Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
expand_more
expand_more
format_list_bulleted
Videos
Question
Chapter 9, Problem 111P
(a)
To determine
The acceleration of the center of the rod.
(b)
To determine
The initial acceleration of the free end of the rod.
(c)
To determine
The speed of center of mass when the rod is vertical.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
For solid ojbject whose mass distribution does not allow for a simple determination of the center of mass by symmetry, the sums must be generalized to integrals where x and y are the coordinates of a small piece of an object that has mass dm. The integration is over the whole of the object. Consider a thin rod of length L, mass M, and cross-sectional area A. Let the origin of the coordinates be at the left end of the rod and the positive x-axis lie along the rod.
a. If the density p = M/V of the object is uniform, perform the integration described above to show that the x-coordinate of the center of mass of the rod is at its geometrical center.
b. If the density of the object varies linearly with x - that is, p = ax, where a is a positive constant - calculate the x-coordinate of the rod's center of mass.
at the instant a 2 kg particle has a velocity of 4ms in the positive x-direction, a 3kg particle has a velocity of 5ms in the positive y-direction. what is the speed of the centre of mass of the two-particle system ?
Consider a system consisting of three objects: Object A with a mass of 2 kg located at position (1, 0), Object B with a mass of 3 kg located
at position (0, 2), and Object C with a mass of 1 kg located at position (-2, -1). What is the center of mass of this system?
Chapter 9 Solutions
Physics for Scientists and Engineers
Ch. 9 - Prob. 1PCh. 9 - Prob. 2PCh. 9 - Prob. 3PCh. 9 - Prob. 4PCh. 9 - Prob. 5PCh. 9 - Prob. 6PCh. 9 - Prob. 7PCh. 9 - Prob. 8PCh. 9 - Prob. 9PCh. 9 - Prob. 10P
Ch. 9 - Prob. 11PCh. 9 - Prob. 12PCh. 9 - Prob. 13PCh. 9 - Prob. 14PCh. 9 - Prob. 15PCh. 9 - Prob. 16PCh. 9 - Prob. 17PCh. 9 - Prob. 18PCh. 9 - Prob. 19PCh. 9 - Prob. 20PCh. 9 - Prob. 21PCh. 9 - Prob. 22PCh. 9 - Prob. 23PCh. 9 - Prob. 24PCh. 9 - Prob. 25PCh. 9 - Prob. 26PCh. 9 - Prob. 27PCh. 9 - Prob. 28PCh. 9 - Prob. 29PCh. 9 - Prob. 30PCh. 9 - Prob. 31PCh. 9 - Prob. 32PCh. 9 - Prob. 33PCh. 9 - Prob. 34PCh. 9 - Prob. 35PCh. 9 - Prob. 36PCh. 9 - Prob. 37PCh. 9 - Prob. 38PCh. 9 - Prob. 39PCh. 9 - Prob. 40PCh. 9 - Prob. 41PCh. 9 - Prob. 42PCh. 9 - Prob. 43PCh. 9 - Prob. 44PCh. 9 - Prob. 45PCh. 9 - Prob. 46PCh. 9 - Prob. 47PCh. 9 - Prob. 48PCh. 9 - Prob. 49PCh. 9 - Prob. 50PCh. 9 - Prob. 51PCh. 9 - Prob. 52PCh. 9 - Prob. 53PCh. 9 - Prob. 54PCh. 9 - Prob. 55PCh. 9 - Prob. 56PCh. 9 - Prob. 57PCh. 9 - Prob. 58PCh. 9 - Prob. 59PCh. 9 - Prob. 60PCh. 9 - Prob. 61PCh. 9 - Prob. 62PCh. 9 - Prob. 63PCh. 9 - Prob. 64PCh. 9 - Prob. 65PCh. 9 - Prob. 66PCh. 9 - Prob. 67PCh. 9 - Prob. 68PCh. 9 - Prob. 69PCh. 9 - Prob. 70PCh. 9 - Prob. 71PCh. 9 - Prob. 72PCh. 9 - Prob. 73PCh. 9 - Prob. 74PCh. 9 - Prob. 75PCh. 9 - Prob. 76PCh. 9 - Prob. 77PCh. 9 - Prob. 78PCh. 9 - Prob. 79PCh. 9 - Prob. 80PCh. 9 - Prob. 81PCh. 9 - Prob. 82PCh. 9 - Prob. 83PCh. 9 - Prob. 84PCh. 9 - Prob. 85PCh. 9 - Prob. 86PCh. 9 - Prob. 87PCh. 9 - Prob. 88PCh. 9 - Prob. 89PCh. 9 - Prob. 90PCh. 9 - Prob. 91PCh. 9 - Prob. 92PCh. 9 - Prob. 93PCh. 9 - Prob. 94PCh. 9 - Prob. 95PCh. 9 - Prob. 96PCh. 9 - Prob. 97PCh. 9 - Prob. 98PCh. 9 - Prob. 99PCh. 9 - Prob. 100PCh. 9 - Prob. 101PCh. 9 - Prob. 102PCh. 9 - Prob. 103PCh. 9 - Prob. 104PCh. 9 - Prob. 105PCh. 9 - Prob. 106PCh. 9 - Prob. 107PCh. 9 - Prob. 108PCh. 9 - Prob. 109PCh. 9 - Prob. 110PCh. 9 - Prob. 111PCh. 9 - Prob. 112PCh. 9 - Prob. 113PCh. 9 - Prob. 114PCh. 9 - Prob. 115PCh. 9 - Prob. 116PCh. 9 - Prob. 117PCh. 9 - Prob. 118PCh. 9 - Prob. 119PCh. 9 - Prob. 120PCh. 9 - Prob. 121PCh. 9 - Prob. 122PCh. 9 - Prob. 123PCh. 9 - Prob. 124PCh. 9 - Prob. 126PCh. 9 - Prob. 127PCh. 9 - Prob. 128PCh. 9 - Prob. 129P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- The centre of mass of a non-uniform rod of length 4 m whose mass per unit length is K = 3x kg/m, where xis in m. The distance of centre of mass from its one end which is at origin will bearrow_forwardThree masses, 1.0 kg, 2.0 kg, and 3.0 kg, are located at (0, 0), (1.0 m, 1.0 m), and (2.0 m, -2.0 m),respectively. What is the location of the center of mass of the system?arrow_forwardOne astronaut is 75kg, and another who is 3.4 m away in the x-direction is 85kg. How far from the first astronaut is their mutual center of mass? Do not actually solve the problem numerically or algebraically, just pick the one equation and define the relevant knowns and single unknown.arrow_forward
- A 68 kg man is in the prone position while during pushups. His feet and hands are 95 cm and 42 cm away respectively from his center of mass. What is the normal force exerted by on each (a) hand and (b) foot?arrow_forwardThree identical masses m are located at the three corners of an equilateral triangle with sides a in the xy-plane, with its base along the x-axis. Find their center of mass rCM and moments of inertia I with respect to (a) an axis through the center of mass parallel to the x-axis and (b) an axis through the center of mass parallel to the y-axis.arrow_forwardTRUE OR FALSE. For an object on the surface of the Earth, the center of gravity and center of mass are the same point.arrow_forward
- A door 1.00m wide of mass 15.0 kg, is hinged at one side so that it can rotate without friction about a vertical axis. It is unlatched. A police officer fires a bullet with a mass of 10.0g and a speed of 400m/s into the exact center of the door in a direction perpendicular to the door.(use: the moment of inertia of the rotating door at the hinge, Idoor =1/3Md2) a. What is the initial momentum of the system?b. What is the angular speed of the door just after the bullet embeds itself in the door?arrow_forwardA system consists of three masses connected by light (effectively massless) rigid rods. The first, m1 = 3.00 kg is at a distance of 2.75 m along the y axis. The second, m2 = 4.00 kg is at a distance of 2.50 m along the x axis. A final mass, m3 = 2.50 kg, is placed at (-4.00, -3.30) m and connected to m1 and m2 so that the resulting center of mass of the system is at the origin. The entire system rotates about the origin. A force with a constant magnitude of 2.9 N is applied leftwards on m1. And a force of 9.7 N is applied downwards on m2. What is the resultant angular acceleration of the system about the origin, if angular acceleration out of the page is considered positive?arrow_forwardConsider a flat rectangular plate of known mass, width and breadth with a negligible thickness that lies in the horizontal xy-plane. The plate is suspended from a thin piece of piano wire that is in the vertical orientation coincident to the z-axis and where the piano wire is attached to the center of the plate. When the plate is subjected to a torque whose vector is coincident to the z-axis, the plate rotates in the horizontal plane such that the rotation of the plate is modelled as θ=Csin(ωnt+ϕ). The parameter information is: mass of plate M = 1.2 kilogram width of plate W = 0.040 meter breadth of plate B = 0.075 meter shear modulus of piano wire G = 79.3 gigaPascals diameter of piano wire D = 0.003 meter length of piano wire L = 0.120 meter amplitude of rotation C = 0.087267520415 radian phase lag of rotation ϕ = 1.565872597159 radian Using the supplied information and any appropriate assumptions and / or approximations to determine the following; 1) the mass moment of inertia I 2)…arrow_forward
- Find the center of mass and the moments of inertia about the coordinate axes of a thin plate bounded by the line y = x and the parabola y = x2 in the xy-plane if the density is d(x, y) = x + 1.arrow_forwardA 4.73 kg particle has the xy coordinates (-1.50 m, 0.794 m), and a 5.13 kg particle has the xy coordinates (0.550 m, -0.965 m). Both lie on a horizontal plane. At what (a) x and (b) y coordinates must you place a 1.09 kg particle such that the center of mass of the three-particle system has the coordinates (-0.686 m, -0.458 m)?arrow_forward2.50 kg particle that is moving horizontally over a floor with velocity (-3.00 m/s)ˆj undergoes a completely inelastic collision with a 4.00 kg particle that is moving horizontally over the floor with velocity (4.50 m/s)iˆ. The collision occurs at xy coordinates (-0.500 m, -0.100 m). After the collision and in unit-vector notation, what is the angular momentum of the stuck-together particles with respect to the origin?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Classical Dynamics of Particles and SystemsPhysicsISBN:9780534408961Author:Stephen T. Thornton, Jerry B. MarionPublisher:Cengage Learning
Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Classical Dynamics of Particles and Systems
Physics
ISBN:9780534408961
Author:Stephen T. Thornton, Jerry B. Marion
Publisher:Cengage Learning
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Momentum | Forces & Motion | Physics | FuseSchool; Author: FuseSchool - Global Education;https://www.youtube.com/watch?v=DxKelGugDa8;License: Standard YouTube License, CC-BY