Which way of dispensing champagne, the traditional vertical method or a tilted beer-like pour, preserves more of the tiny gas bubbles that improve flavor and aroma? The following data was reported in the article “On the Losses of Dissolved CO2 during Champagne Serving” (J. Agr. Food Chem., 2010: 8768–8775).
Temp (°C) | Type of Pour | n | SD | |
18 | Traditional | 4 | 4.0 | .5 |
18 | Slanted | 4 | 3.7 | .3 |
12 | Traditional | 4 | 3.3 | .2 |
12 | Slanted | 4 | 2.0 | .3 |
Assume that the sampled distributions are normal.
a. Carry out a test at significance level .01 to decide whether true average CO2 loss at 18 °C for the traditional pour differs from that for the slanted pour.
b. Repeat the test of hypotheses suggested in (a) for the 12° temperature. Is the conclusion different from that for the 18° temperature? Note: The 12° result was reported in the popular media.
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Chapter 9 Solutions
Student Solutions Manual for Devore's Probability and Statistics for Engineering and the Sciences, 9th
- Respiratory Rate Researchers have found that the 95 th percentile the value at which 95% of the data are at or below for respiratory rates in breath per minute during the first 3 years of infancy are given by y=101.82411-0.0125995x+0.00013401x2 for awake infants and y=101.72858-0.0139928x+0.00017646x2 for sleeping infants, where x is the age in months. Source: Pediatrics. a. What is the domain for each function? b. For each respiratory rate, is the rate decreasing or increasing over the first 3 years of life? Hint: Is the graph of the quadratic in the exponent opening upward or downward? Where is the vertex? c. Verify your answer to part b using a graphing calculator. d. For a 1- year-old infant in the 95 th percentile, how much higher is the walking respiratory rate then the sleeping respiratory rate? e. f.arrow_forwardWhich way of dispensing champagne, the traditional vertical method or a tilted beer-like pour, preserves more of the tiny gas bubbles that improve flavor and aroma? The following data was reported in an article. Temp (°C) Type of Pour n Mean (g/L) SD 18 Traditional 4 4.0 0.7 18 Slanted 4 3.7 0.3 12 Traditional 4 3.3 0.4 12 Slanted 4 2.0 0.2 (a) At a significance level of 0.01 , calculate the test statistic and P-value for the 18° temperature. (Round your test statistic to one decimal place and your P-value to three decimal places.) (b) Repeat the test of hypotheses suggested in (a) for the 12° temperature. calculate the test statistic and P-value (Round your test statistic to one decimal place and your P-value to three decimal places.).arrow_forwardHydrogen content is conjectured to be an important factor in porosity of aluminum alloy castings. An article gives the accompanying data on x = content and y = gas porosity for one particular measurement technique. 0.18 0.20 0.21 0.21 0.21 0.22 0.23 0.23 0.24 0.24 0.25 0.28 0.30 0.37 0.48 0.71 0.42 0.44 0.55 0.44 0.24 0.48 0.22 0.82 0.86 0.72 0.70 0.74 Minitab gives the following output in a response to a Correlation command: Correlation of Hydrcon and Porosity = 0.425 (a) Test at level 0.05 to see whether the population correlation coefficient differs from o. State the appropriate null and alternative hypotheses. O Ho: p = 0 Hip 0 O Ho: p = 0 Hip + 0 O Ho: p+0 Hip = 0 Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to three decimal places.) t = P-value = State the conclusion in the problem context. O Fail to reject H: The data does not suggest that the population correlation coefficient differs significantly…arrow_forward
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