Determine the amino acid sequence of Peptide A, which was obtained by hydrolyzing a larger peptide with trypsin, using the data below: Total hydrolysis of Peptide A produces (Ala2, Arg, Glu, Gly, Met, Pro2, Ser, Tyr). Sequential Edman degradation of Peptide A produces a derivative of Ala in the first cycle; a derivative of Serine in the second cycle; and a derivative of Proline in the third cycle. Cleavage of Peptide A with chymotrypsin yields two peptides: a tripeptide III containing Ala, Arg and Gly; and a heptapeptide IV containing Ala, Glu, Met, Pro2, Ser and Tyr. Edman treatment of tripeptide III generated a derivative of Alanine. Cleavage of Peptide A with cyanogen bromide (which cleaves peptides on the C-terminal side of Methionine) yields two pentapeptides labeled I and II. Total hydrolysis or peptide I indicate that it contains Ala, Arg, Gly, Pro and Tyr; pentapeptide II contains Ala, Glu, Met, Pro, and Ser.

Biochemistry
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Chapter1: Biochemistry: An Evolving Science
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Determine the amino acid sequence of Peptide A, which was obtained by hydrolyzing a larger peptide with trypsin, using the data below:

Total hydrolysis of Peptide A produces (Ala2, Arg, Glu, Gly, Met, Pro2, Ser, Tyr).

Sequential Edman degradation of Peptide A produces a derivative of Ala in the first cycle; a derivative of

Serine in the second cycle; and a derivative of Proline in the third cycle.

Cleavage of Peptide A with chymotrypsin yields two peptides:

a tripeptide III containing Ala, Arg and Gly;

and a heptapeptide IV containing Ala, Glu, Met, Pro2, Ser and Tyr.

Edman treatment of tripeptide III generated a derivative of Alanine.

Cleavage of Peptide A with cyanogen bromide (which cleaves peptides on the C-terminal side of Methionine)

yields two pentapeptides labeled I and II. Total hydrolysis or peptide I indicate that it contains Ala, Arg, Gly, Pro and Tyr; pentapeptide II contains Ala, Glu, Met, Pro, and Ser. 

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