Organic Chemistry
Organic Chemistry
5th Edition
ISBN: 9780078021558
Author: Janice Gorzynski Smith Dr.
Publisher: McGraw-Hill Education
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Chapter 10, Problem 10.44P
Interpretation Introduction

Interpretation: The melting point of elaidic acid is to be compared with the melting points of stearic and oleic acids.

Concept introduction: Fatty acids are of two types: saturated fatty acid and unsaturated fatty acid. In Saturated fatty acid, double bond is absent, whereas unsaturated fatty acid consists of one or more than one double bond. The melting point of a fatty acid indirectly depends upon the number of double bond present in an acid. Higher is the number of double bonds in an acid, lower will be the melting point of that acid.

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The first double bond in an unsaturated fatty acid is typically found: A) between the C9 and C10 positions B) conjugated to the carbonyl C) in the trans configuration D) at the omega position E) in palmitic acid
As we saw in Section 4.15, oleic acid has one C=C double bond that is in the cis configuration. Elaidic acid is identical to oleic acid, but the C=C is in the trans configuration. Which fatty acid has the higher melting point? Explain.
How would you expect the melting point of eicosapentaenoic acid[CH3CH2(CH=CHCH2)5(CH2)2COOH] to compare with the melting points of the fatty acids listed in attached file

Chapter 10 Solutions

Organic Chemistry

Ch. 10 - Linolenic acidTable 10.2 and stearidonic acid are...Ch. 10 - Prob. 10.12PCh. 10 - Problem 10.13 What product is formed when each...Ch. 10 - Prob. 10.14PCh. 10 - Problem 10.15 Draw the products formed when each...Ch. 10 - Prob. 10.16PCh. 10 - Prob. 10.17PCh. 10 - Addition of HBr to which of the following alkenes...Ch. 10 - Problem 10.19 Draw the products, including...Ch. 10 - Prob. 10.20PCh. 10 - Problem 10.21 What two alkenes give rise to each...Ch. 10 - Prob. 10.22PCh. 10 - Problem 10.23 Draw the products of each reaction,...Ch. 10 - Problem 10.24 Draw all stereoisomers formed in...Ch. 10 - Prob. 10.25PCh. 10 - Problem 10.26 What alkylborane is formed from...Ch. 10 - Draw the products formed when each alkene is...Ch. 10 - What alkene can be used to prepare each alcohol as...Ch. 10 - Prob. 10.29PCh. 10 - Draw the products of each reaction using the two...Ch. 10 - Problem 10.31 Devise a synthesis of each compound...Ch. 10 - Give the IUPAC name for each compound. a.b.Ch. 10 - a Label the carbon-carbon double bond in A as E or...Ch. 10 - Prob. 10.34PCh. 10 - 10.35 Calculate the number of degrees of...Ch. 10 - Prob. 10.36PCh. 10 - Label the alkene in each drug as E or Z....Ch. 10 - Give the IUPAC name for each compound. a. c. e. b....Ch. 10 - Prob. 10.39PCh. 10 - 10.40 (a) Draw all possible stereoisomers of, and...Ch. 10 - Prob. 10.41PCh. 10 - 10.42 Now that you have learned how to name...Ch. 10 - Prob. 10.43PCh. 10 - Prob. 10.44PCh. 10 - Prob. 10.45PCh. 10 - Draw the products formed when (CH3)2C=CH2 is...Ch. 10 - What alkene can be used to prepare each alkyl...Ch. 10 - Prob. 10.48PCh. 10 - Draw the constitutional isomer formed in each...Ch. 10 - Prob. 10.50PCh. 10 - Draw all stereoisomers formed in each reaction. a....Ch. 10 - Draw the products of each reaction, including...Ch. 10 - Prob. 10.53PCh. 10 - Prob. 10.54PCh. 10 - Prob. 10.55PCh. 10 - 10.56 Draw a stepwise mechanism for the following...Ch. 10 - Prob. 10.57PCh. 10 - Draw a stepwise mechanism for the conversion of...Ch. 10 - Draw a stepwise mechanism that shows how all three...Ch. 10 - Less stable alkenes can be isomerized to more...Ch. 10 - Prob. 10.61PCh. 10 - Prob. 10.62PCh. 10 - Bromoetherification, the addition of the elements...Ch. 10 - Devise a synthesis of each product from the given...Ch. 10 - 10.65 Draw a synthesis of each compound from...Ch. 10 - 10.66 Explain why A is a stable compound but B is...Ch. 10 - Prob. 10.67PCh. 10 - Prob. 10.68PCh. 10 - 10.69 Lactones, cyclic esters such as compound A,...Ch. 10 - 10.70 Draw a stepwise mechanism for the following...Ch. 10 - 10.71 Like other electrophiles, carbocations add...Ch. 10 - 10.72 Draw a stepwise mechanism for the...
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