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ChemistryPrinciples of Instrumental AnalysisThe wavelength of sodium atom at high -temperature source is 1139 nm and the transition of atoms occurs from 4s to 3p state. The ratio of excited state 4s to the ground state 3s for sodium atom is to be calculated the range of temperature of acetylene-oxygen flame of 3000 ? and at an inductively coupled plasma source of 8750 ?. Concept introduction: Boltzmann equation is used for the calculation of the ratio. This equation tells that how much an atom or ion is populated as a function of temperature. This equation is given as- N j N o = g j g o exp ( − E j k T ) ......(1) And the calculation of energy of atom and ion is done by the following formula- E j = h c λ ......(2) Where, h= Planck’s constant c = light velocity λ= wavelength Ej= energy difference of excited state and ground stateStart your trial now! First week only $4.99!*arrow_forward*

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7th Edition

Douglas A. Skoog + 2 others

Publisher: Cengage Learning

ISBN: 9781305577213

Chapter 8, Problem 8.10QAP

Interpretation Introduction

**Interpretation:**

The wavelength of sodium atom at high -temperature source is 1139 nm and the transition of atoms occurs from 4s to 3p state. The ratio of excited state 4s to the ground state 3s for sodium atom is to be calculated the range of temperature of acetylene-oxygen flame of 3000 ? and at an inductively coupled plasma source of 8750 ?.

**Concept introduction:**

Boltzmann equation is used for the calculation of the ratio. This equation tells that how much an atom or ion is populated as a function of temperature. This equation is given as-

And the calculation of energy of atom and ion is done by the following formula-

Where,

h= Planck’s constant

c = light velocity

λ= wavelength

Ej= energy difference of excited state and ground state