ORGANIC CHEMISTRY GGC>CUSTOM<-TEXT
ORGANIC CHEMISTRY GGC>CUSTOM<-TEXT
2nd Edition
ISBN: 9781119288510
Author: Klein
Publisher: WILEY
Question
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Chapter 8, Problem 65PP

 (a)

Interpretation Introduction

Interpretation:

For the each given descriptions the used compound are needed to be drawn.

Concept introduction:

In an elimination reaction, alkenes are formed when alkyl halides are treated with bases via eliminating one β-proton and one α-halo group of the alkyl halide. The double bond is located between α,β-carbons.

The product of the elimination reaction is depends upon the β-positions of alkyl halide. If the β-positions are identical and the products formed are also identical. If the β-positions are different and the products formed are also different. This means the double bond can form in two different regions, so it will give different alkene products.

If there are two different β-protons at a β-position of alkyl halide, then on the basis of stereoselectivity, cis,tran-sisomers are possible.

To draw: the alkyl halide fitted for given descriptions.

(b)

Interpretation Introduction

Interpretation:

For the each given descriptions the used compound are needed to be drawn.

Concept introduction:

In an elimination reaction, alkenes are formed when alkyl halides are treated with bases via eliminating one β-proton and one α-halo group of the alkyl halide. The double bond is located between α,β-carbons.

The product of the elimination reaction is depends upon the β-positions of alkyl halide. If the β-positions are identical and the products formed are also identical. If the β-positions are different and the products formed are also different. This means the double bond can form in two different regions, so it will give different alkene products.

If there are two different β-protons at a β-position of alkyl halide, then on the basis of stereoselectivity, cis,tran-sisomers are possible.

To draw: the alkyl halide fitted for given descriptions.

(c)

Interpretation Introduction

Interpretation:

For the each given descriptions the used compound are needed to be drawn.

Concept introduction:

In an elimination reaction, alkenes are formed when alkyl halides are treated with bases via eliminating one β-proton and one α-halo group of the alkyl halide. The double bond is located between α,β-carbons.

The product of the elimination reaction is depends upon the β-positions of alkyl halide. If the β-positions are identical and the products formed are also identical. If the β-positions are different and the products formed are also different. This means the double bond can form in two different regions, so it will give different alkene products.

If there are two different β-protons at a β-position of alkyl halide, then on the basis of stereoselectivity, cis,tran-sisomers are possible.

To draw: the alkyl halide fitted for given descriptions.

(d)

Interpretation Introduction

Interpretation:

For the each given descriptions the used compound are needed to be drawn.

Concept introduction:

In an elimination reaction, alkenes are formed when alkyl halides are treated with bases via eliminating one β-proton and one α-halo group of the alkyl halide. The double bond is located between α,β-carbons.

The product of the elimination reaction is depends upon the β-positions of alkyl halide. If the β-positions are identical and the products formed are also identical. If the β-positions are different and the products formed are also different. This means the double bond can form in two different regions, so it will give different alkene products.

If there are two different β-protons at a β-position of alkyl halide, then on the basis of stereoselectivity, cis,tran-sisomers are possible.

To draw: the alkyl halide fitted for given descriptions.

Blurred answer

Chapter 8 Solutions

ORGANIC CHEMISTRY GGC>CUSTOM<-TEXT

Ch. 8.5 - Prob. 8PTSCh. 8.6 - Prob. 4LTSCh. 8.6 - Prob. 9PTSCh. 8.6 - Prob. 10PTSCh. 8.6 - Prob. 11ATSCh. 8.6 - Prob. 12ATSCh. 8.7 - Prob. 13CCCh. 8.7 - Prob. 14CCCh. 8.7 - Prob. 5LTSCh. 8.7 - Prob. 15PTSCh. 8.7 - Prob. 16ATSCh. 8.7 - Prob. 17ATSCh. 8.7 - Prob. 6LTSCh. 8.7 - Prob. 18PTSCh. 8.7 - Prob. 19ATSCh. 8.7 - Prob. 20CCCh. 8.7 - Prob. 21CCCh. 8.8 - Prob. 7LTSCh. 8.8 - Prob. 22PTSCh. 8.8 - Prob. 23ATSCh. 8.8 - Prob. 24ATSCh. 8.8 - Prob. 25ATSCh. 8.9 - Prob. 26CCCh. 8.9 - Prob. 27CCCh. 8.9 - Prob. 28CCCh. 8.9 - Prob. 8LTSCh. 8.9 - Prob. 29PTSCh. 8.9 - Prob. 31CCCh. 8.10 - Prob. 32CCCh. 8.10 - Prob. 33CCCh. 8.10 - Prob. 9LTSCh. 8.10 - Prob. 34PTSCh. 8.10 - Prob. 35ATSCh. 8.10 - Prob. 36ATSCh. 8.11 - Prob. 37CCCh. 8.11 - Prob. 38CCCh. 8.12 - Prob. 10LTSCh. 8.13 - Prob. 11LTSCh. 8.14 - Prob. 12LTSCh. 8.14 - Prob. 46PTSCh. 8.14 - Prob. 48ATSCh. 8.14 - Prob. 49ATSCh. 8 - Prob. 50PPCh. 8 - Prob. 51PPCh. 8 - Prob. 52PPCh. 8 - Prob. 53PPCh. 8 - Prob. 54PPCh. 8 - Prob. 55PPCh. 8 - Prob. 56PPCh. 8 - Prob. 57PPCh. 8 - Prob. 58PPCh. 8 - Prob. 59PPCh. 8 - Prob. 60PPCh. 8 - Prob. 61PPCh. 8 - Prob. 62PPCh. 8 - Prob. 63PPCh. 8 - Prob. 64PPCh. 8 - Prob. 65PPCh. 8 - Prob. 66PPCh. 8 - Prob. 67PPCh. 8 - Prob. 68PPCh. 8 - Prob. 69PPCh. 8 - Prob. 70PPCh. 8 - Prob. 71PPCh. 8 - Prob. 72PPCh. 8 - Prob. 73PPCh. 8 - Prob. 74PPCh. 8 - Prob. 75PPCh. 8 - Prob. 76PPCh. 8 - Prob. 77IPCh. 8 - Prob. 78IPCh. 8 - Prob. 79IPCh. 8 - Prob. 80IPCh. 8 - Prob. 81IPCh. 8 - Prob. 82IPCh. 8 - Prob. 83IPCh. 8 - Prob. 84IPCh. 8 - Prob. 85IPCh. 8 - Prob. 86IPCh. 8 - Prob. 87IP
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