BIOCHEMISTRY 2 TERM ACCESS
9th Edition
ISBN: 9781319402877
Author: BERG
Publisher: MAC HIGHER
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Question
Chapter 10, Problem 15P
Interpretation Introduction
Interpretation:
A double-reciprocal plot for a typical Michaelis-Menten enzyme and an allosteric enzyme that have the same
Concept introduction:
The enzyme which is able to do the conformational changes if an effector gets attached to it is known as allosteric enzyme. This enzyme responds to the environmental signal which works as an effector.
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What is true about the conformational aspects of coupling?
O The proton gradient is involved in the release of bound ATP from the synthase as a result of conformational change.
O The conformational states interconvert as a result of proton flux through the synthase.
There are two sites for substrate on the synthase and two possible conformational states: open (0) and tight-binding (T).
Dinitrophenol binds to and inhibits ATP synthase conformational changes, thus inhibiting ATP synthesis.
The Fo portion of ATP synthase acts as a rotary motor.
For 100 words. What are the two essential requirements to effectively carry out metabolic work?
not true about the Michaelis-Menten equation?
The equation that gives the rate, v, of an
the substrate concentration [S] is the Michaelis-Menten equation
= Vmax[S]/(Km + [S]), where V,
enzyme-catalyzed reaction for all values of
max and Km are constants. Which of the following is
a)
for [S] << Km, V = Vmax
applies to most enzymes, but allosteric enzymes have different kinetics
when [S] = Km, then v =
Vmax/2
gives the rate when the enzyme concentration, temperature, pH, and ionic
strength are constant
for very high values of [S], v approaches Vmax
e)
Which is correct about the constant Km in the Michaelis-Menten equation?
also called the catalytic constant or turnover number
equal to the number of product molecules produced per unit time when the
enzyme is saturated with substrate
it is the constant in the first order rate equation v = k[A]
it is the constant in the second order rate equation v =
equal to the substrate concentration at which the velocity or rate of a reaction is
½ the…
Chapter 10 Solutions
BIOCHEMISTRY 2 TERM ACCESS
Ch. 10 - Prob. 1PCh. 10 - Prob. 2PCh. 10 - Prob. 3PCh. 10 - Prob. 4PCh. 10 - Prob. 5PCh. 10 - Prob. 6PCh. 10 - Prob. 7PCh. 10 - Prob. 8PCh. 10 - Prob. 9PCh. 10 - Prob. 10P
Ch. 10 - Prob. 11PCh. 10 - Prob. 12PCh. 10 - Prob. 13PCh. 10 - Prob. 14PCh. 10 - Prob. 15PCh. 10 - Prob. 16PCh. 10 - Prob. 17PCh. 10 - Prob. 18PCh. 10 - Prob. 19PCh. 10 - Prob. 20PCh. 10 - Prob. 21PCh. 10 - Prob. 22PCh. 10 - Prob. 23PCh. 10 - Prob. 24PCh. 10 - Prob. 25PCh. 10 - Prob. 26PCh. 10 - Prob. 27PCh. 10 - Prob. 28PCh. 10 - Prob. 29PCh. 10 - Prob. 30PCh. 10 - Prob. 31PCh. 10 - Prob. 32PCh. 10 - Prob. 33PCh. 10 - Prob. 34PCh. 10 - Prob. 35PCh. 10 - Prob. 36PCh. 10 - Prob. 37PCh. 10 - Prob. 38PCh. 10 - Prob. 39PCh. 10 - Prob. 40PCh. 10 - Prob. 41PCh. 10 - Prob. 42PCh. 10 - Prob. 43P
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