Chapter 6, Problem 6.49QP

Interpretation Introduction

Interpretation:

The reason why ${\text{H}}_{\text{2}}{\text{O}}_{\text{2(l)}}$ has the tendency to decompose into ${\text{H}}_{\text{2}}{\text{O}}_{\text{(l)}}$ and ${\text{O}}_{\text{2(g)}}$ in spite of having negative value of ${\text{ΔH°}}_{\text{f}}$.

Concept Introduction:

The change in enthalpy that is associated with the formation of one mole of a substance from its related elements being in standard state is called standard enthalpy of formation (${\text{ΔH}}_{\text{f}}\text{°}$).  The standard enthalpy of formation is used to determine the standard enthalpies of compound and element.

The standard enthalpy of reaction is the enthalpy of reaction that takes place under standard conditions.

To explain: The reason why ${\text{H}}_{\text{2}}{\text{O}}_{\text{2(l)}}$ has the tendency to decompose into ${\text{H}}_{\text{2}}{\text{O}}_{\text{(l)}}$ and ${\text{O}}_{\text{2(g)}}$ in spite of having negative value of ${\text{ΔH°}}_{\text{f}}$