Computer Systems: A Programmer's Perspective (3rd Edition)
Computer Systems: A Programmer's Perspective (3rd Edition)
3rd Edition
ISBN: 9780134092669
Author: Bryant, Randal E. Bryant, David R. O'Hallaron, David R., Randal E.; O'Hallaron, Bryant/O'hallaron
Publisher: PEARSON
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Chapter 9, Problem 9.13HW

Repeat Problem 9.11 for the following address.

Virtual address: 0x0040

Chapter 9, Problem 9.13HW, Repeat Problem 9.11 for the following address. Virtual address: 0x0040 A. Address translation , example  1

  1. A.    Address translation
  • Parameter
  • Value
VPN _____
TLB index _____
TLB tag _____
TLB hit? (Y/N) _____
Page fault? (Y/N) _____
PPN _____
  1. B.     Physical address format

Chapter 9, Problem 9.13HW, Repeat Problem 9.11 for the following address. Virtual address: 0x0040 A. Address translation , example  2

  1. C.     Physical memory reference
  • Parameter
  • Value
Byte offset _____
Cache index _____
Cache tag _____
Cache hit? (Y/N) _____
Cache byte returned _____
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Students have asked these similar questions
Suppose a computer system uses 16-bit addresses for both its virtual and physical addresses. In addition, assume each page (and frame) has size 256 bytes. Could you hand draw the page table, if possible a) Suppose that the OS uses a two-level page table. Draw the page table. (Assume that frames 7 through 221 are free, so you can allocate space for the page table there.) In addition, suppose that the page-table directory storage comprises a whole number of consecutive full frames. (For examples: if the directory entry is 2 bytes, the entry’s storage comprises 1 frame; if the directory entry is 260 bytes, the entry’s storage comprises 2 consecutive frames.)  b) What is the size of the two-level page table
Consider a memory-management system based on paging. The total size of the physical address space 64 MB, Pages of size 4 KB, the Logical address space of 4GB. total number of pages are 16384, total number of frames are 16384 and the number of entries in a page table are 1048576.Now Calculate: a)Size of Page Table b) No of bits in Physical Address c) No of Bits in Logical Address
CA_10 Let the virtual address be V bits and the virtual addtess space be byte-addressable, the page size be P KB (and P is a power of 2), and the the main memory size be MM MB(where [MM MB]) is divide into [P KB]). (d)How many of the virtual memory bits need to be translated? (e) How many bits will be produced if the virtual-to-pyysical address translation is "successful" (f) How many bits does a physical address have, and how are each of these bits obtained?

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Instruction Format (With reference to address); Author: ChiragBhalodia;https://www.youtube.com/watch?v=lNdy8HREvgo;License: Standard YouTube License, CC-BY