Question
Asked Dec 7, 2019
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Calculate the flux of energy arising from a temperature gradient of 10.5 K·m−1 in a sample of carbon dioxide in which the mean temperature is 280. K (Assume κ280. K = 7.05 ✕ 10−3 J·K−1·m−1·s−1).

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Expert Answer

Step 1

Given information in the problem:

Temperature gradient in sample of carbon dioxide = 10.5 K.m-1

Mean temperature of Carbon dioxide sample = 280 K

Thermal conductivity (K280K = 7.05*10-3 J.K-1m-1.s-1)

Step 2

Flux can be def...

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Image Transcriptionclose

Rate of energy trans ferred Flux=. Area Flux=2 dT :-K- dX

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