W Practice 4 - CHEM 1201 Xco Course: 2020 Spring CHEMb My Questions | bartlebyA https://www.webassign.net/web/Student/Assignment-Responses/randomize?pos=4&dep=22671454&tags=autosave#question359784_4...5.0/0 POINTSPREVIOUS ANSWERS5/100 Submissions UsedMY NOTESASK YOUR TEACHERChoose the selection which correctly characterizes all three of the following substances in terms of whether they are polar or nonpolar:IF5 and NH3 and SiF4O a) IFs is polar and NH3 is polar and SiF4 is polar.O b) IF5 is nonpolar and NH3 is polar and SIF4 is polar.O c) IF5 is polar and NH3 is polar and SİF4 is nonpolar.O d) IF5 is polar and NH3 is nonpolar and SIF4 is polar.O e) IF5 is nonpolar and NH3 is polar and SİF4 is nonpolar.6.0/0 POINTSPREVIOUS ANSWERS2/100 Submissions UsedMY NOTESASK YOUR TEACHERChoose the selection which correctly identifies the sets of hybrid orbitals used by central atoms to form bonds in both of the molecules and/or ions whose formulas are given below:PCI3 and HCN3:46 AMO Type here to search4/10/2020

Please find below the structures of all the 3 molecules

Answered: W Practice 4 - CHEM 1201 X co Course:…

Appl Of Ms Excel In Analytical Chemistry

2nd Edition

ISBN:9781285686691

Author:Crouch

Publisher:Crouch

Chapter4: Least-squares And Calibration Methods

Section: Chapter Questions

Problem 12P

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can you answer, please? the experimental data are Reference: https://www.youtube.com/watch?v=OOXRkycKEOc&feature=youtu.be and https://www.youtube.com/watch?v=3wLJLm0QLpg&feature=youtu.be
Show all steps leading to the final answer po. Here’s a pdf file in accordance with the topic po: https://drive.google.com/file/d/1_FnDtXCrFKSol3RNWIG_9tNQ7IxgxD6t/view?usp=drivesdk
the following experiment is reference from this video link, they are the first 2 experiments ; reference https://www.youtube.com/watch?v=NFTBOIvTLtI
NH4+ {aq) + NO2(aq) -> N2(g) +2H2O{l} Data Initial [NH4+] Initial [NO2-] rate 1 0.0100 0.200 5.4 x10-7 2 0.0200 0.200 10.8x10-7 3 0.0400 0.200 21.5x10-7 4 0.200 0.0202 10.8x10-7 5 0.200 0.0404 21.6x10-7 6 0.200 0.0808 43.3x10-7 Find x,y,k
Please check my observations from the lab worksheet and watch the video. Accordingly, answer the questions . Link to lab Video: https://drive.google.com/file/d/1BR55ITa7wyOLgLy-MT6ogeXp-fiyuTHn/view?usp=sharing Link to calculated observations: https://drive.google.com/file/d/1zQ952X4N6hOgoToBF_o0zRARScwe54WH/view?usp=sharing Questions:
Please answer super fast and answer all questions and show calculations For the image attached For 1. a Mass of metal: Trial 1 is 35.0228 g Trial 2 is 35.0915 g Trial 3 is 34.0821 g Mass of water: Trial 1 is 20.0177 g Trial 2 is 20.0250 g Trial 3 is 20.0168 g For delta t of water: Trial 1 is 15.5 C Trial 2 is 15.7 C Trial 3 is 15.1 C For delta t of metal Trial 1 is 80.1 C Trial 2 is 80.2 C Trial 3 is 79.5 C For B my calculated Specific heat is: Trial 1 is 0.462 Trial 2 is 0.467 Trial 3 is 0.466
If 5 µM enzyme was used to obtain the data in the summary plot below, V-max = ________________ µM sec-1 and Km = ____________ µM for this enzyme (Enter numeric values to the nearest integer; Do NOT write units.)
Ee.15. With full details....
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There's 1 drink (and you are asked to determine the glucose concentration in the drink in the units of g/100mL. (Why these units? Well, once you have the concentrations in g/100mL you will be able to compare your values with the nutritional values given on the drink bottles’ labels). The sample of the drink was diluted 1/100 (i.e. by a factor of 100). This was an essential step in the method because, without it, the machine used to analyse the glucose concentration (spectrophotometer) would have given an error as the concentration would have been too high for accurate detection. What this means for you is that the dilution factor will need to be taken into consideration in your calculations (remember the aim is to calculate the concentration in the original drink and not in the diluted drink). You measured the concentration of their diluted drink using the spectrophotometer and their results were provided to them in the units mM (millimolar). Glucose Concentration in mM of drink =…
There's 1 drink (and you are asked to determine the glucose concentration in the drink in the units of g/100mL. (Why these units? Well, once you have the concentrations in g/100mL you will be able to compare your values with the nutritional values given on the drink bottles’ labels). The sample of the drink was diluted 1/100 (i.e. by a factor of 100). This was an essential step in the method because, without it, the machine used to analyse the glucose concentration (spectrophotometer) would have given an error as the concentration would have been too high for accurate detection. What this means for you is that the dilution factor will need to be taken into consideration in your calculations (remember the aim is to calculate the concentration in the original drink and not in the diluted drink). You measured the concentration of their diluted drink using the spectrophotometer and their results were provided to them in the units mM (millimolar). Glucose Concentration in mM of drink =…
Benzene is dissolved at a constant initial concentration of 350 mg/l and is contained within a landfill in leachate water above bottom liner of the landfill system. It starts to diffuse through the liner at time t = 0. Using Equation Ci (x,t) = Co erfc x/ 2(D*t)0.5 related narrative, and (error function table), calculate the concentration of benzene at its breakthrough location as it diffuses through a 1.5 meter thick liner (x=1.5 meters represents breakthrough location where liner fails of contaminant is released), after 50 years. Assume D = 10-5 m2/sec (diffusion coefficient in free standing water) and w = 0.7 (coefficient of tortuousity). Clearly present your assumptions and your value of erf, Select the answer range which best fits the answer you calculate. Group of answer choices 315 to 350 mg/l My answer is not in the range of any of the choices my answer. 215 to 314 mg/l 175 to 200 mg/l 370 to 400 mg/l

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