EBK CONCEPTS OF GENETICS
12th Edition
ISBN: 9780134818979
Author: Killian
Publisher: YUZU
expand_more
expand_more
format_list_bulleted
Concept explainers
Textbook Question
Chapter 6, Problem 25ESP
A plaque assay is performed beginning with 1 mL of a solution containing bacteriophages. This solution is serially diluted three times by combining 0.1 mL of each sequential dilution with 9.9 mL of liquid medium. Then 0.1 mL of the final dilution is plated in the plaque assay and yields 17 plaques. What is the initial density of bacteriophages in the original 1 mL?
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
A plaque assay is performed beginning with 1 mL of a solution containing bacteriophages. This solution is serially diluted 3 times by combining 0.1 mL of each sequential dilution with 9.9 mL of liquid medium. Then 0.1 mL of the final dilution is plated in the plaque assay and yields 12 plaques.What is the initial density of bacteriophages in the original 1 mL? Enter your answer to two significant figures ( for example: 1.1 * 10^2)
A plaque assay is performed beginning with 1 mL of a solution containing bacteriophages. This solution is serially diluted 4 times by combining 0.1 mL of each sequential dilution with 9.9 mL of liquid medium. Then 0.1 mL of the final dilution is plated in the plaque assay and yields 21 plaques. What is the initial density of bacteriophages in the original 1 mL? Recall that initial phage density = (plaque number/mL) ×× (dilution factor).
Considering counting rules, calculate the initial titre of the sample viral stock if the following plaques
were counted in a plaque assay. Show clear sample calculations.
Table 1: Plaque assay counts for lambda phage stock titre enumeration of average concentration
(PFU/mL)
Total dilution of viral stock
1/13500000
1/135000000
1/135000000
plated
Volume diluted viral stock
0.1
0.1
0.1
plated (mL)
PFU replicate 1
TNTC
275
25
Calculated concentration
(PFU/mL) replicate 1
PFU replicate 2
TNTC
239
23
Calculated concentration
(PFU/mL) replicate 2
Average concentration
(PFU/mL)
Chapter 6 Solutions
EBK CONCEPTS OF GENETICS
Ch. 6 - When the interrupted mating technique was used...Ch. 6 - In a transformation experiment involving a...Ch. 6 - In complementation studies of the rII locus of...Ch. 6 - A 4-month-old infant had been running a moderate...Ch. 6 - Prob. 2CSCh. 6 - Prob. 3CSCh. 6 - Prob. 4CSCh. 6 - HOW DO WE KNOW? In this chapter, we have focused...Ch. 6 - Review the Chapter Concepts list on p. 123. Many...Ch. 6 - With respect to F+ and F bacterial matings, answer...
Ch. 6 - List all major differences between (a) the F+ F...Ch. 6 - Describe the basis for chromosome mapping in the...Ch. 6 - In general, when recombination experiments are...Ch. 6 - Why are the recombinants produced from an Hfr F...Ch. 6 - Describe the origin of F bacteria and merozygotes.Ch. 6 - In a transformation experiment, donor DNA was...Ch. 6 - Describe the role of heteroduplex formation during...Ch. 6 - Explain the observations that led Zinder and...Ch. 6 - Prob. 12PDQCh. 6 - Two theoretical genetic strains of a virus (abc...Ch. 6 - The bacteriophage genome consists of many genes...Ch. 6 - If a single bacteriophage infects one E. coli cell...Ch. 6 - A phage-infected bacterial culture was subjected...Ch. 6 - In recombination studies of the rII locus in phage...Ch. 6 - In an analysis of rII mutants, complementation...Ch. 6 - If further testing of the mutations in Problem 18...Ch. 6 - Using mutants 2 and 3 from Problem 19, following...Ch. 6 - During the analysis of seven rII mutations in...Ch. 6 - In studies of recombination between mutants 1 and...Ch. 6 - Prob. 23ESPCh. 6 - An Hfr strain is used to map three genes in an...Ch. 6 - A plaque assay is performed beginning with 1 mL of...Ch. 6 - In a cotransformation experiment, using various...Ch. 6 - For the experiment in Problem 26, another gene, g,...Ch. 6 - Bacterial conjugation, mediated mainly by...Ch. 6 - A study was conducted in an attempt to determine...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- In the plaque assay, what is the precise origin of a single plaque?arrow_forwardDr. Wakefield would like to isolate recombinant plasmids from her bacterial culture using the alkaline lysis method. She is planning to use the chemicals as listed below: Solution I: 50 mM glucose, 25 mM Tris-Cl (pH 8.0), 10 mM EDTA (pH 8.0) Solution II: ??? Solution III: 5 M potassium acetate, glacial acetic acid, de-ion water Ethanol 70% (v/v) Isopropanol TE-RNAase pH 8.0 (i) (ii) (iii) Based on the chemical list above, state the content(s) of Solution II. Explain the functions of Solution II described in Q3 a) (i) in plasmid isolation. What is the role of alcohol precipitation conducted after the plasmids are obtained at the end of the procedure? Discuss the roles of ethanol and salt in alcohol precipitation step.arrow_forwardDuring the incubation step of the plaque assay, viral replication leads to host cell lysis. This allows the freshly-released virions to diffuse through the media and infect new hosts. The amount of agar added to the top agar is 7 g per liter rather than the 16 g of agar per liter for most solid media, including the bottom agar used in this assay. How would it change the plaque assay results if bottom agar was used in place of the top agar in this assay? a- The diameter of the plaques would be smaller. b- The diameter of the plaques would not change. c- The diameter of the plaques would be larger. (2) A researcher measured the viral titer of PhiX174 in fish tank water, untreated sewage water, and unpasteurized apple juice. Which sample do you predict will have the highest titer on this page? a- Fish tank water b- Unpasteurized apple juice c- Untreated sewage waterarrow_forward
- During incubation, prepare dilutions of the standard antiserum which constitutes the standard curve for the assay (concentration in ng/mL). Add 500 µL of PBS-milk to the supplied microtube containing 500 µL of standard antiserum to obtain Standard 1 [500 ng/mL]. Identify seven microtubes for standards 2 to 7 and place 500 µL of PBS-milk in each. Calculate how much of antiserum is used in each standard ?arrow_forwardWhich of the following are true regarding assay attributes? List all that are true. a) Accuracy represents the closeness of the assay result to the “true value”. b) Robustness represents the ability of a method to distinguish between the analyte and similar components. c) Precision is determined by replicate analysis of a reference standard or well-characterized material. d) A robust assay would have a very narrow range of acceptable assay conditions. For those that were not true in question 1, correct the statement(s).arrow_forwardUsing the table below, what volume from the master mix will be dispensed to each sample tube if the genomic DNA is 1 µL and the Taq polymerase is 0.3 µL?arrow_forward
- Since higher concentration colcemid will result in shorter chromosome, you want to change your protocol and reduce final concentration of colcemid in your 10 ml blood culture from 0.1ug/ml to 0.05ug/ml. how many ul colcemid stock solution with concentration10ug/ml needed to be added in 10ml blood culture?arrow_forwardCentrifugation is the first step in most fractionations, but it separates only components that differ greatly in size. Compare and contrast very high, high, medium, and low-speed centrifugations of supernatant mixtures. Define the following: SDS Polyacrylamide-Gel Electrophoresis and Immunoprecipitationarrow_forwardYou are counting plaques on your plaque assay plates made from serial dilutions of your high titer lysate. Your 10-5 plate has 615 plaques although some are butting up against each other so it is difficult to get an accurate count. Your 10-6 plate has 42 plaques, and your 10-7 plate has only 1 plaque. Which plate would probably yield the most accurate titer calculation of your phage and why is it more trustworthy than the others?arrow_forward
- Two auxotrophic triple Escherichia coli strains (A: met- phe- ade- val+ bio+ thr+ and B: met+ phe+ ade+ val- bio- thr-) are mixed in LB liquid medium, diluted and then spread on LB solid rich medium. Six colonies are observed: Then, replicates are performed on 6 different media (minimum medium + glucose + indicated substances). The results are shown below. Determine the genotype of the 6 colonies observed. Which ones are from strain A? From strain B? Which hypotheses can explain these results and which one do you prefer? met phe val bio Abbreviations: met ade val thr phe ade bio thr Met: methionine; Phe: phenylalanine; Ade: adenine; Val: valine; Bio: biotin; Thr: threonine.arrow_forwardWe need to prepare a stock solution of medium for your culture cells, which usually includes liquid salt solution and bovine serum. Our liquid salt solution is supplied in a 50X concentration, and we need to dilute it to 1X for use. We also need to add 75% fetal bovine serum for a final concentration of 15%. How would we make up 0.80 liters of this culture media using water as our solvent?arrow_forward3) Were all of the conditions of a standardized Kirby-Bauer test met as you performed this assay? If not, which were not? 4) What is the significance of colonies that develop within otherwise clear zones of inhibition? If the laboratory report for one of your patients indicated colonies within the zone, what concerns would you have for your patient?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Molecular Techniques: Basic Concepts; Author: Dr. A's Clinical Lab Videos;https://www.youtube.com/watch?v=7HFHZy8h6z0;License: Standard Youtube License