A protein has a stability ranging from 6 to 15 kcal/mole at 37 OC. Stability is a measure of the equilibrium between the folded and unfolded protein given by the relationship; folded(F) = unfolded (U), k=[U]/[F] For a protein with a stability of 10 kcal/mole, calculate the fraction of unfolded protein that would exist at equilibrium at 37 OC. Use the following equation: GO=RTlnk=-2.3RTlog k, where R=1.98 x 10-3 kcal/mole and T is temperature in Kelvin (K) and k is the equilibrium constant.
A protein has a stability ranging from 6 to 15 kcal/mole at 37 OC. Stability is a measure of the equilibrium between the folded and unfolded protein given by the relationship; folded(F) = unfolded (U), k=[U]/[F] For a protein with a stability of 10 kcal/mole, calculate the fraction of unfolded protein that would exist at equilibrium at 37 OC. Use the following equation: GO=RTlnk=-2.3RTlog k, where R=1.98 x 10-3 kcal/mole and T is temperature in Kelvin (K) and k is the equilibrium constant.
Introduction to General, Organic and Biochemistry
11th Edition
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter23: Enzymes
Section: Chapter Questions
Problem 23.25P: 5 Which of the following is a correct statement describing the induced-fit model of enzyme action?...
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A protein has a stability ranging from 6 to 15 kcal/mole at 37 OC. Stability is a measure
of the equilibrium between the folded and unfolded protein given by the relationship;
folded(F) = unfolded (U), k=[U]/[F]
For a protein with a stability of 10 kcal/mole, calculate the fraction of unfolded protein
that would exist at equilibrium at 37 OC. Use the following equation:
GO=RTlnk=-2.3RTlog k,
where R=1.98 x 10-3
kcal/mole and T is temperature in Kelvin (K) and k is the
equilibrium constant.
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