Bundle: Organic Chemistry, Loose-leaf Version, 9th + LMS Integrated for OWLv2, 4 terms (24 months) Printed Access Card
Bundle: Organic Chemistry, Loose-leaf Version, 9th + LMS Integrated for OWLv2, 4 terms (24 months) Printed Access Card
9th Edition
ISBN: 9781305780170
Author: John E. McMurry
Publisher: Cengage Learning
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Chapter 9.4, Problem 6P
Interpretation Introduction

a)

Bundle: Organic Chemistry, Loose-leaf Version, 9th + LMS Integrated for OWLv2, 4 terms (24 months) Printed Access Card, Chapter 9.4, Problem 6P , additional homework tip  1

Interpretation:

The alkyne which can be used as a starting material to prepare the compound given by hydroboration-oxidation reaction is to be stated.

Concept introduction:

The hydroboration reaction takes place with syn stereochemistry and results in a non-Markovnikov addition of water to the triple bond in an alkyne. The resulting product has the hydroxyl group on the less highly substituted carbon which tautomerises to yield carbonyl compounds. Terminal alkynes give an aldehyde while non-terminal internal alkynes give a ketone.

To state:

The alkyne which can be used as a starting material to prepare the compound given by hydroboration-oxidation reaction.

b)

Interpretation Introduction

Interpretation:

The alkyne which can be used as a starting material to prepare the compound given by hydroboration-oxidation reaction is to be stated.

Concept introduction:

The hydroboration reaction takes place with syn stereochemistry and results in a non-Markovnikov addition of water to the triple bond in an alkyne. The resulting product has the hydroxyl group on the less highly substituted carbon which tautomerises to yield carbonyl compounds. Terminal alkynes give an aldehyde while non-terminal internal alkynes give a ketone.

To state:

The alkyne which can be used as a starting material to prepare the compound given by hydroboration-oxidation reaction.

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Chapter 9 Solutions

Bundle: Organic Chemistry, Loose-leaf Version, 9th + LMS Integrated for OWLv2, 4 terms (24 months) Printed Access Card

Ch. 9.8 - Prob. 11PCh. 9.9 - Show the terminal alkyne and alkyl halide from...Ch. 9.9 - Beginning with acetylene and any alkyl halide...Ch. 9.SE - Name the following alkynes, and predict the...Ch. 9.SE - From what alkyne might each of the following...Ch. 9.SE - Prob. 16VCCh. 9.SE - The following cycloalkyne is too unstable to...Ch. 9.SE - Prob. 18MPCh. 9.SE - Assuming that strong acids add to alkynes in the...Ch. 9.SE - Prob. 20MPCh. 9.SE - Prob. 21MPCh. 9.SE - Prob. 22MPCh. 9.SE - Prob. 23MPCh. 9.SE - Prob. 24MPCh. 9.SE - Reaction of acetone with D3O+ yields...Ch. 9.SE - Give IUPAC names for the following compounds:Ch. 9.SE - Draw structures corresponding to the following...Ch. 9.SE - Prob. 28APCh. 9.SE - Prob. 29APCh. 9.SE - Prob. 30APCh. 9.SE - Predict the products from reaction of l-hexyne...Ch. 9.SE - Prob. 32APCh. 9.SE - Prob. 33APCh. 9.SE - Propose structures for hydrocarbons that give the...Ch. 9.SE - Identify the reagents a-c in the following scheme:Ch. 9.SE - Prob. 36APCh. 9.SE - Prob. 37APCh. 9.SE - Prob. 38APCh. 9.SE - How would you carry out the following...Ch. 9.SE - Prob. 40APCh. 9.SE - Synthesize the following compounds using 1-butyne...Ch. 9.SE - Prob. 42APCh. 9.SE - Prob. 43APCh. 9.SE - Prob. 44APCh. 9.SE - Prob. 45APCh. 9.SE - A hydrocarbon of unknown structure has the formula...Ch. 9.SE - Compound A(C9H12) absorbed 3 equivalents of H2 on...Ch. 9.SE - Hydrocarbon A has the formula C12H8. It absorbs 8...Ch. 9.SE - Occasionally, a chemist might need to invert the...Ch. 9.SE - Prob. 50APCh. 9.SE - Prob. 51APCh. 9.SE - Prob. 52APCh. 9.SE - Prob. 53APCh. 9.SE - Prob. 54APCh. 9.SE - Prob. 55APCh. 9.SE - Prob. 56APCh. 9.SE - Prob. 57AP
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