PRACTICE OF STATISTICS F/AP EXAM
PRACTICE OF STATISTICS F/AP EXAM
6th Edition
ISBN: 9781319113339
Author: Starnes
Publisher: MAC HIGHER
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Chapter 7.3, Problem 65E

(a)

To determine

To Calculate: the probability that the mean loss from fire is greater than $300 for an SRS of 1000 homeowners.

(a)

Expert Solution
Check Mark

Answer to Problem 65E

37.45%

Explanation of Solution

Given:

  μ=250σ=5000n=1000x¯=300

Formula used:

  z=xμx¯σx¯

Calculation:

Since the population distribution is normal, the sampling distribution of the sample mean x¯ is also normal.

The Z-score is

  z=xμx¯σx¯=x¯μσ/n=3002505000/1000=0.32

The associating probability using the normal probability

  P(Z<0.32) is given in the row starting with 0.3 and in the column starting with 0.2 of the standard normal probability

  P(X¯300)=P(Z>0.32)=1P(Z<0.32)=10.6255=0.3745=37.45%

(b)

To determine

To find: the company charge.

(b)

Expert Solution
Check Mark

Answer to Problem 65E

$452.39

Explanation of Solution

Given:

  μ=250σ=5000n=1000P(X¯x¯)=90%

Formula used:

  z=xμx¯σx¯

Calculation:

Finding the z-score that associates with a probability of 90% or 0.90 in the normal probability and it is observed that the closest probability is 0.8997 which lies in the row 1.2 and in the column .08 of the normal probability table and therefore the corresponding z-score is then 1.2+.08=1.28

  z=1.28

The z-score is

  z=xμx¯σx¯=x¯μσ/n=x¯2505000/1000

The two found expressions of the z-score than have to be equal:

  x¯2505000/1000=1.28

  x¯250=1.28(5000/1000)

Add 250 to each side:

  x¯250+1.28(5000/1000)

Evaluate:

  x=452.39

Therefore the company should charge $ 452.39 .

Chapter 7 Solutions

PRACTICE OF STATISTICS F/AP EXAM

Ch. 7.1 - Prob. 11ECh. 7.1 - Prob. 12ECh. 7.1 - Prob. 13ECh. 7.1 - Prob. 14ECh. 7.1 - Prob. 15ECh. 7.1 - Prob. 16ECh. 7.1 - Prob. 17ECh. 7.1 - Prob. 18ECh. 7.1 - Prob. 19ECh. 7.1 - Prob. 20ECh. 7.1 - Prob. 21ECh. 7.1 - Prob. 22ECh. 7.1 - Prob. 23ECh. 7.1 - Prob. 24ECh. 7.1 - Prob. 25ECh. 7.1 - Prob. 26ECh. 7.1 - Prob. 27ECh. 7.1 - Prob. 28ECh. 7.1 - Prob. 29ECh. 7.1 - Prob. 30ECh. 7.1 - Prob. 31ECh. 7.1 - Prob. 32ECh. 7.2 - Prob. 33ECh. 7.2 - Prob. 34ECh. 7.2 - Prob. 35ECh. 7.2 - Prob. 36ECh. 7.2 - Prob. 37ECh. 7.2 - Prob. 38ECh. 7.2 - Prob. 39ECh. 7.2 - Prob. 40ECh. 7.2 - Prob. 41ECh. 7.2 - Prob. 42ECh. 7.2 - Prob. 43ECh. 7.2 - Prob. 44ECh. 7.2 - Prob. 45ECh. 7.2 - Prob. 46ECh. 7.2 - Prob. 47ECh. 7.2 - Prob. 48ECh. 7.2 - Prob. 49ECh. 7.2 - Prob. 50ECh. 7.2 - Prob. 51ECh. 7.2 - Prob. 52ECh. 7.3 - Prob. 53ECh. 7.3 - Prob. 54ECh. 7.3 - Prob. 55ECh. 7.3 - Prob. 56ECh. 7.3 - Prob. 57ECh. 7.3 - Prob. 58ECh. 7.3 - Prob. 59ECh. 7.3 - Prob. 60ECh. 7.3 - Prob. 61ECh. 7.3 - Prob. 62ECh. 7.3 - Prob. 63ECh. 7.3 - Prob. 64ECh. 7.3 - Prob. 65ECh. 7.3 - Prob. 66ECh. 7.3 - Prob. 67ECh. 7.3 - Prob. 68ECh. 7.3 - Prob. 69ECh. 7.3 - Prob. 70ECh. 7.3 - Prob. 71ECh. 7.3 - Prob. 72ECh. 7.3 - Prob. 73ECh. 7.3 - Prob. 74ECh. 7.3 - Prob. 75ECh. 7.3 - Prob. 76ECh. 7.3 - Prob. 77ECh. 7.3 - Prob. 78ECh. 7 - Prob. R7.1RECh. 7 - Prob. R7.2RECh. 7 - Prob. R7.3RECh. 7 - Prob. R7.4RECh. 7 - Prob. R7.5RECh. 7 - Prob. R7.6RECh. 7 - Prob. R7.7RECh. 7 - Prob. T7.1SPTCh. 7 - Prob. T7.2SPTCh. 7 - Prob. T7.3SPTCh. 7 - Prob. T7.4SPTCh. 7 - Prob. T7.5SPTCh. 7 - Prob. T7.6SPTCh. 7 - Prob. T7.7SPTCh. 7 - Prob. T7.8SPTCh. 7 - Prob. T7.9SPTCh. 7 - Prob. T7.10SPTCh. 7 - Prob. T7.11SPTCh. 7 - Prob. T7.12SPTCh. 7 - Prob. T7.13SPTCh. 7 - Prob. AP2.1CPTCh. 7 - Prob. AP2.2CPTCh. 7 - Prob. AP2.3CPTCh. 7 - Prob. AP2.4CPTCh. 7 - Prob. AP2.5CPTCh. 7 - Prob. AP2.6CPTCh. 7 - Prob. AP2.7CPTCh. 7 - Prob. AP2.8CPTCh. 7 - Prob. AP2.9CPTCh. 7 - Prob. AP2.10CPTCh. 7 - Prob. AP2.11CPTCh. 7 - Prob. AP2.12CPTCh. 7 - Prob. AP2.13CPTCh. 7 - Prob. AP2.14CPTCh. 7 - Prob. AP2.15CPTCh. 7 - Prob. AP2.16CPTCh. 7 - Prob. AP2.17CPTCh. 7 - Prob. AP2.18CPTCh. 7 - Prob. AP2.19CPTCh. 7 - Prob. AP2.20CPTCh. 7 - Prob. AP2.21CPTCh. 7 - Prob. AP2.22CPTCh. 7 - Prob. AP2.23CPTCh. 7 - Prob. AP2.24CPTCh. 7 - Prob. AP2.25CPT
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