Chapter 7, Problem 40A

Interpretation Introduction

Interpretation:

The balanced chemical equation for the given process needs to be determined.

Concept Introduction:

In the chemical reaction; reactant written to the left side whereas product written to the right side. Reactant takes part in the chemical reaction whereas product produced after the reaction is occurring.

Answer to Problem 40A

The balanced chemical equation is shown below:

  $\text{CO}\left(\text{g}\right)\text{+}{\text{2H}}_{\text{2}}\left(\text{g}\right)\to {\text{CH}}_{\text{3}}\text{OH}\left(\text{l}\right)$

Explanation of Solution

The steps for balancing the chemical react ion are shown below:

Step 1:

Identify the reactants and products of the chemical reaction are shown below:

Gaseous carbon monoxide (CO (g)) and gaseous hydrogen (H₂(g)) present at the reactant side.

Liquid methanol (CH₃OH (l)) present at the product side.

Step 2:

The unbalanced equation is shown below:

  $\text{CO}\left(\text{g}\right)\text{+}{\text{H}}_{\text{2}}\left(\text{g}\right)\to {\text{CH}}_{\text{3}}\text{OH}\left(\text{l}\right)$

Step 3:

In the reactant side; there are two hydrogen atoms present whereas in the product side there are four hydrogen atoms. To balance the hydrogen atom multiply hydrogen atom by two to the reactant side as shown below:

  $\text{CO}\left(\text{g}\right)\text{+}{\text{2H}}_{\text{2}}\left(\text{g}\right)\to {\text{CH}}_{\text{3}}\text{OH}\left(\text{l}\right)$

Step 4:

There are 1C, 1O and 4H atoms on both the sides of the reaction. Therefore, the balanced reaction is shown below:

  $\text{CO}\left(\text{g}\right)\text{+}{\text{2H}}_{\text{2}}\left(\text{g}\right)\to {\text{CH}}_{\text{3}}\text{OH}\left(\text{l}\right)$

Conclusion

The balanced chemical equation is shown below:

  $\text{CO}\left(\text{g}\right)\text{+}{\text{2H}}_{\text{2}}\left(\text{g}\right)\to {\text{CH}}_{\text{3}}\text{OH}\left(\text{l}\right)$