The result of decreasing the Kelvin temperature by a factor of 2 at constant pressure and moles of the gas through the given diagrams I to IV has to be described. Concept Introduction: Charles’s Law tells that the relationship between temperature and volume of a gas. The law states that at constant pressure the volume of a fixed amount of gas is directly proportional to the temperature in Kelvin units. The mathematical expression for the relationship between volume and Kelvin temperature according to the Charles’s law can be shown as follows, V 1 T 1 = V 2 T 2 Where, V 1 = T h e v o l u m e o f a g a s a t a g i v e n p r e s s u r e . T 1 = T h e K e l v i n t e m p e r a t u r e o f t h e g a s . V 2 = T h e v o l u m e o f t h e g a s u n d e r a n e w s e t o f c o n d i t i o n s . T 2 = T h e K e l v i n t e m p e r a t u r e o f t h e g a s u n d e r a n e w s e t o f c o n d i t i o n s .

Question

Calculate pressure using Dalton's law of partial pressures. A gas mixture is made up of N2 (6.91 g), 02 (7.95 g), and H2 (0.850 g). The mixture has a volume of 27.1 L at 27 °C. Calculate the partial pressure of each gas in the mixture and the total pressure of the gas mixture. PN2 = P02 PH = H2 = Ptotal atm atm atm atm

Answer 1

Question

Chapter 7, Problem 7.31EP

Interpretation Introduction

Interpretation:

The result of decreasing the Kelvin temperature by a factor of 2 at constant pressure and moles of the gas through the given diagrams I to IV has to be described.

Concept Introduction:

Charles’s Law tells that the relationship between temperature and volume of a gas. The law states that at constant pressure the volume of a fixed amount of gas is directly proportional to the temperature in Kelvin units. The mathematical expression for the relationship between volume and Kelvin temperature according to the Charles’s law can be shown as follows,

V1T1=V2T2

Where,

V1 = The volume of a gas at a given pressure.T1 = The Kelvin temperature of the gas.V2 = The volume of the gas under a new set of conditions.T2 = The Kelvin temperature of the gas under a new set of conditions.

Expert Solution & Answer

Trending nowThis is a popular solution!

See solution

Check out sample textbook solution

Students have asked these similar questions

Calculate pressure using Dalton's law of partial pressures. A gas mixture is made up of N2 (6.91 g), 02 (7.95 g), and H2 (0.850 g). The mixture has a volume of 27.1 L at 27 °C. Calculate the partial pressure of each gas in the mixture and the total pressure of the gas mixture. PN2 = P02 PH = H2 = Ptotal atm atm atm atm

Determine and report the pressure of collected hydrogen gas in atmospheres. Report this result to one more digit than allowed by applying the rules of significant figures. (1 atm = 760 mm Hg, an exact conversion factor.) Determine the moles of hydrogen collected by substituting the appropriate quantities into the ideal gas equation and solving. Report this result to one more digit than allowed by applying the rules of significant figures. Notes: the gas temperature is the same as the listed temperature; R = 0.082057 L-atm/mol-K. Be mindful of units. Determine the experimental atomic mass of Cu. Round this result to the correct number of significant figures. Determine the percent relative error (= ????????????−?h????????? ? 100). The molar mass of Cu is 63.546 g/mol. Mass of copper before electrolysis 6.008 g Mass of copper after electrolysis 5.860 g Volume of H2 collected 58.9 mL Pressure of H2, PH2 720.8 mm Hg Temperature 24.0 oC

A sample of nitrogen gas occupies a volume of 2.00 L at 756 mm Hg and 0.00° C. Thevolume increases by 2.00 L and the temperature decreases to 137 K. What is the finalpressure exerted on the gas?