   # Greenhouse Gas Emissions For problem 45, calculate the number of grams of CO 2 emitted into the atmosphere. a. Use the balanced equation for the combustion of methane to determine how many grams of CO 2 would be produced from the amount of natural gas required. b. Assume that coal produces 5.25 kJ of energy per gram of CO 2 produced and calculate how many grams of carbon dioxide would be produced. ### Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692

#### Solutions

Chapter
Section ### Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692
Chapter 9, Problem 47E
Textbook Problem
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## Greenhouse Gas EmissionsFor problem 45, calculate the number of grams of CO 2 emitted into the atmosphere.a. Use the balanced equation for the combustion of methane to determine how many grams of CO 2 would be produced from the amount of natural gas required.b. Assume that coal produces 5.25 kJ of energy per gram of CO 2 produced and calculate how many grams of carbon dioxide would be produced.

Interpretation Introduction

Interpretation:

The number of grams of carbon dioxide produced is to be calculated.

Concept introduction:

The power derived from the utilization of chemical or physical resources to provide heat and light or to carry out various processes is known as energy. The SI unit of energy is joule.

Carbon dioxide is a colorless gas that consists of carbon atoms bonded with two oxygen atoms.

### Explanation of Solution

a) The number of grams of carbon dioxide produced from the combustion of methane using balance equation.

The balanced equation for the combustion of methane is as follows:

CH4+2O2Δ2H2O+CO2

This is the balanced equation for the combustion of methane. From the balanced equation of the reaction, it can be concluded that 1 mol of methane forms 1 mol of carbon dioxide.

The amount of methane gas is 130 g. (As calculated in problem 45).

The number of grams of carbon dioxide is calculated as follows:

m=(130 g of CH4)×(1 mol CH416.04 g CH4)×(1 mol CO21 mol CH4)×(44

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