Explanation Given info: The potential difference is 40 kV Write an expression to calculate the wavelength of the signal. λ = h c e V Here, λ is the wavelength h is the Planck constant c is the speed of light e is the charge V is the potential difference Substitute 6.626 × 10 − 34 m 2 kg/s for h , 3.00 × 10 8 m/s for c , 1.602 × 10 − 19 C for e and 40 kV for V . λ = ( 6.626 × 10 − 34 m 2 kg/s ) ( 3

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Chapter 9, Problem 20E

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The shortest radiation from an x-ray machine.

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Chapter 9, Problem 19E

Chapter 9, Problem 21E

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The shortest radiation from an x-ray machine.

Solution Summary: The author explains that the shortest radiation from an x-ray machine is 3.11times 10-11m.

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The shortest radiation from an x-ray machine.

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