P. 1. Assume that we would like to expand the RISC-V register file to 128 registers and expane the instruction set to contain four times as many instructions. a) How would this affect the size of each of the bit fields in the R-type instructions ? b) How would this affect the size of each of the bit fields in the I-type instructions? c) How could each of the two proposed changes decrease the size of a RISC-V assembly program? On the other hand. how could the proposed change increase the size of an RISC-V assembly program?

P. 1. Assume that we would like to expand the RISC-V register file to 128 registers and expane the instruction set to contain four times as many instructions. a) How would this affect the size of each of the bit fields in the R-type instructions ? b) How would this affect the size of each of the bit fields in the I-type instructions? c) How could each of the two proposed changes decrease the size of a RISC-V assembly program? On the other hand. how could the proposed change increase the size of an RISC-V assembly program?

Systems Architecture

7th Edition

ISBN:9781305080195

Author:Stephen D. Burd

Publisher:Stephen D. Burd

Chapter4: Processor Technology And Architecture

Section: Chapter Questions

Problem 2PE: If a microprocessor has a cycle time of 0.5 nanoseconds, what’s the processor clock rate? If the...

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For the MIPS assembly instructions below, what is thecorresponding C statement? Assume that the variables f, g, h, i, and j areassigned to registers $s0, $s1, $s2, $s3, and $s4, respectively. Assume thatthe base address of the arrays A and B are in registers $s6 and $s7,respectively. Note: for each line of MIPS code below, write the respective Ccode. After that, write the corresponding C code for the MIPS.sll $t0, $s0, 2add $t0, $s6sll $t1, $s1, 2 add $t1, $s7, $t1lw $s0, 0($t0)addi $t2, $t0, 4lw $t0, 0($t2)add $t0, $t0, $s0sw $t0, 0($t1)
Consider the following store instruction: SW R1, 0x000F(R0). Assume that the registers R0 and R1 are initialized with 0x00000001 and 0x53A78BC Frespectively. A section of the MIPS byte addressable data memory is shown. Give the memory word of the following memory locations after the SW operation: (a). 0x00000015. (b). 0x00000014. (c). 0x00000013. (d) 0x00000012.(e). 0x00000011. (f). 0x00000010.
5. Consider two microprocessors having 8- and 16-bit-wide external data buses, respectively. The two processors are identical otherwise and their bus cycles take just as long. (a) Suppose all instructions and operands are one byte long, by what factor do the maximum data transfer rates differ?
For the MIPS assembly instructions below, what is the corresponding C statement?Assume that the variables f, g, h, i, and j are assigned to registers $s0, $s1, $s2, $s3, and$s4, respectively. Assume that the base address of the arrays A and B are in registers $s6 and $s7, respectively. sll $t1, $s1, 2add $t1, $t1, $s6lw $t1, 0($t1)sub $t0, $s3, $s4sll $t0, $t0, 2add $t0, $t0, $s7lw $t0, 0($t0)add $t1, $t1, $t0sll $t0, $s0, 2add $t0, $t0, $s7sw $t1, 0($t0)
6. Assume that two numbers: dividend and divisor are saved in memory address M1 and M2 respectively. Quotient and remainder should be saved in R1 and R2 respectively. Write assembly language instructions and then list microoperations for each instruction and list the control signals required to be activated for each microoperation. MBR is used as buffer for any register to register transfer operation. Signal Description: Control signals operation Comments C0 MAR to RAM (through address bus) C1 PC to MBR C2 PC to MAR C3 MBR to PC C4 MBR to IR C5 RAM to MBR C6 MBR to ALU C7 Accumulator to ALU C8 IR to MAR C9 ALU to Accumulator C10 MBR to Accumulator C11 Accumulator to MBR C12 MBR to RAM (through data bus) C13 IR to Control Unit C14 MBR to R1 C15 MBR to R2 C16 MBR to R3 C17 MBR to R4…
I have a little bit problem with my late quiz for computer architecture, I get the answer from my lecturer but I still don't feel fully understand, can I ask for some help: In a computer system, the memory has 32 blocks and the cache has 8 blocks. Assume there is only one word per block with 4 bytes in one word. The reference sequence in terms of word location is 0, 2, 4, 10, 5, 12, 8, 18, 13. If the cache is direct-mapped, how many misses do we have if the cache is initially empty? Can you give the hit or miss for each reference?
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1. Name all of the general purpose registers and some of their special functions. 2. How are the segment registers used to form a 20-bit address? 3. (a) If CS contains 03E0H and IP contains 1F20H, from what address is the next instruction fetched? (b) If SS contains 0400H and SP contains 3FFEH, where is the top of the stack located? (c) If a data segment deigns at address 24000H, what is the address of the last location in the segment? 4. Explain what the instruction array and data caches are used for. 5. What is the EU and BIU, and what purpose in the microcomputer? 6. Two memory locations, beginning at address 3000H, contain the bytes 34H and 12H. What is the word stored at location 3000H? See Figure 2.26 for details. Address 3000 Data 34 3001 12 Figure 2.26 For question 6 7. What is a physical address? What are the differences between the 8086 logical and physical memory maps? 8. May memory segments overlap? If so, what is the minimum number of overlapped bytes…
Please look at the whole document and show all work and steps. Please solve and show work. What is the corresponding MIPS assembly code for the following C statement? Assume that the variables f, g, h, i, and j are assigned to register $s0, $s1, $s2, $s3, and $s4, respectively. Assume that the base address of the arrays A and B are in registers $s6 and $s7, respectively. B[8] = A[i−j] Translate the following C code to MIPS. Assume that the variables f, g, h, i, and j are assigned to register $s0, $s1, $s2, $s3, and $s4, respectively. Assume that the base address of the arrays A and B are in registers $s6 and $s7, respectively. Assume that the elements of the arrays A and B are 8-byte words: B[8] = A[i] + A[j] Assume that registers $s0 and $s1 hold the values 0x80000000 and 0xD0000000, respectively. What is the value of $t0 for the following assembly code? add $t0, $s0, $s1 Is the result in $t0 the desired result, or has there been an overflow? For the contents of registers $s0…
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