BIOL:CONCEPT+INVEST.ETEXT
5th Edition
ISBN: 9781264154173
Author: Hoefnagels
Publisher: MCG
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Question
Chapter 6.6, Problem 1MC
Summary Introduction
To explain:
How to arrive at the estimate that each glucose molecule theoretically yields 36 ATPs.
Concept introduction:
The
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For each of the four possibilities listed below (a through d), only one answer is correct and the others are false. Identify the correct statement and explain why the others are false. In your answer, write CORRECT next to the statement that you think is true, and ONLY for the ones that you think are false, explain what is wrong with the statement .
When glucose reacts with ATP to form glucose-6-phosphate (as shown on the figure below):
1. The synthesis of glucose-6-phosphate is exergonic
2. ADP is at a higher energy level than ATP
3. Glucose-6-phosphate is at a higher energy level than glucose
4. Because ATP donates a phosphate to glucose, this is not a coupled reaction
Consider ten glucose molecules that enter a cell. How many ATP can be generated by the complete catabolism of these into CO2 and H2O? If all ten are first incorporated into glycogen, liberated from glycogen, and then fully catabolized into CO2 and H2O, does the ATP tally increase, decrease or stay the same? Consider that 1 UTP = 1 ATP. Explain. Describe the processes which produce ATP and provide a balanced equation of glucose, CO2, H2O and O2
If 100% of the free energy from the metabolism of glucose is used for the conversion of ADP to ATP, how manymolecules of ATP can be produced from each gram of glucose (mm = 180.16)?
Chapter 6 Solutions
BIOL:CONCEPT+INVEST.ETEXT
Ch. 6.1 - Why do all organisms need ATP?Ch. 6.1 - What are the three general ways to generate ATP...Ch. 6.1 - Prob. 3MCCh. 6.1 - Prob. 4MCCh. 6.2 - Prob. 1MCCh. 6.2 - What occurs in each of the three stages of...Ch. 6.3 - Prob. 1MCCh. 6.3 - Prob. 2MCCh. 6.4 - Prob. 1MCCh. 6.4 - Prob. 2MC
Ch. 6.4 - Prob. 3MCCh. 6.5 - Prob. 1MCCh. 6.5 - Prob. 2MCCh. 6.5 - Prob. 3MCCh. 6.5 - Prob. 4MCCh. 6.6 - Prob. 1MCCh. 6.6 - How does the actual ATP yield compare to the...Ch. 6.7 - Prob. 1MCCh. 6.7 - Prob. 2MCCh. 6.8 - Prob. 1MCCh. 6.8 - Prob. 2MCCh. 6.8 - Prob. 3MCCh. 6.9 - Prob. 1MCCh. 6.9 - Why must the first metabolic pathways have been...Ch. 6.9 - What is the evidence that photosynthesis may have...Ch. 6.10 - What hypothesis were the researchers testing, and...Ch. 6.10 - Prob. 2MCCh. 6 - Which of the following best describes aerobic...Ch. 6 - Which stage in cellular respiration produces the...Ch. 6 - What is the role of ATP synthase? a. It uses ATP...Ch. 6 - Prob. 4MCQCh. 6 - Prob. 5MCQCh. 6 - What is endosymbiosis? a. A type of fermentation...Ch. 6 - Respiration contains the Latin word root spiro,...Ch. 6 - All steps of cellular respiration are closely...Ch. 6 - How might a mitochondrion's double membrane make...Ch. 6 - Health-food stores sell a product called pyruvate...Ch. 6 - At what point does O2 enter the energy pathways of...Ch. 6 - Describe the energy pathways that are available...Ch. 6 - Prob. 7WIOCh. 6 - Describe how aerobic respiration occurs in...Ch. 6 - Prob. 9WIOCh. 6 - Explain the fact that species as diverse as humans...Ch. 6 - Prob. 11WIOCh. 6 - Prob. 1PITCh. 6 - Prob. 2PITCh. 6 - Prob. 3PITCh. 6 - Where would fermentation, anaerobic respiration,...
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- Twenty-three milligrams of glucose were eaten by the bacteria Sanacoccus pumasareus. Calculate the hypothetical amount of ATP your patient can generate under aerobic respiration with this amount of glucose. (Note: Glucose MW-180.16 g/mole; 1 mole= 6.02 x 1023 molecules (Avogadro's number)). 2.8 x 10^24 ATPs 02.9 x 10^21 ATPs 028 x 10-21 ATP5 029 x 10 24 ATPS Lacks information, cannot be determinedarrow_forwardIf the DGo for ATP hydrolysis into ADP + inorganic phosphate is -7.3 kcal/mole, and the DGo for sucrose synthesis from glucose + fructose is +5.5 kcal/mole, calculate standard free energy change for the combined reaction of ATP + glucose + fructose g ADP + sucrose + inorganic phosphate. DGo = -12.8 kcal/mole DGo = -1.8 kcal/mole DGo = 0 kcal/mole DGo = +1.8 kcal/mole DGo = +12.8 kcal/molearrow_forwardTwenty-three milligrams of glucose were eaten by the bacteria Sanacoccus pumasareus. Calculate the hypothetical amount of ATP your patient can generate under fermentative metabolism with this amount of glucose. (Note: Glucose MW-180.16 g/mole; 1 mole= 6.02 x 1023 molecules (Avogadro's number)). O2.8 x 10^21 ATPs 01.5 x 10 20 ATPs 01.5 x 10^21 ATPs O2.8 x 10^20 ATPs O No ATP produced since it's fermentation O Lacks information, cannot be determined Nexte Previousarrow_forward
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