‘Mo diagram’ should be identified. Concept introduction: Molecular orbital of a compound can be find out by knowing the electronic configuration of individual element. Electronic configuration of S = 1 S 2 2 S 2 2 S 6 3 S 2 3 S 4 = [ N e ] 3 S 2 3 P 4 . Greater the bond order, shorter will be its bond length.

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Answer 1

Question

Chapter 8, Problem 8.115CP

Interpretation Introduction

Interpretation:

‘Mo diagram’ should be identified.

Concept introduction:

Molecular orbital of a compound can be find out by knowing the electronic configuration of individual element.

Electronic configuration of S=1S22S22S63S23S4=[Ne]3S23P4.

Greater the bond order, shorter will be its bond length.

Interpretation Introduction

(b) To determine:

Is S2 likely to be paramagnetic or diamagnetic

Interpretation Introduction

(c) To determine:

The bond order of S2

(g) ?

Interpretation Introduction

(d) To determine:

When two electrons are added to S2, the disulfide ion S2−2 is formed is the bond length in S2−2 likely to be shorter or longer than the bond length in S2 ?

Expert Solution & Answer

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Answer 2

Question

Chapter 8, Problem 8.115CP

Interpretation Introduction

Interpretation:

‘Mo diagram’ should be identified.

Concept introduction:

Molecular orbital of a compound can be find out by knowing the electronic configuration of individual element.

Electronic configuration of S=1S22S22S63S23S4=[Ne]3S23P4.

Greater the bond order, shorter will be its bond length.

Interpretation Introduction

(b) To determine:

Is S2 likely to be paramagnetic or diamagnetic

Interpretation Introduction

(c) To determine:

The bond order of S2

(g) ?

Interpretation Introduction

(d) To determine:

When two electrons are added to S2, the disulfide ion S2−2 is formed is the bond length in S2−2 likely to be shorter or longer than the bond length in S2 ?

Expert Solution & Answer

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See solution

Answer 3

Question

Chapter 8, Problem 8.115CP

Interpretation Introduction

Interpretation:

‘Mo diagram’ should be identified.

Concept introduction:

Molecular orbital of a compound can be find out by knowing the electronic configuration of individual element.

Electronic configuration of S=1S22S22S63S23S4=[Ne]3S23P4.

Greater the bond order, shorter will be its bond length.

Interpretation Introduction

(b) To determine:

Is S2 likely to be paramagnetic or diamagnetic

Interpretation Introduction

(c) To determine:

The bond order of S2

(g) ?

Interpretation Introduction

(d) To determine:

When two electrons are added to S2, the disulfide ion S2−2 is formed is the bond length in S2−2 likely to be shorter or longer than the bond length in S2 ?

Expert Solution & Answer

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See solution

Answer 4

Question

Chapter 8, Problem 8.115CP

Interpretation Introduction

Interpretation:

‘Mo diagram’ should be identified.

Concept introduction:

Molecular orbital of a compound can be find out by knowing the electronic configuration of individual element.

Electronic configuration of S=1S22S22S63S23S4=[Ne]3S23P4.

Greater the bond order, shorter will be its bond length.

Interpretation Introduction

(b) To determine:

Is S2 likely to be paramagnetic or diamagnetic

Interpretation Introduction

(c) To determine:

The bond order of S2

(g) ?

Interpretation Introduction

(d) To determine:

When two electrons are added to S2, the disulfide ion S2−2 is formed is the bond length in S2−2 likely to be shorter or longer than the bond length in S2 ?

Expert Solution & Answer

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See solution

Answer 5

Chapter 8, Problem 8.115CP

Interpretation Introduction

Interpretation:

‘Mo diagram’ should be identified.

Concept introduction:

Molecular orbital of a compound can be find out by knowing the electronic configuration of individual element.

Electronic configuration of S=1S22S22S63S23S4=[Ne]3S23P4.

Greater the bond order, shorter will be its bond length.

Interpretation Introduction

(b) To determine:

Is S2 likely to be paramagnetic or diamagnetic

Interpretation Introduction

(c) To determine:

The bond order of S2

(g) ?

Interpretation Introduction

(d) To determine:

When two electrons are added to S2, the disulfide ion S2−2 is formed is the bond length in S2−2 likely to be shorter or longer than the bond length in S2 ?

Answer 6

Chapter 8, Problem 8.115CP

Interpretation Introduction

Interpretation:

‘Mo diagram’ should be identified.

Concept introduction:

Molecular orbital of a compound can be find out by knowing the electronic configuration of individual element.

Electronic configuration of S=1S22S22S63S23S4=[Ne]3S23P4.

Greater the bond order, shorter will be its bond length.

Answer 7

Chapter 8, Problem 8.115CP

Interpretation Introduction

Interpretation:

‘Mo diagram’ should be identified.

Concept introduction:

Molecular orbital of a compound can be find out by knowing the electronic configuration of individual element.

Electronic configuration of S=1S22S22S63S23S4=[Ne]3S23P4.

Greater the bond order, shorter will be its bond length.

Answer 8

Interpretation Introduction

(b) To determine:

Is S2 likely to be paramagnetic or diamagnetic

Answer 9

Interpretation Introduction

(b) To determine:

Is S2 likely to be paramagnetic or diamagnetic

Answer 10

Interpretation Introduction

(c) To determine:

The bond order of S2

(g) ?

Answer 11

Interpretation Introduction

(c) To determine:

The bond order of S2

(g) ?

Answer 12

Interpretation Introduction

(d) To determine:

When two electrons are added to S2, the disulfide ion S2−2 is formed is the bond length in S2−2 likely to be shorter or longer than the bond length in S2 ?

Answer 13

Interpretation Introduction

(d) To determine:

When two electrons are added to S2, the disulfide ion S2−2 is formed is the bond length in S2−2 likely to be shorter or longer than the bond length in S2 ?

Answer 14

Expert Solution & Answer

Answer 15

Expert Solution & Answer

Answer 16

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Answer 17

Ch. 8 - Prob. 8.1P Ch. 8 - Prob. 8.2A Ch. 8 - PRACTICE 8.3 Acetic acid, CH3CO2H , is the main...Ch. 8 - APPLY 8.4 Benzene, C6H6 , is a cyclic molecule in...Ch. 8 - PRACTICE 8.5 Identify the orbitals that overlap to...Ch. 8 - APPLY 8.6 Describe the bonding in propane, C3H8 ,...Ch. 8 - PRACTICE 8.7 Describe the hybridization of the...Ch. 8 - APPLY 8.8 Describe the hybridization of each...Ch. 8 - PRACTICE 8.9 Describe the hybridization of the...Ch. 8 - APPLY 8.10 Describe the hybridization of the...

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(b) To determine:

Is S2 likely to be paramagnetic or diamagnetic

(c) To determine:

The bond order of S2

(g) ?

(d) To determine:

When two electrons are added to S2, the disulfide ion S2−2 is formed is the bond length in S2−2 likely to be shorter or longer than the bond length in S2 ?

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Chapter 8 Solutions

Concept explainers

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(b) To determine: Is S2 likely to be paramagnetic or diamagnetic

(c) To determine: The bond order of S2 (g) ?

(d) To determine: When two electrons are added to S2, the disulfide ion S2−2 is formed is the bond length in S2−2 likely to be shorter or longer than the bond length in S2 ?

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Chapter 8 Solutions

(b) To determine:

Is S2 likely to be paramagnetic or diamagnetic

(c) To determine:

The bond order of S2

(g) ?

(d) To determine:

When two electrons are added to S2, the disulfide ion S2−2 is formed is the bond length in S2−2 likely to be shorter or longer than the bond length in S2 ?