Glencoe Physics: Principles and Problems, Student Edition
Glencoe Physics: Principles and Problems, Student Edition
1st Edition
ISBN: 9780078807213
Author: Paul W. Zitzewitz
Publisher: Glencoe/McGraw-Hill
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Question
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Chapter 1, Problem 40A

(a)

To determine

The equivalent value of addition of 16.2m+5.008m+13.48m .

(a)

Expert Solution
Check Mark

Answer to Problem 40A

  34.7m

Explanation of Solution

Given:

  16.2m+5.008m+13.48m

Calculation:

For the addition of decimals,

Write down the numbers one under the other such that their decimal points are lined up. Then add zeros at the end of the numbers so that each number has same length. Finally, add the numbers using column addition and put the decimal point in the appropriate place in the answer.

Find the addition of 16.2m+5.008m+13.48m as follows:

  16.2m5.008m+13.480m_34.688m_

Round off the result to the least precise value among the measurement-the smallest number of digits to the right of decimal points.

Among the given numbers, the least precision value is 16.2m as it has one digit to the right of the decimal point.

The sum is only precise as the least precise number being added.

Hence, the result of the sum is rounded off to 34.7m .

Conclusion:

Hence, the addition of 16.2m+5.008m+13.48m is equal to 34.7m .

(b)

To determine

The equivalent value of addition of 5.006m+12.0077m+8.0084m .

(b)

Expert Solution
Check Mark

Answer to Problem 40A

  25.022m

Explanation of Solution

Given:

  5.006m+12.0077m+8.0084m

Calculation:

For the addition of decimals,

Write down the numbers one under the other such that their decimal points are lined up. Then add zeros at the end of the numbers so that each number has same length. Finally, add the numbers using column addition and put the decimal point in the appropriate place in the answer.

Find the addition of 5.006m+12.0077m+8.0084m as follows:

  5.006m12.0077m+8.0084m_25.0221m_

Round off the result to the least precise value among the measurement-the smallest number of digits to the right of decimal points.

Among the numbers, the least precision value is 5.006m as it has only three digits to the right of decimal point.

The sum is only precise as the least precise number being added.

Hence, the result of the sum is rounded off to 25.022m .

Conclusion:

Hence, the addition of 5.006m+12.0077m+8.0084m is equal to 25.022m .

(c)

To determine

The equivalent value of subtraction of 78.05cm232.046cm2 .

(c)

Expert Solution
Check Mark

Answer to Problem 40A

  46.00cm2

Explanation of Solution

Given:

  78.05cm232.046cm2

Calculation:

For the subtraction of decimals,

Write down the numbers one under the other such that their decimal points are lined up. Then add zeros at the end of the numbers so that each number has same length. Finally, subtract the numbers using column subtraction and put the decimal point in the appropriate place in the answer.

Find the subtraction of 78.05cm232.046cm2 as follows:

  78.05cm232.046cm2_46.004cm2_

Round off the result to the least precise value among the measurement-the smallest number of digits to the right of decimal points.

Among the measurements, the least precision value is 78.05cm2 as it has only two digits to the right of the decimal point.

The subtraction is only precise as the least precise number being involved in subtraction.

Hence, the result of the subtraction is rounded off to 46.00cm2 .

Conclusion:

Hence, the subtraction of 78.05cm232.046cm2 is equal to 46.00cm2 .

(d)

To determine

The equivalent value of subtraction of 15.07kg12.0kg .

(d)

Expert Solution
Check Mark

Answer to Problem 40A

  3.1kg .

Explanation of Solution

Given:

  15.07kg12.0kg

Calculation:

For the subtraction of decimals,

Write down the numbers one under the other such that their decimal points are lined up. Then add zeros at the end of the numbers so that each number has same length. Finally, subtract the numbers using column subtraction and put the decimal point in the appropriate place in the answer.

Find the subtraction of 15.07kg12.0kg as follows:

  15.07kg12.0kg_3.07kg_

Round off the result to the least precise value among the measurement-the smallest number of digits to the right of decimal points.

Among the measurements, the least precision value is 12.0kg as it has only one digit to the right of decimal point.

The subtraction is only precise as the least number being involved in subtraction.

Hence, the result of the subtraction is rounded off to 3.1kg .

Conclusion:

Hence, the subtraction of 15.07kg12.0kg is equal to 3.1kg .

Chapter 1 Solutions

Glencoe Physics: Principles and Problems, Student Edition

Ch. 1.2 - Prob. 11SSCCh. 1.2 - Prob. 12SSCCh. 1.2 - Prob. 13SSCCh. 1.2 - Prob. 14SSCCh. 1.3 - Prob. 15SSCCh. 1.3 - Prob. 16SSCCh. 1.3 - Prob. 17SSCCh. 1.3 - Prob. 18SSCCh. 1.3 - Prob. 19SSCCh. 1.3 - Prob. 20SSCCh. 1.4 - Prob. 21PPCh. 1.4 - Prob. 22SSCCh. 1.4 - Prob. 23SSCCh. 1.4 - Prob. 24SSCCh. 1.4 - Prob. 25SSCCh. 1.4 - Prob. 26SSCCh. 1 - Prob. 27ACh. 1 - Prob. 28ACh. 1 - Prob. 29ACh. 1 - Prob. 30ACh. 1 - Prob. 31ACh. 1 - Prob. 32ACh. 1 - Prob. 33ACh. 1 - Prob. 34ACh. 1 - Prob. 35ACh. 1 - Prob. 36ACh. 1 - Prob. 37ACh. 1 - Prob. 38ACh. 1 - Prob. 39ACh. 1 - Prob. 40ACh. 1 - Prob. 41ACh. 1 - Prob. 42ACh. 1 - Prob. 43ACh. 1 - Prob. 44ACh. 1 - Prob. 45ACh. 1 - Prob. 46ACh. 1 - Prob. 47ACh. 1 - Prob. 48ACh. 1 - Prob. 49ACh. 1 - Prob. 50ACh. 1 - Prob. 52ACh. 1 - Prob. 53ACh. 1 - Prob. 54ACh. 1 - Prob. 55ACh. 1 - Prob. 56ACh. 1 - Prob. 57ACh. 1 - Prob. 58ACh. 1 - Prob. 59ACh. 1 - Prob. 60ACh. 1 - Prob. 61ACh. 1 - Prob. 62ACh. 1 - Prob. 63ACh. 1 - Prob. 64ACh. 1 - Prob. 65ACh. 1 - Prob. 66ACh. 1 - Prob. 67ACh. 1 - Prob. 68ACh. 1 - Prob. 69ACh. 1 - Prob. 70ACh. 1 - Prob. 71ACh. 1 - Prob. 72ACh. 1 - Prob. 73ACh. 1 - Prob. 74ACh. 1 - Prob. 75ACh. 1 - Prob. 76ACh. 1 - Prob. 77ACh. 1 - Prob. 78ACh. 1 - Prob. 79ACh. 1 - Prob. 80ACh. 1 - Prob. 81ACh. 1 - Prob. 82ACh. 1 - Prob. 83ACh. 1 - Prob. 84ACh. 1 - Prob. 85ACh. 1 - Prob. 86ACh. 1 - Prob. 87ACh. 1 - Prob. 88ACh. 1 - Prob. 89ACh. 1 - Prob. 90ACh. 1 - Prob. 92ACh. 1 - Prob. 1STPCh. 1 - Prob. 2STPCh. 1 - Prob. 3STPCh. 1 - Prob. 4STPCh. 1 - Prob. 5STPCh. 1 - Prob. 6STPCh. 1 - Prob. 7STPCh. 1 - Prob. 8STP
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