Provide brief well focused  responses to the following questions. a.Why is Δo for the [Cr(CN)6]3-  anion very much larger than Δo   for [CrCl6]3-?b.Qualitatively compare the expected μeff (298K) values for the octahedral complex anions  [CrCl6]3-  and [Cr(CN)6]3-  .c.The [CoCl4]2- anion is intensely  blue colored and [CoCl6]4- is a lightly colored pink.d.Why is the method of descending symmetry needed to derive an mo diagram for acetylene (ethyne), but not needed for diazene((NH)2)?e.Why is IR spectroscopy an ineffective method for vibrational studies of homo-nuclear diatomic molecules in the gas phase ?

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Asked Apr 17, 2019
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Provide brief well focused  responses to the following questions. 

a.Why is Δo for the [Cr(CN)6]3-  anion very much larger than Δo   for [CrCl6]3-?

b.Qualitatively compare the expected μeff (298K) values for the octahedral complex anions  [CrCl6]3-  and [Cr(CN)6]3-  .

c.The [CoCl4]2- anion is intensely  blue colored and [CoCl6]4- is a lightly colored pink.

d.Why is the method of descending symmetry needed to derive an mo diagram for acetylene (ethyne), but not needed for diazene((NH)2)?

e.Why is IR spectroscopy an ineffective method for vibrational studies of homo-nuclear diatomic molecules in the gas phase ?

 

 

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Expert Answer

Step 1

(a)Ligands in complex compound decide the energy gap between metal orbital.  Stronger the ligand, greater the repulsion between orbitals and larger the Δo value.  Weaker the ligand, lesser the repulsion between orbital and smaller the Δo.  In the given chromium complex [Cr(CN)6]3-,  cyanide is the strong field ligand which separates metal orbitals and have larger Δo value.  While [CrCl6]3- has weak ligand chlorine.  Hence, Δfor the [Cr(CN)6]3-  anion very much larger than Δo   for [CrCl6]3-.

Step 2

(b)Both [Cr(CN)6]3- and [CrCl6]3-  complexes have three d-electrons each which are occupied in t2g orbitals. ...

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