Chapter 1, Problem 56A

Interpretation Introduction

Interpretation:

The average maximum area of the ozone hole needs to be determined between the given years.

Concept introduction:

Visual display of data is defined as a graph. By using the given data, a student can create graph. Graph helps to understand any data easily.

Answer to Problem 56A

The average maximum area of the ozone hole between the years $2005$ and $2009$ is $\text{25}\text{.04}$.

The average maximum area of the ozone hole between the years $2000$ and $2004$ is $23.92$.

The average maximum area of the ozone hole between the years $1995$ and $1999$ is $23.38$.

Explanation of Solution

The graph represents the data of ozone depletion which is divided between years and area. Area is given in million kilometers square. According to the graph,

The ozone hole between the years $2005$ and $2009$ :

$\text{Average = }\frac{\text{Sum}\text{of}\text{given}\text{data}}{\text{Count}\text{of}\text{given}\text{data}}$ $\text{= }\frac{125.2}{5}=25.04$

Hence, the average is $\text{25}\text{.04}$.

The ozone hole between the years $2000$ and $2004$ :

$\text{Average = }\frac{\text{Sum}\text{of}\text{given}\text{data}}{\text{Count}\text{of}\text{given}\text{data}}$ $\text{= }\frac{119.6}{5}=23.92$

Hence, the average is $23.92$.

The ozone hole between the years $1995$ and $1999$ :

$\text{Average = }\frac{\text{Sum}\text{of}\text{given}\text{data}}{\text{Count}\text{of}\text{given}\text{data}}$ $\text{= }\frac{116.9}{5}=23.38$

Hence, the average is $23.38$.

Conclusion

The average maximum area of the ozone hole,

Between the years $2005$ and $2009$ $\text{= 25}\text{.04}$.

Between the years $2000$ and $2004$ $\text{=<mn>23.92</mn>}$.

Between the years $1995$ and $1999$ $\text{=<mn>23.38</mn>}$.