Vector Mechanics for Engineers: Statics, 11th Edition
Vector Mechanics for Engineers: Statics, 11th Edition
11th Edition
ISBN: 9780077687304
Author: Ferdinand P. Beer, E. Russell Johnston Jr., David Mazurek
Publisher: McGraw-Hill Education
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Chapter 9.1, Problem 9.20P
To determine

Find the moment of inertia (Iy) and radius of gyration (ky) of the shaded area with respect to y axis.

Expert Solution & Answer
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Answer to Problem 9.20P

The moment of inertia (Iy) and radius of gyration (ky) of the shaded area with respect to y axis is 0.61345a3h_ and 1.299a_ respectively.

Explanation of Solution

Given information:

The equation of the upper segment is y=mx+b.

The equation of the lower curve is y=csinkx.

Calculation:

Show the subject area with vertical differential strip element as Figure 1.

Vector Mechanics for Engineers: Statics, 11th Edition, Chapter 9.1, Problem 9.20P

Consider the curve equation as y=csinkx.

Apply the boundary condition at y1.

Condition 1:

At x=2a and y=0.

0=csink(2a)

Since sinθ will be zero when angle at 180°(π).

2ak=πk=π2a

Condition 2:

At x=a and y=h.

h=csink(a)

Substitute π2a for k.

h=csinπ2a(a)h=csinπ2h=c(1)(sinπ2=1)c=h

Consider the upper curve equation y=mx+b.

Apply the boundary condition at y2.

Condition 1:

At x=a and y=2h.

2h=ma+b (1)

Condition 2:

At x=2a and y=0.

0=m2a+b2ma+b=0 (2)

Subtract the equation (1) and (2).

2h0=ma+b2mab2h=mam=2ha

Substitute 2ha for m in the equation (2).

2(2ha)a+b=04h+b=0b=4h

Rewrite the lower equation.

y=csinkx

Substitute y1 for y, h for c and π2a for k.

y1=hsinπ2ax

Rewrite the upper equation.

y=mx+b

Substitute y2 for y, 2ha for m and 4h for b.

y2=2hax+4h=2ha(x+2a)

Calculate the area of the given figure (A) using the formula:

A=dA=(y2y1)dx

Substitute hsinπ2ax for y1 and 2ha(x+2a) for y2.

A=[2ha(x+2a)(hsinπ2ax)]dx=a2ah[2a(x+2a)(sinπ2ax)]dx=h[(2a(x+2a)22(1))(cosπ2axπ2a)]a2a

=h[(1a(x+2a)2)+2aπcosπ2ax]a2a=h[(1a(2a+2a)2+1a(a+2a)2)+(2aπcosπ2a2a(2aπcosπ2aa))]=h[(1a(a+2a)2)+2aπ(1)0]

=h[(1a(a+2a)2)2aπ]=ah[(11(1+2)22π)]=ah[12π]=0.36338ah

Calculate the moment of inertia about y axis using the formula:

Iy=dIy=x2dA=a2ax2(y2y1)dx

Substitute hsinπ2ax for y1 and 2ha(x+2a) for y2.

Iy=a2a[x2(2ha(x+2a))(hsinπ2ax)]dx=a2ah[2a(x3+2ax2)x2sinπ2ax]dx (3)

Take u=x2 from the equation (3).

Differentiate the u equation with respect to x.

du=2xdx

Take dv=sinπ2axdx from the equation (3).

Integrate the above equation with respect to x.

dv=sinπ2axdxv=cosπ2axπ2a=2aπcosπ2ax

Consider the second term from the equation (3).

x2sinπ2axdx

Integrate the above equation by UV method with respect to x.

Substitute 2aπcosπ2ax for sinπ2ax.

Since uv=udvvdu.

x2sinπ2axdx=x2(2aπcosπ2ax)(2aπcosπ2ax)(2xdx)=2ax2πcosπ2ax+4aπ[x(2aπsinπ2ax)+2aπsinπ2ax(1)]=2ax2πcosπ2ax+8a2π2xsinπ2ax+4aπ(2aπ×2aπcosπ2ax)=2ax2πcosπ2ax+8a2π2xsinπ2ax+16a3π3cosπ2ax

Substitute 2ax2πcosπ2ax+8a2π2xsinπ2ax+16a3π3cosπ2ax for x2sinπ2axdx in the equation (1).

Iy=h[2a(x44+2ax33)(2ax2πcosπ2ax+8a2π2xsinπ2ax+16a3π3cosπ2ax)]a2a={h[2a((2a)44+2a(2a)33)(2a(2a)2πcosπ2a2a+8a2π22asinπ2a2a+16a3π3cosπ2a2a)]h[2a(a44+2aa33)(2aa2πcosπ2aa+8a2π2asinπ2aa+16a3π3cosπ2aa)]}=h{[2a(16a44+16a43)(8a3π(1)+16a3π3)]}h[(2a(a44+2a43))8a3π2]=0.61345a3h

Calculate the radius of gyration (ky) along y axis using the formula:

ky=IyA

Substitute 0.36338ah for A and 0.61345a3h for Ix.

ky=0.61345a3h0.36338ah=1.299a

Therefore, the moment of inertia (Iy) and radius of gyration (ky) of the shaded area with respect to y axis are 0.61345a3h_ and 1.299a_ respectively.

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Chapter 9 Solutions

Vector Mechanics for Engineers: Statics, 11th Edition

Ch. 9.1 - 9.9 through 9.11 Determine by direct integration...Ch. 9.1 - 9.12 through 9.14 Determine by direct integration...Ch. 9.1 - Prob. 9.13PCh. 9.1 - 9.12 through 9.14 Determine by direct integration...Ch. 9.1 - 9.15 through 9.16 Determine the moment of inertia...Ch. 9.1 - 9.15 through 9.16 Determine the moment of inertia...Ch. 9.1 - 9.17 through 9.18 Determine the moment of inertia...Ch. 9.1 - Prob. 9.18PCh. 9.1 - Prob. 9.19PCh. 9.1 - Prob. 9.20PCh. 9.1 - Prob. 9.21PCh. 9.1 - 9.21 and 9.22 Determine the polar moment of...Ch. 9.1 - 9.23 and 9.24 Determine the polar moment of...Ch. 9.1 - 9.23 and 9.24 Determine the polar moment of...Ch. 9.1 - (a) Determine by direct integration the polar...Ch. 9.1 - (a) Show that the polar radius of gyration kQ of...Ch. 9.1 - Determine the polar moment of inertia and the...Ch. 9.1 - Determine the polar moment of inertia and the...Ch. 9.1 - Using the polar moment of inertia of the isosceles...Ch. 9.1 - Prove that the centroidal polar moment of inertia...Ch. 9.2 - 9.31 and 9.32 Determine the moment of inertia and...Ch. 9.2 - 9.31 and 9.32 Determine the moment of inertia and...Ch. 9.2 - 9.33 and 9.34 Determine the moment of inertia and...Ch. 9.2 - 9.33 and 9.34 Determine the moment of inertia and...Ch. 9.2 - 9.35 and 9.36 Determine the moments of inertia of...Ch. 9.2 - Prob. 9.36PCh. 9.2 - 9.37 The centroidal polar moment of inertia of...Ch. 9.2 - 9.38 Determine the centroidal polar moment of...Ch. 9.2 - 9.39 Determine the shaded area and its moment of...Ch. 9.2 - 9.40 Knowing that the shaded area is equal to 6000...Ch. 9.2 - 9.41 through 9.44 Determine the moments of inertia...Ch. 9.2 - 9.41 through 9.44 Determine the moments of inertia...Ch. 9.2 - 9.41 through 9.44 Determine the moments of inertia...Ch. 9.2 - Prob. 9.44PCh. 9.2 - 9.45 and 9.46 Determine the polar moment of...Ch. 9.2 - 9.45 and 9.46 Determine the polar moment of...Ch. 9.2 - Prob. 9.47PCh. 9.2 - Prob. 9.48PCh. 9.2 - 9.49 Two channels and two plates are used to form...Ch. 9.2 - 9.50 Two . angles are welded together to form the...Ch. 9.2 - Four L3 3 14 - in. angles are welded to a rolled...Ch. 9.2 - Two 20-mm steel plates are welded to a rolled S...Ch. 9.2 - A channel and a plate are welded together as shown...Ch. 9.2 - The strength of the rolled W section shown is...Ch. 9.2 - Two L76 76 6.4-mm angles are welded to a C250 ...Ch. 9.2 - Two steel plates are welded to a rolled W section...Ch. 9.2 - 9.57 and 9.58 The panel shown forms the end of a...Ch. 9.2 - 9.57 and 9.58 The panel shown forms the end of a...Ch. 9.2 - Prob. 9.59PCh. 9.2 - Prob. 9.60PCh. 9.2 - A vertical trapezoidal gate that is used as an...Ch. 9.2 - The cover for a 0.5-m-diameter access hole in a...Ch. 9.2 - Determine the x coordinate of the centroid of the...Ch. 9.2 - Determine the x coordinate of the centroid of the...Ch. 9.2 - Show that the system of hydrostatic forces acting...Ch. 9.2 - Show that the resultant of the hydrostatic forces...Ch. 9.3 - 9.67 through 9.70 Determine by direct integration...Ch. 9.3 - Prob. 9.68PCh. 9.3 - 9.67 through 9.70 Determine by direct integration...Ch. 9.3 - 9.67 through 9.70 Determine by direct integration...Ch. 9.3 - 9.71 through 9.74 Using the parallel-axis theorem,...Ch. 9.3 - 9.71 through 9.74 Using the parallel-axis theorem,...Ch. 9.3 - 9.71 through 9.74 Using the parallel-axis theorem,...Ch. 9.3 - Prob. 9.74PCh. 9.3 - 9.75 through 9.78 Using the parallel-axis theorem,...Ch. 9.3 - 9.75 through 9.78 Using the parallel-axis theorem,...Ch. 9.3 - 9.75 through 9.78 Using the parallel-axis theorem,...Ch. 9.3 - Prob. 9.78PCh. 9.3 - Determine for the quarter ellipse of Prob. 9.67...Ch. 9.3 - Determine the moments of inertia and the product...Ch. 9.3 - Determine the moments of inertia and the product...Ch. 9.3 - 9.75 through 9.78 Using the parallel-axis theorem,...Ch. 9.3 - Determine the moments of inertia and the product...Ch. 9.3 - Determine the moments of inertia and the product...Ch. 9.3 - Prob. 9.85PCh. 9.3 - 9.86 through 9.88 For the area indicated,...Ch. 9.3 - 9.86 through 9.88 For the area indicated,...Ch. 9.3 - 9.86 through 9.88 For the area indicated,...Ch. 9.3 - 9.89 and 9.90 For the angle cross section...Ch. 9.3 - 9.89 and 9.90 For the angle cross section...Ch. 9.4 - Using Mohrs circle, determine for the quarter...Ch. 9.4 - Using Mohrs circle, determine the moments of...Ch. 9.4 - Using Mohrs circle, determine the moments of...Ch. 9.4 - Using Mohrs circle, determine the moments of...Ch. 9.4 - Using Mohrs circle, determine the moments of...Ch. 9.4 - Using Mohrs circle, determine the moments of...Ch. 9.4 - For the quarter ellipse of Prob. 9.67, use Mohrs...Ch. 9.4 - Prob. 9.98PCh. 9.4 - 9.98 though 9.102 Using Mohrs circle, determine...Ch. 9.4 - 9.98 though 9.102 Using Mohrs circle, determine...Ch. 9.4 - 9.98 through 9.102 Using Mohrs circle, determine...Ch. 9.4 - 9.98 through 9.102 Using Mohrs circle, determine...Ch. 9.4 - Prob. 9.103PCh. 9.4 - 9.104 and 9.105 Using Mohrs circle, determine the...Ch. 9.4 - 9.104 and 9.105 Using Mohrs circle, determine the...Ch. 9.4 - Prob. 9.106PCh. 9.4 - it is known that for a given area Iy = 48 106 mm4...Ch. 9.4 - Prob. 9.108PCh. 9.4 - Using Mohrs circle, prove that the expression...Ch. 9.4 - Using the invariance property established in the...Ch. 9.5 - A thin plate with a mass m is cut in the shape of...Ch. 9.5 - A ring with a mass m is cut from a thin uniform...Ch. 9.5 - Prob. 9.113PCh. 9.5 - The parabolic spandrel shown was cut from a thin,...Ch. 9.5 - Prob. 9.115PCh. 9.5 - Fig. P9.115 and P9.116 9.116 A piece of thin,...Ch. 9.5 - Prob. 9.117PCh. 9.5 - Prob. 9.118PCh. 9.5 - Prob. 9.119PCh. 9.5 - The area shown is revolved about the x axis to...Ch. 9.5 - Prob. 9.121PCh. 9.5 - 9.122 Determine by direct integration the mass...Ch. 9.5 - Prob. 9.123PCh. 9.5 - Determine by direct integration the mass moment of...Ch. 9.5 - Prob. 9.125PCh. 9.5 - A thin steel wire is bent into the shape shown....Ch. 9.5 - Shown is the cross section of an idler roller....Ch. 9.5 - Shown is the cross section of a molded flat-belt...Ch. 9.5 - Prob. 9.129PCh. 9.5 - Prob. 9.130PCh. 9.5 - Prob. 9.131PCh. 9.5 - Prob. 9.132PCh. 9.5 - After a period of use, one of the blades of a...Ch. 9.5 - Determine the mass moment of inertia of the 0.9-lb...Ch. 9.5 - 9.135 and 9.136 A 2-mm thick piece of sheet steel...Ch. 9.5 - 9.135 and 9.136 A 2 -mm thick piece of sheet steel...Ch. 9.5 - Prob. 9.137PCh. 9.5 - A section of sheet steel 0.03 in. thick is cut and...Ch. 9.5 - Prob. 9.139PCh. 9.5 - Prob. 9.140PCh. 9.5 - The machine element shown is fabricated from...Ch. 9.5 - Determine the mass moments of inertia and the...Ch. 9.5 - Determine the mass moment of inertia of the steel...Ch. 9.5 - Fig. P9.143 and P9.144 9.144 Determine the mass...Ch. 9.5 - Determine the mass moment of inertia of the steel...Ch. 9.5 - Aluminum wire with a weight per unit length of...Ch. 9.5 - The figure shown is formed of 18-in.-diameter...Ch. 9.5 - A homogeneous wire with a mass per unit length of...Ch. 9.6 - Determine the mass products of inertia Ixy, Iyz,...Ch. 9.6 - Determine the mass products of inertia Ixy, Iyz,...Ch. 9.6 - Prob. 9.151PCh. 9.6 - Determine the mass products of inertia Ixy, Iyz,...Ch. 9.6 - Prob. 9.153PCh. 9.6 - Prob. 9.154PCh. 9.6 - 9.153 through 9.156 A section of sheet steel 2 mm...Ch. 9.6 - 9.153 through 9.156 A section of sheet steel 2 mm...Ch. 9.6 - The figure shown is formed of 1.5-mm-diameter...Ch. 9.6 - Prob. 9.158PCh. 9.6 - 9.159 and 9.160 Brass wire with a weight per unit...Ch. 9.6 - Fig. P9.160 9.159 and 9.160 Brass wire with a...Ch. 9.6 - Complete the derivation of Eqs. (9.47) that...Ch. 9.6 - Prob. 9.162PCh. 9.6 - Prob. 9.163PCh. 9.6 - Prob. 9.164PCh. 9.6 - Shown is the machine element of Prob. 9.141....Ch. 9.6 - Determine the mass moment of inertia of the steel...Ch. 9.6 - The thin, bent plate shown is of uniform density...Ch. 9.6 - A piece of sheet steel with thickness t and...Ch. 9.6 - Determine the mass moment of inertia of the...Ch. 9.6 - 9.170 through 9.172 For the wire figure of the...Ch. 9.6 - Prob. 9.171PCh. 9.6 - 9.172 Prob. 9.146 9.146 Aluminum wire with a...Ch. 9.6 - For the homogeneous circular cylinder shown with...Ch. 9.6 - For the rectangular prism shown, determine the...Ch. 9.6 - Prob. 9.175PCh. 9.6 - Prob. 9.176PCh. 9.6 - Consider a cube with mass m and side a. (a) Show...Ch. 9.6 - Prob. 9.178PCh. 9.6 - Prob. 9.179PCh. 9.6 - 9.180 through 9.184 For the component described in...Ch. 9.6 - 9.180 through 9.184 For the component described in...Ch. 9.6 - Prob. 9.182PCh. 9.6 - 9.180 through 9.184 For the component described in...Ch. 9.6 - 9.180 through 9.184 For the component described in...Ch. 9 - Determine by direct integration the moments of...Ch. 9 - Determine the moment of inertia and the radius of...Ch. 9 - Determine the moment of inertia and the radius of...Ch. 9 - Determine the moments of inertia Ix and Iy of the...Ch. 9 - Determine the polar moment of inertia of the area...Ch. 9 - Two L4 4 12-in. angles are welded to a steel...Ch. 9 - Using the parallel-axis theorem, determine the...Ch. 9 - Prob. 9.192RPCh. 9 - Fig. P9.193 and P9.194 9.193 A thin plate with a...Ch. 9 - Fig. P9.193 and P9.194 9.194 A thin plate with...Ch. 9 - A 2-mm-thick piece of sheet steel is cut and bent...Ch. 9 - Determine the mass moment of inertia of the steel...
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