Chapter 7, Problem 7.133MP

(a)

Interpretation Introduction

Interpretation:

The give two redox equations are should be balanced.

Concept Introduction:

Redox:

The reduction and oxidation reactions are occur simultaneously with in a single reaction is known as redox reaction.

Balancing of redox reaction:

The unbalanced charge (electron) and atoms (ions) in the equation of redox reactions are commonly balanced by half reaction method.

In this method, the given redox reaction is separated by two half reactions, one is oxidation and another one is reduction.

The medium of the reaction is used to balance the Hydrogen and Oxygen atoms in the half cell reactions.

Balancing of redox reaction in acid medium:

In the acid medium, the addition of ${\text{H}}^{+}$ ion to balance the Hydrogen and Water is added to balance the Oxygen atom.

Charge is balanced by addition of electron in the sides with the greater positive charge.

(b)

Interpretation Introduction

Interpretation:

The mass percent of ${\text{NO}}_{\text{2}}{}^{\text{-}}$ ion in given sample should be calculated.

Concept Introduction:

Redox reaction:

The reduction and oxidation reactions are occur simultaneously with in a single reaction is known as redox reaction.

Balancing of redox reaction:

The unbalanced charge (electron) and atoms (ions) in the equation of redox reactions are commonly balanced by half reaction method.

In this method, the given redox reaction is separated by two half reactions, one is oxidation and another one is reduction.

The medium of the reaction is used to balance the Hydrogen and Oxygen atoms in the half cell reactions.

Balancing of redox reaction in acid medium:

In the acid medium, the addition of ${\text{H}}^{+}$ ion to balance the Hydrogen and Water is added to balance the Oxygen atom.

Charge is balanced by addition of electron in the sides with the greater positive charge.

Mole:

Mole of solute in solute is given by below equating,

$\text{Mole}\text{solute}\text{=}\text{Molarity}\times \text{Liters}\text{of}\text{solution}$

Mass:

Mass of solid substance from mole is given by,

$\text{Mass}\text{=}\text{Mole}\text{×}\text{Molar}\text{mass}$

Mass percentage:

Percent mass of analyte present in the taken mass of sample is known as mass percentage.

$\text{\%}\text{mass}\text{=}\frac{\text{Mass}\text{of}\text{analyte}}{\text{Sample}\text{mass}}\text{×100}$