The wavelength of sodium atom at high -temperature source is 1139 nm and the transition of atoms occurs from 4s to 3p state. The ratio of excited state 4s to the ground state 3s for sodium atom is to be calculated the range of temperature of acetylene-oxygen flame of 3000 ? and at an inductively coupled plasma source of 8750 ?. Concept introduction: Boltzmann equation is used for the calculation of the ratio. This equation tells that how much an atom or ion is populated as a function of temperature. This equation is given as- N j N o = g j g o exp ( − E j k T ) ......(1) And the calculation of energy of atom and ion is done by the following formula- E j = h c λ ......(2) Where, h= Planck’s constant c = light velocity λ= wavelength Ej= energy difference of excited state and ground state

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Principles of Instrumental Analysis

7th Edition
Douglas A. Skoog + 2 others
Publisher: Cengage Learning
ISBN: 9781305577213
BuyFind

Principles of Instrumental Analysis

7th Edition
Douglas A. Skoog + 2 others
Publisher: Cengage Learning
ISBN: 9781305577213

Solutions

Chapter 8, Problem 8.10QAP
Interpretation Introduction

Interpretation:

The wavelength of sodium atom at high -temperature source is 1139 nm and the transition of atoms occurs from 4s to 3p state. The ratio of excited state 4s to the ground state 3s for sodium atom is to be calculated the range of temperature of acetylene-oxygen flame of 3000 ? and at an inductively coupled plasma source of 8750 ?.

Concept introduction:

Boltzmann equation is used for the calculation of the ratio. This equation tells that how much an atom or ion is populated as a function of temperature. This equation is given as-

NjNo=gjgoexp(EjkT)    ......(1)

And the calculation of energy of atom and ion is done by the following formula-

Ej=hcλ    ......(2)

Where,

h= Planck’s constant

c = light velocity

λ= wavelength

Ej= energy difference of excited state and ground state

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