Calculate the ΔG for Malate dehydrogenase reaction of CAC if the concentration of oxaloacetate is 1x 10-8 M, malate is 0.2 mM, NAD+ is 10 mM and NADH is 0.1 mM in rat liver mitochondria. ΔGo’ for this reaction is 30 kJ/mole. Please write the units of the final answer and the formula you are using to solve. R = 0.008314kJ/K*mol, T = 298K
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Calculate the ΔG for Malate dehydrogenase reaction of CAC if the concentration of oxaloacetate is 1x 10-8 M, malate is 0.2 mM, NAD+ is 10 mM and NADH is 0.1 mM in rat liver mitochondria. ΔGo’ for this reaction is 30 kJ/mole. Please write the units of the final answer and the formula you are using to solve.
R = 0.008314kJ/K*mol, T = 298K
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- For part (b) of this problem, use the following standard reduction potentials, free energies, and nonequilibrium concentrations of reactants and products: Consider the last two steps in the alcoholic fermentation of glucose by brewer’s yeast: pyruvate + NADH + 2H+ → ethanol + NAD+ + CO2 (a) Do you predict that ∆S° for this reaction is > 0 or < 0? (b) Calculate the nonequilibrium concentration of ethanol in yeast cells, if ∆G = -38.3 kJ/mol for this reaction at pH = 7.4 and 37 °C when the reactants and products are at the concentrations given above. (c) How would a drop in pH affect ∆G for the reaction described in part (b)? (d) How would an increase in intracellular CO2 levels affect ∆G for the reaction in part (b)? (e) How would an increase in intracellular CO2 levels affect ∆G°′ for the reaction in part (b)?Compare the delta ΔG0' values for the oxidation of succinate by NAD+ and by FAD. Use the data given in Table 18.1 to find the E0' of the NAD+-NADH and fumarate-succinate couples, and assume that E0' for the FAD – FADH2 redox couple is nearly 0.05 V. Why is FAD rather than NAD+ the electron acceptor in the reaction catalyzed by succinate dehydrogenase?Given the following information, calculate the physiological ΔG of the isocitrate dehydrogenase reaction at 25°C and pH 7.0: [NAD+]/[NADH] = 8, [α-ketoglutarate] = 0.1 mM, and [isocitrate] = 0.02 mM. Assume standard conditions for CO2 (ΔG°′ is given in Table). Is this reaction a likely site for metabolic control?
- The half-reactions involved in the lactate dehydrogenase (LDH) reaction and their standard reduction potentials are (see attached)). Calculate ΔG at pH 7.0 for the LDH-catalyzed reduction of pyruvate under the following conditions: (a) [lactate]/[pyruvate] = 1 and [NAD+]/[NADH] = 1. (b) [lactate]/[pyruvate] = 160 and [NAD+]/[NADH] = 160. (c) [lactate]/[pyruvate] = 1000 and [NAD+]/[NADH] = 1000. (d) Discuss the eff ect of the concentration ratios in Parts a–c on the direction of the reaction.The complete combustion of palmitate and glucose yields 9781 kJ ∙ mol−1 and 2850 kJ ∙ mol−1 of free energy, respectively. Compare these values to the free energy (as ATP) obtained though catabolism of palmitate and glucose under standard conditions. Which process is more efficient?The standard free energy change for the reaction catalyzed by phosphoglucomutase is -7.1kJ/mol, (a) calculate ΔG at 37°C when the concentration of glucose-1-phosphate is 1-mM and the concentration of glucose-6-phosphate is 25-mM, (b) Is the reaction spontaneous under these conditions?
- Your current Vmax (4x10-3 A/S) from the Michaelis-Menten plot has the units of A/s and was determined using 0.1 mg of ADH in a total volume of 1.25 mL. Use the Beer-Lambert equation followed by simple conversion to express your estimated Vmax in (mol )/s per 1 mg ADH. The molar absorptivity of NADH at 340 nm is 6220 L/(mol*cm).Calculate the standard free-energy change of the reaction catalyzed by theenzyme phosphoglucomutase, given that, starting with 20 mM glucose 1-phosphate and no glucose 6- phosphate, the final equilibrium mixture at 25 °C and pH 7.0 contains 1.0 mM glucose 1-phosphate and 19 mM glucose 6-phosphate. Does the reaction in the direction of glucose 6-phosphate formation proceed with a loss or a gain of free energy?One process catalyzed by NADHNADH dehydrogenase is NADH+H^++ubiquinone ↽−−⇀ NAD+ubiquinolNADH+H^++ubiquinone ↽−−⇀ NAD^++ubiquinol The standard reduction potentials for the half‑reactions are given in the table. Oxidant Reductant ?′0 ubiquinone+2H++2e−ubiquinone+2H++2e^− ubiquinolubiquinol 0.045 NAD^++H^++2e−NAD^++H^++2e^− NADHNADH –0.32 Calculate Δ?′0 for the reaction as shown. Δ?′0=____(V) Calculate Δ?′0 . Δ?′0=____(kJ/mol)
- Begining with 1 M concentrations of each reactant and product at pH=7 and 25.0 degrees C, calculate the K'eq (to one decimal point) of the reaction Pyruvate + NADH+H+ <=> Lactate + NAD+.Note the temperature of this reaction will not affect the standard reducton potential delta E'o in the table 13-7b. please provide a comprehensive explanation with each step taken.The Keq (25C) of the reaction below is 635.67. Fructose 1,6-biphosphate <-->fructose -6-phosphate + Pi. a) What is the standard Gibbs free energy change for this reaction? b) if the concentrationof fructose 1,6 biphosphate is adjusted to 0.85 M and that of fructose 6 phosphate and phosphate adjusted to 0.055 M, what is the actual free energy changeWrite a balanced equation for each of the following reactions or reaction sequences. (a) The reaction catalyzed by PFK-2 (b) The conversion of 2 moles of oxaloacetate to glucose (c) The conversion of glucose to UDP-Glc (d) The conversion of 2 moles of glycerol toglucose (e) The conversion of 2 moles of malate to glucose-6-phosphate