Explanation Given info: α = 0.01 , x 1 = 110 ( = 11 % of 1 , 000 ) , n 1 = 1 , 000 , x 2 = 180 ( = 18 % of 1 , 000 ) , and n 2 = 1 , 000 Calculation: The hypotheses are given below: Null hypothesis: H 0 : p 1 ≥ p 2 Alternative hypothesis: H a : p 1 < p 2 Here, the test is one tailed test. Critical value: Step by step procedure to obtain the critical value using the MINITAB software: Choose Graph > Probability Distribution Plot choose View Probability > OK. From Distribution , choose ‘ Normal ’ distribution. Click the Shaded Area tab. Choose probability Value and Left Tail for the region of the curve to shade. Enter the probability value as 0.01 . Click OK . Output using the MINITAB software is given below:

Elementary Statistics: Picturing the World (7th Edition)

7th Edition

ISBN: 9780134683416

Author: Ron Larson, Betsy Farber

Publisher: PEARSON

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Chapter 8.4, Problem 17E

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To check: Whether the claim that the proportion of newlywed whites who have a spouse of a different race or ethnicity is less than the proportion of newlywed blacks who have a spouse of a different race or ethnicity is support or not.

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Chapter 8.4, Problem 16E

Chapter 8.4, Problem 18E

Chapter 8 Solutions

Elementary Statistics: Picturing the World (7th Edition)

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Population Genetics In the study of population genetics, an important measure of inbreeding is the proportion of homozygous genotypesthat is, instances in which the two alleles carried at a particular site on an individuals chromosomes are both the same. For population in which blood-related individual mate, them is a higher than expected frequency of homozygous individuals. Examples of such populations include endangered or rare species, selectively bred breeds, and isolated populations. in general. the frequency of homozygous children from mating of blood-related parents is greater than that for children from unrelated parents Measured over a large number of generations, the proportion of heterozygous genotypesthat is, nonhomozygous genotypeschanges by a constant factor 1 from generation to generation. The factor 1 is a number between 0 and 1. If 1=0.75, for example then the proportion of heterozygous individuals in the population decreases by 25 in each generation In this case, after 10 generations, the proportion of heterozygous individuals in the population decreases by 94.37, since 0.7510=0.0563, or 5.63. In other words, 94.37 of the population is homozygous. For specific types of matings, the proportion of heterozygous genotypes can be related to that of previous generations and is found from an equation. For mating between siblings 1 can be determined as the largest value of for which 2=12+14. This equation comes from carefully accounting for the genotypes for the present generation the 2 term in terms of those previous two generations represented by for the parents generation and by the constant term of the grandparents generation. a Find both solutions to the quadratic equation above and identify which is 1 use a horizontal span of 1 to 1 in this exercise and the following exercise. b After 5 generations, what proportion of the population will be homozygous? c After 20 generations, what proportion of the population will be homozygous?

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To check: Whether the claim that the proportion of newlywed whites who have a spouse of a different race or ethnicity is less than the proportion of newlywed blacks who have a spouse of a different race or ethnicity is support or not.

Solution Summary: The author explains that the proportion of newlywed whites who have a spouse of another race or ethnicity is less than that of blacks.

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To check: Whether the claim that the proportion of newlywed whites who have a spouse of a different race or ethnicity is less than the proportion of newlywed blacks who have a spouse of a different race or ethnicity is support or not.

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Chapter 8 Solutions