Chapter 6, Problem 6.94QP

Interpretation Introduction

Interpretation:

The change in enthalpy of $\text{6}{\text{.6×10}}^{\text{5}}\text{g}\text{of}{\text{SO}}_{\text{2}}$ removed from the process has to be calculated.

Concept Introduction:

The change in enthalpy that is associated with the formation of one mole of a substance from its related elements being in standard state is called standard enthalpy of formation (${\text{ΔH}}_{\text{f}}\text{°}$).  The standard enthalpy of formation is used to determine the standard enthalpies of compound and element.

The standard enthalpy of reaction is the enthalpy of reaction that takes place under standard conditions.

 The equation for determining the standard enthalpies of compound and element can be given by,

${\text{ΔH°}}_{\text{reaction}}\text{=}{\displaystyle \sum {\text{nΔH°}}_{\text{f}}\text{(products)}}\text{-}{\displaystyle \sum {\text{mΔH°}}_{\text{f}}\text{(reactants)}}$

To calculate: The change in enthalpy of $\text{6}{\text{.6×10}}^{\text{5}}\text{g}\text{of}{\text{SO}}_{\text{2}}$