Interpretation: The transfer of an ethyl group by triethyloxonium tetrafluoroborate to a nucleophile in a
Concept introduction: The replacement or substitution of one
The nucleophilic reaction contains a substrate as well as a nucleophile as the reactants which mean a bimolecular nucleophilic reaction is termed as
The
To determine: A mechanism for the transfer of an ethyl group by triethyloxonium tetrafluoroborate to a nucleophile in a
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Chapter 6 Solutions
ORGANIC CHEMISTRY MASTERINGCHEM ACCESS
- Complete the reactions below using the required reagents or products. If there is no reaction, indicate so. If a product is in the majority, specify which one.arrow_forwardConsider the attached E2 reaction What happens to the reaction rate with each of the following changes?[1] The solvent is changed to DMF. [2] The concentration of −OC(CH3)3 is decreased. [3] The base is changed to −OH. [4] The halide is changed to CH3CH2CH2CH2CH(Br)CH3. [5] The leaving group is changed to I−.arrow_forwardChoose the reagent(s) that would be most likely to complete this reaction. I||| / A B C D 1. BH3-THF 2. H2O2, NaOH Br₂ H₂O OsO4 (catalytic) NMO RCO3H Donearrow_forward
- Complete the reaction scheme below. Show all reagents and intermediates. No reaction is a possible answer. Do not neglect stereochemistry. NaCN DIBAL Br в A "OCH3 (sodium cyanide)arrow_forward5a) Draw the product(s) of the reaction shown below. Additionally, identify the nucleophile, electrophile and leaving group.arrow_forwardSuggest a reasonable mechanism for the reaction shown Br here. HO CH;CH,OHarrow_forward
- Select reagents from the table to carry out this transformation in 5 steps.arrow_forwardGive a reasonable mechanism for this reaction. Explain why it is exothermic. H+ хо Дон H2Oarrow_forwarda) Briefly explain the reason by showing what kind of reaction mechanism the main product (major) and by-product (minor) will be formed as a result of the reaction of 1 chlorobutane and 2 chloro butane with NaOH, a strong base (nucleophile). b) In the presence of a polar solvent and in the presence of a polar solvent and reacting with sodium ethoxide (NaOC,H5), 2-Bromo-2-methyl propane can be formed when the main product (major) and by-product (minor) will be formed by showing which reaction mechanism will be followed and briefly explain why.arrow_forward
- Draw the neutral organic starting material. The Hint: The reaction conditions support electrophilic addition of Br2 to an alkene's C=C double bond, which would normally yield a dibromo product. However, the product has only one bromine atom, with a C–O bond on the adjacent carbon. This fragment is diagnostic for a halohydrin, where an oxygen nucleophile (water or alcohol) reacts with a bromonium intermediate to generate the O–CH2CH2–Br motif. Work backwards to determine what the starting material must look like. There should be an alcohol and an alkene in the neutral organic starting material.arrow_forwardConstruct a three‑step synthesis of 1,2‑epoxycyclopentane from bromocyclopentane by dragging the appropriate formulas into the bins. Note that each bin should hold only one item, and not all of the given reagents or structures will be used. Reactant −→−−−−reagent 1 →reagent 1 Step 1 product −→−−−−reagent 2 →reagent 2 Step 2 product −→−−−−reagent 3 →reagent 3 Final productarrow_forwardThe following flow chart connects three of the reactions we have discussed that involve carbocation intermediates. Each arrow may represent more than one elementary step in a mechanism.Arrows 1 and 2 summarize the conversion of alcohols to alkyl halides, 3 and 4 the dehydrohalogenation of an alkyl halide to an alkene by the E1 mechanism, and 1 and 4 the formation of an alkene by dehydration of an alcohol. The reaction indicated by arrow 5 constitutes a major focus of the next chapter. There we will explore reactions that give overall addition to the double bond by way of carbocation intermediates. One such process converts alkenes to alkyl halides (5 + 2), another converts alkenes to alcohols (5 + 6).What term best describes the relationship between an alkene and a carbocation? A. Isomers B. Resonance contributors C. Alkene is conjugate acid of carbocation D. Alkene is conjugate base of carbocationarrow_forward
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