Chapter 8.5, Problem 50CCR

(a)

To determine

What decimal part, rounded to the nearest hundredth, of the annual tornadoes occurred in June for each year?

Answer to Problem 50CCR

Explanation of Solution

Given:

The table shows the number of tornadoes that occurred in Nebraska in June and the total number of tornadoes for selected years.

Annual Nebraska Tornadoes

Year	June	Total
2009	24	39
2006	8	22
2003	43	81
2000	21	61

What decimal part, rounded to the nearest hundredth, of the annual tornadoes occurred in June for each year?

Concept Used:

Calculation:

  $2009:\frac{39}{24}=1.625=1.63$ (Thousandth part rounded)

  $2006:\frac{22}{8}=2.75$ (It is already in hundredth, no need to rounded)

  $2003:\frac{81}{43}=1.883720=1.88$ (No need to round, cause the thousandth part is 3 less than 5)

  $2000:\frac{61}{21}=2.9047=2.90$ (No need to round, cause the thousandth part is 4 less than 5)

(b)

To determine

Find which years more than two fifths of the tornadoes occurred in June.

Answer to Problem 50CCR

In 2009 it is more than $\frac{2}{5}\text{of}$ total number of Tornadoes.

Explanation of Solution

Given:

The table shows the number of tornadoes that occurred in Nebraska in June and the total number of tornadoes for selected years.

Annual Nebraska Tornadoes

Year	June	Total
2009	24	39
2006	8	22
2003	43	81
2000	21	61

In which years did more than two fifths of the tornadoes occur in June?

Concept Used:

Find $\frac{2}{5}\text{of}$ each year separately.

Annual Nebraska Tornadoes

Year	June	Total
2009	24	39
2006	8	22
2003	43	81
2000	21	61

Calculation:

  $\begin{array}{l}2009:\frac{2}{5}\text{of}\text{39}\text{=}\text{15}\text{.6}\\ 2006:\frac{2}{5}\text{of}\text{22}=8.8\\ 2003:\frac{2}{5}\text{of}\text{81}=32.4\\ 2000:\frac{2}{5}\text{of}\text{61}=24.4\end{array}$

Thus, in 2009 it is more than $\frac{2}{5}\text{of}$ total number of Tornadoes.