The atomic orbital overlap and MO energy diagrams for CH 3 CH 2 Br (Figs. 3-13 through 3-25 to be reviewed) are to be constructed, and these diagrams are to be used to determine its HOMO and LUMO. Whether answers agree with the ones shown in Figure D-10a is to be explained. Concept introduction: Molecular orbitals are constructed from the AOs of different atoms. When two atoms are brought close enough together (i.e., about a bond length apart), the AOs of one atom significantly overlap the AOs of the other atom, enabling them to undergo constructive and destructive interference, or mix, to produce new orbitals. The two C atoms and the Br atom are all sp 3 hybridized, and each H atom contributes a 1s orbital. End-on overlap occurs in the C-H , C-C , and C-Br bonding and, therefore, results in seven σ bonds. When the 14 AOs overlap, 14 MOs are produced: seven σ bonding and seven σ* antibonding. This leaves three nonbonding orbitals.

Question

Want to see the full answer?

Answer 1

Question

Chapter D, Problem D.11YT

Interpretation Introduction

Interpretation:

The atomic orbital overlap and MO energy diagrams for CH3CH2Br (Figs. 3-13 through 3-25 to be reviewed) are to be constructed, and these diagrams are to be used to determine its HOMO and LUMO. Whether answers agree with the ones shown in Figure D-10a is to be explained.

Concept introduction:

Molecular orbitals are constructed from the AOs of different atoms. When two atoms are brought close enough together (i.e., about a bond length apart), the AOs of one atom significantly overlap the AOs of the other atom, enabling them to undergo constructive and destructive interference, or mix, to produce new orbitals. The two C atoms and the Br atom are all sp3 hybridized, and each H atom contributes a 1s orbital. End-on overlap occurs in the C-H, C-C, and C-Br bonding and, therefore, results in seven σ bonds. When the 14 AOs overlap, 14 MOs are produced: seven σ bonding and seven σ* antibonding. This leaves three nonbonding orbitals.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

In the reaction of CN- + H + → HCN; 1) Which boundary orbitals are used? Draw a diagram and explain according to MOT. 2) Explain the orbital overlaps of the product according to VBT. 3) Determine the point group of the product.

Let us construct the molecular orbital diagram of ethylene (in pieces). a. First, construct the MO diagram of linear carbene (CH2). Draw pictures of all 6 orbitals b. Now bend the carbene to a bond angle of about 120°. How does this change your MO diagram? Draw pictures of all 6 orbitals. c. Now bring two of these carbene molecules together to make ethylene. Draw pictures of all 12 orbitals.

2) For each pair of molecules, generate the relevant MO diagram and predict which of the twowill have the highest bond order. (Be sure to include all valenceorbitals, and show the relative positions of the orbitals for each constituent atom.)a) HF vs HF-b) NP vs NP+c) CS vs CS+