Essentials of Genetics, Books a la Carte Plus Mastering Genetics with eText -- Access Card Package (9th Edition)
9th Edition
ISBN: 9780134319070
Author: William S. Klug, Michael R. Cummings, Charlotte A. Spencer, Michael A. Palladino
Publisher: PEARSON
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Textbook Question
Chapter CHST2, Problem 6RQ
The mechanism for RNA-induced transcriptional silencing of heterochromatic DNA is paradoxical. For example, how does it make sense that centromeric DNA in fission yeast first needs to be transcribed before it can be transcriptionally silenced?
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In eukaryotes many transcriptional activators are dimers of related proteins. Assuming each dimer binds to one unique sequence, how many unique sequences can protein dimers derived from a family of six related proteins bind to?
Many eukaryotic promoter regions contain CAAT boxes with consensus sequences CAAT or CCAAT approximately 70 to 80 bases upstream from the transcription start site. How might one determine the influence of CAAT boxes on the transcription rate of a given gene?
For each of the following transcription factors, explain how eukaryotic transcriptional initiation would be affected if it were missing.
A. TFIIB C. TFIIH
B. TFIID
Chapter CHST2 Solutions
Essentials of Genetics, Books a la Carte Plus Mastering Genetics with eText -- Access Card Package (9th Edition)
Ch. CHST2 - What are some of the different roles that RNA...Ch. CHST2 -
2. What arguments support the RNA World...Ch. CHST2 - Prob. 3RQCh. CHST2 - How is bacterial DNA methylation and expression of...Ch. CHST2 - What are the three types of small noncoding RNAs...Ch. CHST2 - The mechanism for RNA-induced transcriptional...Ch. CHST2 - Although exRNAs are found in many fluids within...Ch. CHST2 - How and why are eukaryotic mRNAs transported and...Ch. CHST2 - The RNA World Hypothesis suggests that the...Ch. CHST2 - Bacterial sRNAs can bind to mRNAs through...
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- Transcriptionally active chromatin are generally found near the outer regions of the nucleus near the membrane. true or false?arrow_forwardConsider the Rho-dependent terminator sequence 5’CCCAGCCCGCCUAAUGAGCGGCCUUUUUUUU-3’. What affect would a point mutation at any one of the bolded and underlined nucleotides disrupt termination of transcription? Group of answer choices Mutation in one of these nucleotides would disrupt base pairing, preventing the formation of the hairpin and disrupting termination. Mutation in one of these nucleotides would have no affect on base pairing, so the termination hairpin is formed and termination proceeds. Mutation in one of these nucleotides would not disrupt base pairing, but would prevent the formation of the hairpin and disrupt termination. Mutation in one of these nucleotides would disrupt base pairing, but not affect the formation of the hairpin and termination proceeds.arrow_forwardSince RNA polymerase has an error rate of 1 / 10^4 nucleotides, and the DNA polymerase has an error rate of 1 / 10^7 nucleotides, can cells tolerate errors made in transcription in comparison to errors made during DNA replication?arrow_forward
- . Why is a nonsense suppressor tRNATyr, even though ithas a mutant anticodon that cannot recognize a tyrosinecodon, charged with tyrosine by Tyr tRNA synthetase?arrow_forwardWhy transcription initiation requires the assembly of transcription regulatory proteins on DNA sites known as silencers ?arrow_forwardWhat is meant by the term chromatin remodeling? Describe the importance of this process to transcription.arrow_forward
- Refer to figure, which shows the distribution of histone H2A.Z on nucleosomes near a transcription start site. What experimental technique would have been used to generate the data for this figure? Briefly describe the operation of this technique.arrow_forwardA drug called garcinol, is isolated from Garciniaindica (a fruit-bearing tree commonlyknown as kokum), is a potent inhibitor of histone deacetylase. Would you expect thisdrug to enhance or inhibit transcriptional initiation and elongation?arrow_forwardWhy is transcriptionally active chromatin ∼10 times more susceptible to cleavage by DNase I than transcriptionally silent chromatin?arrow_forward
- Consider the Rho-dependent terminator sequence 5’CCCAGCCCGCCUAAUGAGCGGCCUUUUUUUU-3’. What affect would a point mutation at any one of the bolded and underlined nucleotides disrupt termination of transcription? Group of answer choices 1.Mutation in one of these nucleotides would disrupt base pairing, but not affect the formation of the hairpin and termination proceeds. 2.Mutation in one of these nucleotides would have no affect on base pairing, so the termination hairpin is formed and termination proceeds. 3.Mutation in one of these nucleotides would not disrupt base pairing, but would prevent the formation of the hairpin and disrupt termination. 4.Mutation in one of these nucleotides would disrupt base pairing, preventing the formation of the hairpin and disrupting termination.arrow_forwardWhat is the experimental basis for concluding that puffs in polytene chromosomes and loops in lampbrush chromosomes are areas of intense transcription of RNA?arrow_forwardMany promoter regions contain CAAT boxes containing consensus sequences CAAT or CCAAT approximately 70 to 80 bases upstream from the transcription start site. How might one determine the influence of CAAT boxes on the transcription rate of a given gene?arrow_forward
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