Chapter U4.14, Problem 4E

Interpretation Introduction

Interpretation:

The portion of 1.0 L of 0.50 M blue dye solution having the same number of moles as 1.0 L of 0.25 M blue dye solution needs to be determined.

Concept introduction:

Moles of solute can be found from the following formula.

  $n=M\times V$

Here, M is molarity and V is volume of the solution in L.

Answer to Problem 4E

Half portion of1.0 L of 0.50 M blue dye solution has the same number of moles as 1.0 L of 0.25 M blue dye solution.

Explanation of Solution

Moles present in 1.0 L of 0.50 M blue dye solution= $n=M\times V=0.50\times 1=0.5\text{ mol}$

Moles present in 1.0 L of 0.25 M blue dye solution $n=M\times V=0.25\times 1=0.25\text{ mol}$ .

Half of 0.5 is 0.25.

Thus, moles of 1^st solution is double to the moles of 2^nd solution.

Conclusion

Thus, half portion of1.0 L of 0.50 M blue dye solution has the same number of moles as 1.0 L of 0.25 M blue dye solution.