THINKING LIKE AN ENGINEER W/ACCESS
THINKING LIKE AN ENGINEER W/ACCESS
17th Edition
ISBN: 9781323522127
Author: STEPHAN
Publisher: PEARSON C
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Chapter 9.2, Problem 3CC

What are the dimensions of the value 6 in the following equation, assuming T is temperature [kelvin, K] and P is algae population [gram per milliliter, g/mL]?

T=102e–6P

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If the given Pi is 3.14159 Capillary tube: radius = 0.02 cm; length = 9 cm; pressure = 0.7 mmHg Liquid sample: density = 4 ml; time of flow = 4.5 seconds What is the pressure in MKS unit and CGS unit? What is its viscosity? If the weight is 8.5 g, what is its density? What is its kinematic viscosity? What is its fluidity?
(a) Verify that each additive term in the Bernoulli equation has the same dimensions. (b) What are the dimensions of the constant C? (a) Verify that each additive term in the Bernoulli equation has the same dimensions. (b) What are the dimensions of the constant C?
For the Following question Graph all 4 : [I just need all 4 graphs and please explain and make clean solution] Position vs time Velocity vs time Acceleration vs time Force vs time [For your convenience, I have solved the numerical solutions for the problem] (Please Look at the picture since it is much cleaner) Question : A 550 kilogram mass initially at rest acted upon by a force of F(t) = 50et Newtons. What are the acceleration, speed, and displacement of the mass at  t = 4 second ? a =(50 e^t)/(550 ) [N/kg] v = ∫_0^t▒(50 e^t )dt/(550 )= v_0  +(50 e^t-50)/550=((e^t- 1))/11 x = ∫_0^t▒(e^t- 1)dt/(11 )= x_0  +(e^t- t - 1)/(11 ) a(4s)=(50*54.6)/550= 4.96[m/s^2 ] v(4s)=((e^4-1))/11= 4.87[m/s] x(4s)=((e^4- 4 - 1))/11= 4.51 [m]

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THINKING LIKE AN ENGINEER W/ACCESS

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