Density Lab Report
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Determination of Density Lab
11
th
September 2023
Results
Table
1
.
Data for determination of the density of water.
Temperature of the water = 22
o
C
Trial
Mass of flask
empty (g)
Mass of
flask full
(g)
Mass of
water (g)
Initial
volume
(mL)
Final
volume
(mL)
Volume
of water
(mL)
Density
(g/mL)
1
48.6447 g
78.3417 g
29.6967 g
0.00 mL
30.0 mL
30.0 mL
0.98989 g/mL
2
48.6924 g
78.5527 g
29.8603 g
0.00 mL
30.0 mL
30.0 mL
0.99534 g/mL
3
48.6101 g
78.4841 g
29.8740 g
0.00 mL
30.0 mL
30.0 mL
0.99580 g/mL
Average density of water = 0.99368 g/mL
Precision = 5.9476 ppt
%Error = 0.41291%
Table 2.
Data for determination of the density of an unknown liquid.
Temperature of the unknown = 23
o
C.
Trial
Mass flask
empty (g)
Mass flask
full (g)
Mass of
unknown
(g)
Initial
volume
(mL)
Final
volume
(mL)
Volume of
unknown
(mL)
Density (g/mL)
1
48.6298 g
73.1011 g
24.4713 g
0.00 mL
30.0 mL
30.0 mL
0.81571 g/mL
2
48.7805 g
73.1114 g
24.3309 g
0.00 mL
30.0 mL
30.0 mL
0.81103 g/mL
3
48.5257 g
72.7266 g
24.2009 g
0.00 mL
30.0 mL
30.0 mL
0.80670 g/mL
4
47.5417 g
71.5814 g
24.0397 g
0.00 mL
30.0 mL
30.0 mL
0.80132 g/mL
Average density of Unknown = 0.
80869
g/mL
Precision = 17.794 ppt
Name of Unknown – 1 propanol
Unknown code – A
%Error = 18.933 %
`Calculations
The first calculation that needed to be done was to find the mass of just the water. That
was done by subtracting the mass of the flask with water from the mass of the empty flask.
In
trial 1 the mass of the water was 29.6967 g. In trial 2, the mass was to be found at 29.8603 g; for
trial 3, the mass of water was 29.8740 g. After that, the volume of the water needed to be found
which was 30.0 mL for all three trails. With both the mass of water and volume of water
calculated, the density can be found. Density is volume divided by mass. In trial 1 the density
was 0.98989 g/mall. This was calculated by dividing the 30.0 mL of water by 29.6967 g of water.
Trail 2 the density was 0.99534 and trail 3 the density was 0.99580. Since all three densities have
been calculated, the average density of water can be found. This is by adding all three densities
together and dividing it by 3. The average was 0.99368 g/mL. For Table 2 of the unknown liquid,
the same calculations were used to find the density of the unknown which came out to be
0.79711 g/mL. To calculate the precision in parts per thousand the lowest value gets subtracted
by the highest value and then the average gets divided by that number. Finally, it gets multiplied
by 1000. For Table 1, the lowest value was 0.98989 and the highest value was 0.99580. When
those were subtracted the number came out to be 0.00591. The average density of water which
was found earlier gets divided by this new number and came out to be 0.0059476. This then gets
multiplied by 1000 and the ppt came out to be 5.9476 ppt. These same calculations are done for
Table 2 and the precision for the unknown liquid was 17.794 ppt. The percent error for Table 1
was to be found at 0.41291%. This was done by subtracting the accepted value from the
observed value. The accepted value for the density of water at 22
o
C is 0.99780. 0.99780 was
subtracted by the observed value which was 0.99368 and came out to be 0.00412. This gets
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11 of 26
To how many significant figures should each answer be rounded?
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NG 2
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ID102
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ID112
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Express your answer in calories per gram per degree Celsius to two significant figures.
0.214
0.897
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Copper, Cu(s)
0.0920
0.385
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0.0308
0.129
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Compounds
Ammonia,
0.488
2.04
NH3 (s)
Part B Complete previous part(s)
Ethanol,
0.588
2.46
C2 H6 O(s)
Sodium chloride,
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0.207
0.864
NaCl(s)
Water, H2 O(1)
1.00
4.184
Water, H2 0(s) 0.485
2.03
4,419
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