forward
- Draw the genetic map using the following two-point cross data. Locus1 Locus2 Recombination Frequency (%) Locus1 Locus2 Recombination Frequency (%) buckY captAm 50 falcoN tchallA 39 buckY falcoN 50 falcoN visioN 50 buckY natashA 11 falcoN wandA 39 buckY tchallA 50 falcoN wasP 5 buckY visioN 37 natashA tchallA 50 buckY wandA 50 natashA visioN 44 buckY wasP 50 natashA wandA 50 captAm falcoN 30 natashA wasP 50 captAm natashA 50 tchallA visioN 50 captAm tchallA 50 tchallA wandA 50 captAm visioN 50 tchallA wasP 42 captAm wandA 10 visioN wandA 50 captAm wasP 26 visioN wasP 50 falcoN natashA 50 wandA wasP 33arrow_forwardIn a series of two-point map crosses involving five genes locatedon chromosome II in Drosophila, the following recombinant (single- crossover) frequencies were observed:pr–adp 29pr–vg 13pr–c 21pr–b 6adp–b 35adp–c 8adp–vg 16vg–b 19vg–c 8c–b 27 In another set of experiments, a sixth gene (d) was testedagainst b and pr, and the results were d - b = 17% andd - pr = 23%. Predict the results of two-point mapsbetween d and c, d and vg, and d and adp.arrow_forwardThe recombination frequency in a cross can never exceed 50%. Explain why is this limit?arrow_forward
- What does a recombination frequency of 50 indicate?arrow_forwardWhat is the name of the process in which a single strand of DNA disrupts a homologous dsDNA molecule and forms base pairs with one of the strands of this dsDNA molecule? During the recombination process does the single-stranded DNA molecule have a free 5' end, 3' end, or either?”arrow_forwardRecombination frequencies have been determined between four genes (A, B, C and D) as follows: A-B: 20%, B-C: 50%, A-D: 50%, C-D: 5% Which of the four genes is/are likely linked on the same chromosome?arrow_forward
- Recombination frequencies between three loci in corn are shown in the following table: Loci Recombination frequency (%) R and W2 17 R and L2 35 W2 and L2 18 What is the order of the genes on the chromosome?arrow_forwardFor this particular family, what is the recombination rate between the D17S74 marker and the breast cancer gene? Lets say that at age 45 the third granddaughter III-3, is diagnosed with breast cancer. Now recalculate the recombination rate between the marker locus D17S74 and the breast cancer gene? Use only the 5 women in your analysis:the two daugthers in generation II and the three granddaughters in generation IIarrow_forwardWhat characteristic specifically defines a High Frequency Recombination (HFr) cell line?arrow_forward
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genetic recombination strategies of bacteria CONJUGATION, TRANSDUCTION AND TRANSFORMATION; Author: Scientist Cindy;https://www.youtube.com/watch?v=_Va8FZJEl9A;License: Standard youtube license