Foundations of Materials Science and Engineering
6th Edition
ISBN: 9781259696558
Author: SMITH
Publisher: MCG
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Chapter 6.13, Problem 73SEP
When manufacturing complex shapes using cold forging or shape rolling operations, the
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A cylindrical billet that is 100 mm long and 50 mm in diameter is reduced by indirect (backward) extrusion to a 20 mm diameter. The die angle is 90°. In the Johnson equation, a = 0.8 and b = 1.4. In the flow curve for the work metal, the strength coefficient = 800 MPa and strain hardening exponent = 0.13. Determine
d) ram pressure, and (e) ram force
An austenitic stainless steel plate with a width of 100 mm, a length of 150 mm and a thickness of 50 mm is to be hot forged in a hydraulic press so that the width remains constant. If it is to be reduced in one step to a thickness of 40 mm, calculatea) the actual load that needs to be applied at the end of the forging, as well as b) the corresponding deformation energy.
In previous plane strain compression tests, it was found that the material exhibits an average plane strain yield stress of 80 MPa at the forging temperature. Assume that the efficiency of the process is 0.6
Answer: Pfr= 2.5 MN ; WTr= 25 kJ
1 What is the difference between open-die and closed-die forging? Give an example of a metal product produced by each process.
Chapter 6 Solutions
Foundations of Materials Science and Engineering
Ch. 6.13 - (a) How are metal alloys made by the casting...Ch. 6.13 - Why are cast metal sheet ingots hot-rolled first...Ch. 6.13 - What type of heat treatment is given to the rolled...Ch. 6.13 - Describe and illustrate the following types of...Ch. 6.13 - Describe the forging process. What is the...Ch. 6.13 - What is the difference between open-die and...Ch. 6.13 - Describe the wire-drawing process. Why is it...Ch. 6.13 - Distinguish between elastic and plastic...Ch. 6.13 - Define (a) engineering stress and strain and (b)...Ch. 6.13 - Define (a) modulus of elasticity, (b) yield...
Ch. 6.13 - (a) Define the hardness of a metal. (b) How is the...Ch. 6.13 - What types of indenters are used in (a) the...Ch. 6.13 - What are slipbands and slip lines? What causes the...Ch. 6.13 - Describe the slip mechanism that enables a metal...Ch. 6.13 - (a) Why does slip in metals usually take place on...Ch. 6.13 - Prob. 16KCPCh. 6.13 - What other types of slip planes are important...Ch. 6.13 - Define the critical resolved shear stress for a...Ch. 6.13 - Describe the deformation twinning process that...Ch. 6.13 - What is the difference between the slip and...Ch. 6.13 - Prob. 21KCPCh. 6.13 - Prob. 22KCPCh. 6.13 - What experimental evidence shows that grain...Ch. 6.13 - (a) Describe the grain shape changes that occur...Ch. 6.13 - How is the ductility of a metal normally affected...Ch. 6.13 - (a) What is solid-solution strengthening? Describe...Ch. 6.13 - What are the three main metallurgical stages that...Ch. 6.13 - Describe the microstructure of a heavily...Ch. 6.13 - Describe what occurs microscopically when a...Ch. 6.13 - When a cold-worked metal is heated into the...Ch. 6.13 - Describe what occurs microscopically when a...Ch. 6.13 - When a cold-worked metal is heated into the...Ch. 6.13 - Prob. 33KCPCh. 6.13 - Prob. 34KCPCh. 6.13 - Prob. 35KCPCh. 6.13 - Prob. 36KCPCh. 6.13 - Prob. 37KCPCh. 6.13 - Why are nanocrystalline materials stronger? Answer...Ch. 6.13 - A 70% Cu30% Zn brass sheet is 0.0955 cm thick and...Ch. 6.13 - A sheet of aluminum alloy is cold-rolled 30% to a...Ch. 6.13 - Calculate the percent cold reduction when an...Ch. 6.13 - Prob. 42AAPCh. 6.13 - What is the relationship between engineering...Ch. 6.13 - A tensile specimen of cartridge brass sheet has a...Ch. 6.13 - A 0.505-in.-diameter rod of an aluminum alloy is...Ch. 6.13 - In Figure 6.23, estimate the toughness of SAE 1340...Ch. 6.13 - The following engineering stress-strain data were...Ch. 6.13 - Prob. 49AAPCh. 6.13 - A 0.505-in.-diameter aluminum alloy test bar is...Ch. 6.13 - A 20-cm-long rod with a diameter of 0.250 cm is...Ch. 6.13 - Prob. 52AAPCh. 6.13 - Prob. 53AAPCh. 6.13 - Prob. 54AAPCh. 6.13 - Prob. 55AAPCh. 6.13 - Prob. 56AAPCh. 6.13 - A specimen of commercially pure titanium has a...Ch. 6.13 - Prob. 58AAPCh. 6.13 - Prob. 59AAPCh. 6.13 - Prob. 60AAPCh. 6.13 - Prob. 61AAPCh. 6.13 - Prob. 62AAPCh. 6.13 - Prob. 63AAPCh. 6.13 - Prob. 64AAPCh. 6.13 - Prob. 65SEPCh. 6.13 - Prob. 66SEPCh. 6.13 - A 20-mm-diameter, 350-mm-long rod made of an...Ch. 6.13 - Prob. 68SEPCh. 6.13 - Prob. 69SEPCh. 6.13 - Consider casting a cube and a sphere on the same...Ch. 6.13 - When manufacturing complex shapes using cold...Ch. 6.13 - Prob. 74SEPCh. 6.13 - Draw a generic engineering stress-strain diagram...Ch. 6.13 - (a) Draw a generic engineering stress-strain...Ch. 6.13 - Prob. 77SEPCh. 6.13 - Prob. 78SEPCh. 6.13 - Prob. 79SEPCh. 6.13 - The material for a rod of cross-sectional area...Ch. 6.13 - What do E, G, v, Ur, and toughness tell you about...Ch. 6.13 - A cylindrical component is loaded in tension until...Ch. 6.13 - Referring to Figures 6.20 and 6.21 (read the...Ch. 6.13 - (a) Show, using the definition of the Poissons...Ch. 6.13 - A one-inch cube of tempered stainless steel (alloy...Ch. 6.13 - Prob. 87SEPCh. 6.13 - Prob. 88SEPCh. 6.13 - Prob. 89SEPCh. 6.13 - Prob. 90SEPCh. 6.13 - Prob. 91SEPCh. 6.13 - Prob. 92SEPCh. 6.13 - Prob. 93SEPCh. 6.13 - Prob. 94SEPCh. 6.13 - Starting with a 2-in.-diameter rod of brass, we...Ch. 6.13 - Prob. 96SEPCh. 6.13 - Prob. 97SEPCh. 6.13 - Prob. 98SEPCh. 6.13 - The cupro-nickel substitutional solid solution...Ch. 6.13 - Prob. 100SEP
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- A 20 foot long x 4 feet wide x ½ inch thick sheet of an aluminum alloy is cold rolled to a thickness of ¼ inch. During the rolling operation the with of the sheet increases by 10%. The strength coefficient (K) and the strain hardening coefficient (n ) for the aluminum alloy are 25,500 psi and 0.3, respectively Calculate the true strain at the end of the rolling process.arrow_forwardIllustrate the advantages of direct extrusion on indirect extrusion?arrow_forwardA cylindrical specimen of a cold-worked brass has a ductility (%EL) of 21%. If its cold-worked radius is 14 mm, what was its radius before deformation?arrow_forward
- The tensile strength for cold-rolled magnesium alloy AZ31B plate is approximately 160 MPa for specimens tested either parallel or perpendicular to the rolling direction. When similarly oriented specimens are compressed, the yield strength is only 90 MPa. Why? (Hint: Consider the possible deformation mechanisms available in the magnesium alloy and any crystallographic texture that might exist in the wrought plate.)arrow_forwardA cylindrical brass rod with a minimum tensile strength of 450 MPa, a ductility of at least 13% EL (elongation), and a final diameter of 12.7mm is required. You have in your inventory some 19.0mm diameter brass stock that has been cold worked to 35%. Assuming that the cross section of the rod is still circular after being cold worked, and that brass experiences cracking at 65% CW, describe the necessary working steps in order to achieve the final product. Take the expression for % cold work to be = (Ao - Af)/ Ao x 100%, where Ao and Af are the original and final circular cross-sectional areas of the rod.arrow_forwardExplain how do the cold work processes, such as extrusion or rolling, increase the strength of the single-phase metals? Mention the underlying mechanism in detailsarrow_forward
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