exam1_WHITE_BCHM461-0102_OFFICIAL_KEY_Fall2022
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Course
461
Subject
Chemistry
Date
Dec 6, 2023
Type
Pages
12
Uploaded by CoachClover395
BCHM 461-0102
Name:
Official Key (WHITE exams) October 10, 2022
Prof. Julin
Exam I
(100 points)
NOTE:
read
the questions carefully,
think
about your answers, and,
be sure that you
answer all parts of the questions.
Provide specific information
that answers the question being asked.
Always show your work or explain your reasoning.
You may use a calculator, but only
for computation. Any other use is a violation of the
University’s Code of Academic Integrity
.
No other electronic equipment may be used - that is, turn off your cell phone
!
Honor Pledge
Please write
the following sentence in the box, and then sign your name:
“I pledge on my honor that I have not given or received any unauthorized assistance
on this examination.”
Some equations and formulas which might (or might not) be useful:
a) Quadratic formula.
For: ax
2
+ bx + c = 0
x = !
b ± ( b
2
!
4ac )
½
2a
b)
K
w
= [H
+
][OH
!
] = 10
!
14
c)
K
a
= [H
+
][A
!
]/[HA]
pH = pK
a
+ log([A
!
]/[HA])
d) Δ
G = Δ
H !
T
Δ
S
e) Δ
G = Δ
G
EN
+ RT ln{[
products
]/[
reactants
]}
f)
K
eq
= exp(
!
Δ
G
EN
/RT)
g) Δ
G
EN
= !
RTln(K
eq
)
K
eq
= [products] / [reactants]
h)
R = 8.3 J/K/mol = 0.0083 kJ/K/mol
i)
T (K) = T (
E
C) + 273
j)
E
%
Q
1
Q
2 / ε
r
k)
fr dissoc
Ka
H
Ka
H
pH
pKa
pH
pKa
.
.
[
]
[
]
(
)
(
)
1
10
10
1
l)
m
/
z
= (MW + nH)/n H = 1.008
m)
c
= Abs / ε
(
Beer’s Law
)
n) ε
280
= (# Trp) × 5,500 + (# Tyr) × 1,490
1. (20 points)
Given below are the names of five recipients of a Nobel Prize (in various fields).
i) (4 pts)
Consider only the last names
(written in capital letters). Which of these last
names could also be a peptide, written in single-letter code? Explain briefly
and specifically
why
the other last names cannot be a peptide.
1) (Ei-ichi) N E G I S H I
2) (David) B A L T I M O R E
3) (Venkatraman) R A M A K R I S H N A N
4) (Doris) L E S S I N G
5) (Gabriel Garcia) M A R Q U E Z
Answer:
The 6 letters in the alphabet that do not stand for an amino acid are: B, J, O, U, X, Z.
So, David Baltimore (Physiology or Medicine, 1975) and Gabriel Garcia Marquez
(Literature, 1982) are NOT also peptides.
Ei-ichi Negishi (Chemistry, 2010), Venkataraman Ramakrishnan (Chemistry,
2009), and Doris Lessing (Literature, 2007) are also peptides (whether they know it or
not).
ii) (16 pts)
Pick ANY ONE of the last names given above that could be a peptide.
Draw the complete structure
of four consecutive residues from that last name, as a
tetrapeptide.
Your drawing must fit the following conditions:
a)
The amino acid that is the first letter
of the name must be at the amino terminus of
your peptide.
b)
Use the letters (amino acids) in the order (left-to-right) that they appear in the name,
but DO NOT use the same amino acid twice! Skip a repeated letter and use the next one.
c)
Do not use A
or G
(too simple!).
d)
Draw the peptide structure in the form that would predominate in a solution at pH = 7
.
e)
Write the 3-letter abbreviations of the four amino acids that you have drawn (fill in the
blanks, below).
The name that you chose: _____________
3-letter abbreviations: (N-term) - _____ - _____ - _____ - _____
Answer:
See the textbook for amino acid structures and 3 letter abbreviations. In addition
to points deducted for an incorrect structure or incorrect protonation, points were
deducted for: 1) an incorrect 3-letter abbreviation, 2) using A (alanine) and/or G
(glycine) in your structure, 3) the peptide did not start with the amino acid that
corresponds to the first letter in the last name, 4) a letter in the name that is an amino acid
was skipped and omitted from the peptide structure.
2
2. (5 points)
The table given below lists information about four proteins - proteins 1 - 4
. 1)
The last row in the table gives the number of protein chains in the native form of these
proteins.
2)
The second-to-the-last row gives the total number of amino acid residues in one chain
of each protein.
3)
The rest of the table lists the number of each amino acid residue in one chain
of each
protein.
protein 1
protein 2
protein 3
protein 4
Amino acid
#
#
#
#
Alanine
83
28
26
56
Arginine
44
34
12
26
Asparagine
29
22
21
3
Aspartic acid
59
25
22
19
Cysteine
4
11
3
3
Glutamic acid
36
40
25
19
Glutamine
26
21
10
6
Glycine
60
22
27
21
Histidine
14
11
11
12
Isoleucine
41
26
19
10
Leucine
65
40
26
25
Lysine
25
25
19
5
Methionine
19
13
8
7
Phenylalanine
23
20
13
6
Proline
34
23
11
14
Serine
34
25
13
17
Threonine
48
21
17
14
Tryptophan
10
0
4
3
Tyrosine
16
24
15
3
Valine
59
38
28
24
# residues:
729
469
330
293
# chains:
1
2
6
3
Suppose that you analyzed these four proteins by polyacrylamide gel electrophoresis in
the presence of SDS (SDS-PAGE). Which protein would move the farthest
in the gel? Explain
briefly how you decided.
Answer:
The individual chains of a protein separate when a protein is treated with SDS
(detergent) to be run on SDS-PAGE. The mobility of proteins in SDS-PAGE depends on
the molecular weight of their individual chains. The molecular weights of these proteins
is correlated with the number of amino acid residues in the individual chains.
Protein 4
has the fewest amino acids in each chain, so protein 4 runs farthest in
the gel.
3
3. (10 points)
The table given below lists information about three more proteins. The table
contents are the same as for the previous question.
protein A
protein B
protein C
Amino acid
#
#
#
Alanine
83
74
77
Arginine
44
21
57
Asparagine
29
25
8
Aspartic acid
59
27
23
Cysteine
4
11
6
Glutamic acid
36
41
58
Glutamine
26
14
18
Glycine
60
50
53
Histidine
14
17
15
Isoleucine
41
32
9
Leucine
65
50
76
Lysine
25
28
13
Methionine
19
9
7
Phenylalanine
23
16
33
Proline
34
30
55
Serine
34
15
24
Threonine
48
35
19
Tryptophan
10
9
22
Tyrosine
16
16
27
Valine
59
43
45
# residues:
729
563
645
# chains:
1
1
1
Estimated charges:
A B C
+44
+21
+57 (Arg)
!
59
!
27
!
23 (Asp)
!
0.4
!
1.1
!
0.6 (Cys)
!
36
!
41
!
58 (Glu)
+1.4
+1.7
+1.5 (His)
+25
+28
+13
(Lys)
!
25
!
18.4
!
10.1
:total charge
Suppose that you ran a mixture of these three proteins on an ion exchange
chromatography column in which the column beads are positively-charged
. Which protein
would elute last
from the column? Explain how you decided.
Answer:
The protein with the greatest net negative charge will elute last from the column.
Estimate the net charge on each protein by assuming that all Arg and Lys residues
are positively charged and all Asp and Glu are negatively charged, at pH 7. Each His has
an average charge of about +0.1 at pH 7, and each Cys has charge of !
0.1. The Tyr
residues can be ignored because they are almost completely protonated at pH = 7 and do
not contribute any significant charge. See estimates of the net charges given above.
Protein A
elutes last from the column since it has the greatest net negative
charge.
4
4. (5 points)
Here are the last four proteins. The table contents are the same as for the previous
two questions.
protein I
protein II
protein III
protein IV
Amino acid
#
#
#
#
Alanine
59
28
47
8
Arginine
36
20
16
16
Asparagine
34
13
30
6
Aspartic acid
47
16
24
15
Cysteine
12
1
14
1
Glutamic acid
42
21
35
21
Glutamine
28
16
13
7
Glycine
72
35
34
19
Histidine
24
2
18
8
Isoleucine
56
27
24
11
Leucine
64
43
49
30
Lysine
52
18
38
13
Methionine
10
8
11
9
Phenylalanine
23
8
27
13
Proline
42
11
26
18
Serine
38
14
49
17
Threonine
45
9
24
15
Tryptophan
9
7
3
2
Tyrosine
20
6
21
11
Valine
41
18
45
17
# residues:
754
321
548
257
# chains:
1
1
1
1
Suppose you have four aqueous solutions, each of which contains only one of the four
proteins. The protein concentrations are the same in the four solutions.
You measure the absorbance at 280 nm (A
280
)
of each solution.
Which protein solution would have the greatest
A
280
? Explain briefly how you decided.
Answer:
The relation of protein concentration (c) to A
280
is given by Beer’s law:
c = A
280
/
ε
280
.
The ε
280
of a protein is due to absorbance by the Trp and Tyr residues in the
protein, and Trp contributes greater absorbance than does Tyr.
The solution that contains Protein I would have the greatest A
280
.
5
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Madeline Carlo - CHM 112 HW DUE Monday April 12, 2021 ☆ D
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.1. Refer to the table of standard reduction potentials.
Standard Reduction Potentials at 25 C
Reduction Half-Reaction
(V)
FAg + 2 €
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Mno,taq) + 8 H*(aq) + 5 &
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Ozlg + 4 H*(aq) + 4 &
Bra() + 26
Ag*(aq) + e
Fe*(aq) + e
Ozl9) + 2 H'(aq) + 2 €
2(s)+ 26
Ozlg) + 2 HO) + 46
Cu (aq) + 2 €
Sn" (ag)+ 2 6
2 P(aq)
2 H2O()
→ Mn(aq) + 4 H;0()
→2 cr(aq)
2 Cr (aq)+ 7 H0()
→2 HO()
2 Br(aq)
Ag(s)
» Fe*(aq)
→H;Oz(aq)
→2 F(aq)
→4 OH"(aq)
2.87
1.78
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B
U A
G O O- E E E E E E - E - E E
14.5
3 4 5 6
You are asked to perform an experiment to determine the density of
square block below. In order to complete your calculations you will need
to
(AKS 1b, DOK1).
Question options:
1. Use the electronic balance to determine the mass of the block.
2. Use water displacement to determine the volume of the block.
bD
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Madeline Carlo - CHM 112 HW X
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Madeline Carlo - CHM 112 HW DUE Monday April 12, 2021 ☆ D
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III I
III 1 I
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3 1
I 4
5 II II
6 1
III |
MnO, (aq) + 8H*(aq) + 5e → Mn²*(aq) + 4 H,O(1)
Al(s) → Alš*(aq) + 3 e
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.ЗА.
Assign oxidation numbers to all metals whether they be elemental, monatomic ion, or in
a polyatomic ion, in questions (1) and (2),
.3B. Tell what is being oxidized and what is being reduced in each reaction in questions (1) and
(2).
.3C. Identify each half-reaction in question (2) as oxidation half-reaction or reduction
half-reaction.
.4. Do you need to know the temperature to calculate AG° from E°? Explain.
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Part c
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I am not asking for help in writing this report.
Could you solve the calculation parts for the steps on the last page? like 13, 14, 15, 17, 18, and 19.
This experiment is based on this video: https://www.youtube.com/watch?v=SVvGtcFhdls
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CHAPTER 1A - LET'S REVIEW: THE TOOLS OF QUANTITATIVE CHEMISTRY
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The aluminum in a package containing 77 ft" of kitchen foil weighs approximately 19 ounces. Aluminum has a density of 2.70 g/cm. What is the approximate thickness of
the aluminum foil in millimeters? (1 ounce =
28.4 g. 1 ft 12 in, 1 in = 2.54 cm)
%3D
Thickness =
mm
O US 3:2
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