Chapter U5.18, Problem 9E

Interpretation Introduction

Interpretation:Three combinations of ionic compounds and metals that will not react needs to be determined.

Concept introduction: A chemical reaction is a symbolic representation of how reactants react in presence of adequate amount of temperature and reaction medium to generate a product.

An ionic reaction is a symbolic representation of how ions reacts in a chemical reaction.

Answer to Problem 9E

Three combinations of ionic compounds and metals that will not react are:

1. Combination of ${\text{ZnCl}}_{\text{2}}$ and $\text{Fe}$
2. Combination of $\text{Zn}{\left({\text{NO}}_3\right)}_{\text{2}}$ and $\text{Fe}$
3. Combination of $\text{Cu}{\left({\text{NO}}_{\text{3}}\right)}_{\text{2}}$ and $\text{Ag}$

Explanation of Solution

The activity series of metal in the order of increasing reactivity is,

Gold < Silver < Mercury < Bismuth < Antimony < Hydrogen < Lead < Tin < Nickel < Cobalt < Cadmium < Iron < Chromium < Zinc < Manganese < Aluminium < Calcium < Strontium < Barium < Lithium < Sodium < Potassium

The metal lower in the activity series will not replace any atom above in the activity series. So, three such combination of ionic compounds and metals that will not react are,

4. Combination of ${\text{ZnCl}}_{\text{2}}$ and $\text{Fe}$
5. Combination of $\text{Zn}{\left({\text{NO}}_3\right)}_{\text{2}}$ and $\text{Fe}$
6. Combination of $\text{Cu}{\left({\text{NO}}_{\text{3}}\right)}_{\text{2}}$ and $\text{Ag}$

Conclusion

1. Combination of ${\text{ZnCl}}_{\text{2}}$ and $\text{Fe}$
2. Combination of $\text{Zn}{\left({\text{NO}}_3\right)}_{\text{2}}$ and $\text{Fe}$
3. Combination of $\text{Cu}{\left({\text{NO}}_{\text{3}}\right)}_{\text{2}}$ and $\text{Ag}$

The above threecombinations of ionic compounds and metals that will not react.